Lab 5 NEWTON’S THIRD LAW AND Tension FORCES "Many a small thing has been made large by the right kind of advertising." -Mark Twain "What is the difference between unethical and ethical advertising? Unethical advertising uses falsehoods to deceive the public; ethical advertising uses truth to deceive the public." -Vilhjalmur Stefansson I saw a subliminal advertising executive‚ but only for a second. -Steven Wright • To develop an understanding and consequences of Newton’s Third
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Zn(NO3)2 + 2 H2SO4 ? 2 ZnSO4 + 4 HNO3 4 FeSO4 + 2 H2SO4 ? 2 Fe2(SO4)3 + H2 These two reactions happen simultaneously. 2: 4 HNO3 ? 2 H2O + 3O2 + 2 NO The Nitric Acid decomposes in the intense heat produced by the high concentrate Sulphuric Acid used. 3: 2 Fe2(SO4)3 + 2 H2 + 4 NO ? 4 Fe.NO.SO4 + 2 H2SO4 The Fe.NO.SO4 forms a brown ring in the middle of the solution produced by the reaction‚ making it easy to identify the presence of nitrates in the water. 4. LABORATORY METHOD
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Extended Experimental Investigation Cold Pack Year 12 Chemistry Abstract: Cold packs are based on the principle of endothermic reactions‚ which means a reaction that absorbs heat from the surrounding resulting in a temperature drop. Due to this temperature drop‚ cold packs have many benefits when it comes to injuries such as sprains and strains. It cools the local tissue and reduces bleeding‚ swelling and pain. It also aids in a speedy recovery. The most commonly used
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04.05 Chemical Reactions: Combustion: Lab Worksheet and Rubric Before You Begin: You may either copy and paste this document into a word processing program of your choice or print this page. Procedure: 1. Iron (III) and copper (II) sulfate solution 2. Fill a small test tube halfway with copper (II) sulfate solution. Add a 2.0 gram iron rod to the solution and observe the reaction. 3. 4. 5. Lead (II) nitrate and potassium iodide solutions 6. Pour about 2.0 mL of lead (II) nitrate into the test tube
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March 18‚ 2012 Title: Types of Chemical Reactions Data: Reaction Observations Evidence #1 It turned a reddish brown and the liquid went clear. The color change proved it was a chemical change. #2 The reaction turned yellow and it separated and created a fog. The solid formed precipitation and had a color change during the reaction proving it to be a chemical change. #3 There was green smoke and the crystals turned black. The green liquid turned dark green and continued to sizzle with
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Laboratory #16: Analysis of Grease in Water by Solvent Extraction Experiment Date: 2/19/10 Due Date: 2/26/10 II. Objective The goal of this lab was to determine the amount of impurity‚ in the form of oil‚ in water using the method of solvent extraction‚ also known as liquid-liquid extraction‚ a method of separating two materials with different physical and/or chemical properties. Two methods of evaporation will be used to finally determine the concentration of impurity- one using an explosion-proof
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cathode) reduction. 6O2- - 12e- 3O2 (oxygen gas at the (+) anode) oxidation. Aluminium is more dense than the alumina/cryolite solution and so it falls to the bottom of the cell where it can be tapped off as pure liquid metal. The overall reaction is aluminium oxide aluminium + oxygen. 2Al2O3(l) 4Al(l) + 3O2(g) Oxygen is given off at the positive carbon anode. Carbon dioxide is also given off at the carbon anode because hot oxygen reacts
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This is important for the students to appreciate the knowledge of chemistry that is still new for themselves. Personally‚ I think that this chapter is an interesting chapter as it revealed the way of scientist produces the material around me. It also gives me new knowledge of the uses of chemical substances that I usually found in the laboratories. I hope‚ by learning this chapter‚ I will be more interested in learning chemistry as it will help me in the future. All the equations from this chapter
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Top of Form 1. What is the pH of a buffer that results when 33 g NaHCO3 is mixed with 100.0 mL of 2.50 M NaOH and diluted with water to 250 mL? (Ka for HCO3- = 4.8 10-11) (Points : 10) 8.20 10.07 10.12 10.32 10.56 2. What is the pH of an aqueous solution of 0.30 M HF and 0.15 M F-? (Ka of HF = 7.2 10-4) (Points : 10) 1.83 2.84 3.14 3.44 10.86 3. Which of the following mathematical expressions
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Lectures Lectures of Heat Transfer Heat Transfer Rate Processes Mode Conduction Convection Radiation Transfer Mechanism Diffusion of energy due to random molecular motion Diffusion of energy due to random molecular motion plus bulk motion Energy transfer by electromagnetic waves Rate of heat transfer (W) q = - kA dT dx q = h A(Ts-T∞) q = σ ε A(Ts4-Tsur4) By Mr. Amjed Ahmed Ali Syllabus of Heat Transfer (English)‚ (2 hours/ week‚ Applied 2 hours /week) 1.Heat transfer by conduction
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