out who a suspected mole is in “the Circus” (British Intelligence Headquarters in London). Through the flashbacks‚ stories that nestle within stories‚
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using the mole concept. Limiting Reactant: It is the reactant that will deplete or will be used up first during a chemical reaction. Limiting reactant also determine how long the reaction will last for. Balanced Equation: Mg + 2HCl = MgCl2 + H2 The balanced equation is needed to determine the mole ratio between the two reactants. From the equation we know that the equation mole ratio is 1:2. However‚ we need the actual mole ratio to find out the limiting reactant. The actual mole ratio is
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Equilibrium Constant of an Unknown Ester Hydrolysis Reaction Abstract The experiments to follow determined that the equilibrium concentrations of the reaction: ester + water ↔ alcohol + acid‚ are equal to 0.0363 moles of ester‚ 0.2852 moles of water‚ and 0.0268 moles each of alcohol and acid. Using this information the equilibrium constant was determined to be 0.06938. 1. Introduction In this lab the equilibrium constant‚ Kc‚ for the acid catalyzed reaction between an unknown
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T = R = 1. What pressure is required to contain 0.023 moles of nitrogen gas in a 4.2 L container at a temperature of 20.(C? 2. Oxygen gas is collected at a pressure of 123 kPa in a container which has a volume of 10.0 L. What temperature must be maintained on 0.500 moles of this gas in order to maintain this pressure? Express the temperature in degrees Celsius. 3. How many moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100
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of ZnCI2. As well titrating with NaOH solution. After all the experiment we got hta salt witch we weighted and we got our results. Experiment reactions: .33w of Zn(OH)2 x moles Zn(OH)2/m. moles Zn(OH2) x 1molZnCI2/1 mol Zn(OH)2 x g molZnCI2/1 mol of ZnCL2 = .4531 grams of ZnCI2 .4531g of ZnCl2 x 1 moles ZnCI2/m. moles ZnCI2 x 1molZn/1 mol of ZnCI2 x 65.39 of Zn/1 mol Zn = .2174g Zn Materials needed: Scale Burette Beaker Spatula Erlenmeyer flask Prenolpthen (color indicator) ZnCL2
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Hobson‚ a prominent lawyer. Hobson encouraged Deonarine intellectually and lent him books from which he learned about Cola di Rienzo‚ fourteenth century Italian activist and patriot. In 1927 Deonarine changed his name to Adrian Cola Rienzi‚ naming himself after British magistrate Adrian Clarke and Cola di Rienzo. Krishna was a Labor Leader‚ Barrister‚ Trade Unionist and a Politician. He took account of the widespread misery and he decided to throw his lot with
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Analysis of Soda Ash and Volumetric Analysis of a Carbonate-Bicarbonate Mixture Belardo‚ Pia Jobelle J. Department of Chemical Engineering‚ Faculty of Engineering University of Santo Tomas España‚ Manila February 27‚ 2013 Abstract The analyte used is the soda ash which is titrated with an HCl titrant‚ standardized by Na2CO3. The indicators used are phenolphthalein for basicity and methyl orange for acidity. The two volumes of the titrant are then used to calculate percent composition of
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Questions: 1. One mole of a compound A‚ with vapor pressure 400mmHg at 50oC‚ mixed with 3 moles of compound B‚ with vapor pressure 480mmHg at 50oC to form a homogeneous solution. What is the vapor pressure of mixture at 50oC? XA =moles of A\total No. of moles XA =1\4 XB=3\4 Ptotal=PAoXA+PBoXB =400*1\4 + 480*3\4 = 460mmHg 2. Why should a distilling flask be filled not less than 1\3 filled or more than 2\3 full? This is to allow the liquid being heated room to expand as it turns
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2KI 2K(NO3)+ PbI2 1 mole of Pb(NO3)2 react with 2 moles of KI. Molecular mass of Pb(NO3)2: 207.19 + (14.01+16x3)x2 = 331.21m.m.u. Molecular mass of KI: 39.10+126.90 = 166m.m.u. Number of moles of Pb(NO3)2: 1.01g/331.21m.m.u. = 0.00305 mol (rounded). Number of moles of KI: 0.8g/166m.m.u. = 0.0048 mol (rounded). There is only 0.0048 moles of KI‚ therefore the limiting reagent is KI. Molecular mass of PbI2: 207.19 + 126.90x2 = 460.99m.m.u. Number of moles of PbI2:
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solution in the volumetric flask to finally prepare an acidic KHP solution. The molar mass of KHP was calculated and came to be 208.252 grams per mole. To find the moles of KHP‚ the mass of KHP (1.980 g) was divided by the molar mass of KHP ( 208.252 g) and .00951 moles are in the 1.980 grams of KHP. To find the molarity‚ the number of moles of KHP (.00951 moles) was divided by the volume of water in liters (.100 L) giving an answer of 0.0951 M. The second part of the experiment is the reaction
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