9569 35.3111 Mass of product (grams) 0.4000 0.4300 0.4150 Moles of product corresponding to moles CaC2O4.H2O 2.74 x 10-3 2.94 x 10-3 2.84x10-3 % Ca2+ in the unknown sample 0.4384 = 0.44 0.4704 = 0.47 0.45 Calculations : moles of product = moles CaC2O4.H2O (mw = 146 g/mol) Funnel 1: Funnel 2: % Ca2+ in the unknown sample : (atomic wt. Ca = 40 g/mol) % Ca2+ (w/v) = Funnel 1: % Ca2+ = =0.4384 = 0.44% Funnel 2: % Ca2+ = = 0.4704 =0.47% Problem Solving:
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Gas Chromatography (GC) Definition: Gas chromatography is a physical method of separation in which the components to be separated are distributed between two phases‚ one being a stationary bed of large surface area‚ and the other a gas that percolates through the stationary bed. When the stationary phase is a solid‚ the separation process is more precisely called gas-solid chromatography. Introduction: Gas Chromatography is a technique widely used to separate complex mixtures of substances. Compounds
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report required the successful identification of two unknown substances through experimental testing on a selective collection of materials and equipment. For the first substance (which will be either tin or aluminium)‚ two tests shall be done to ensure a decisive and educated decision onto what the substance is. The first step utilizes the dramatic difference in density between the two substances by measuring the volume and mass of the unknown substance. By calculating the volume (through displacement
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Intelligence: Knowns and Unknowns Ulric Neisser (Chair) Gwyneth Boodoo Thomas J. Bouchard‚ Jr. A. Wade Boykin Nathan Brody Stephen J. Ceci Diane E Halpern John C. Loehlin Robert Perloff Robert J. Sternberg Susana Urbina In the fall of 1994‚ the publication of Herrnstein and Murray ’s book The Bell Curve sparked a new round of debate about the meaning of intelligence test scores and the nature of intelligence. The debate was characterized by strong assertions as well as by strong
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Alkene by dehydration of an alcohol in the presence of a catalyst. Calculate the percentage recovery of products. Test for purity and identification of products. Abstract Cyclohexene and cyclohexanol are both colourless aromatic compounds. The major difference between the two is the presence of the hydroxyl group present in cyclohexanol. This hydroxyl group can be removed by a process known as dehydration which results in the production of cyclohexene at the end of the dehydration process
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This is important for the students to appreciate the knowledge of chemistry that is still new for themselves. Personally‚ I think that this chapter is an interesting chapter as it revealed the way of scientist produces the material around me. It also gives me new knowledge of the uses of chemical substances that I usually found in the laboratories. I hope‚ by learning this chapter‚ I will be more interested in learning chemistry as it will help me in the future. All the equations from this chapter
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CHEM 301 LECTURE Unit 1 0 . COORDINATION CHEMISTRY Factors t hat affect solubility: Common ion: decrease in solubility Complex ion: increase in solubility How does complex ion formation increase solubility? Consider the complex ion formation between silver and ammonia: + Ag + 2NH3 A g(NH3 )2 + Kf = 1 .5 x 10 7 where Kf i s the formation constant (always >1 ‚ formation of the complex is highly favorable) Complex ion formation increases the solubility of sol ids in water
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Purpose: The purpose of this was to determine the concentration of sodium carbonate in an unknown sample by titration. The solution of hydrochloric acid was prepared and standardized using Na2CO3. Observations: Week 1: Standardizing hydrochloric acid using sodium carbonate with bromocresol green indicator Table 1: Titration of sodium carbonate using hydrochloric acid Trial | Mass of Na2CO3 (g) | Burette Reading (mL) | Final Volume of HCl (mL) | | | Initial | Final | | 1
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Chemistry Review (mid-term) 1. Use the equation for atomic mass to answer the following questions. (http://johnheilchem10.escuelacampoalegre.wikispaces.net/file/view/average+atomic+mass+calculations+-+3.pdf) 1. Argon has three naturally occurring isotopes: argon-36‚ argon-38‚ and argon-40. Based on argon’sreported atomic mass‚ which isotope do you think is the most abundant in nature? Explain. 2. Copper is made of two isotopes. Copper-63 is 69.17% abundant and it has a mass of 62.9296 amu.
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Borohydride Reduction of a Ketone Results 1. Draw a three-dimensional structure of the stereoisomer formed in the reaction. Name the compound. meso-Hydrobenzoin 2. Include other results as suggested by your data. * The attached IR and NMR spectroscopy data. * The melting point that ranges from 135.6-137.90C. Spectroscopic Analyses Data tables IR Spectroscopy Hydrobenzoin Peaks (cm-1) | Stretches | Intensity | 3332 (cm-1) | O—H stretch | Strong and broad | 3027
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