will react differently under high temperatures. For example‚ [1] strontium‚ lithium carbonate‚ and strontium carbonate are often used in fireworks to create a red color. Calcium may be used to create orange‚ sodium for yellow‚ aluminum for white‚ barium chloride for green‚ copper for blue‚ strontium and copper for purple‚ and titanium for silver. Even though all elements give off unique colors when heated‚ it is impossible to identify all elements with the naked eye by doing this test because you
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Purpose: To determine the colors of the Atomic Emission Spectra of several metallic ions. Materials: Safety glasses 10 test tubes Test tube rack Paper Pencil 50 mL beaker Bunsen burner Nichrome wire Barium Nitrate Copper Nitrate Strontium Nitrate Lithium Nitrate Potassium Nitrate Sodium Chloride Calcium Nitrate Unknown solutions A‚B‚ & C Hydrochloric Acid Wash bottle (with distilled water) Procedure: 1. Label the test tubes with the names of the solutions and unknowns. 2. Place
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CHEMISTRY EXPERIMENT NUMBER 8 PERCENTAGE OF WATER IN A HYDRATE Objectives 1. To determine the percentage of water in barium chloride dihydrate. 2. To determine the percentage of water in an unknown hydrate salt. 3. To calculate the water of crystallization for the unknown hydrate salt. Discussion A hydrate salt is composed of anions (negative ions) and cations (positive ions) which are surrounded by and weakly bonded water molecules. Each hydrate salt has a fixed number
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law of conservation of matter. His theory was that matter cannot be created or destroyed and that chemical reactions only rearrange the way that atoms are combined; the atoms themselves don’t change. The procedure went like this... 1) Pour 15 ml of Barium Chloride into the bottle. 2) Pour 4 ml of Sodium Sulfate Solution into the test tube. 3) Stand the test tube in the bottle as shown below. 4) Weight the whole apparatus. 5) Record the weight‚ now turn the bottle over slowly to allow the solutions
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equation will be: CuSO45H2O + Ba(NO3)2 →BaSO4+ Cu(NO3)2 We can measure the mass of copper (Ⅱ) sulfate and the mass of the barium nitrate. Thus‚ we can calculate the theoretical yield of barium sulfate. By this‚ it is possible to find out the percent yield of barium sulfate; if we found the experimental yield. The percent yield of barium sulfate= experimental yield of barium sulfate
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seven wells in rows A through E: cobalt (II) nitrate‚ copper (II) nitrate‚ iron (III) nitrate‚ barium nitrate‚ and nickel (II) nitrate. Afterward‚ two drops of each of sodium phosphate‚ sodium iodide‚ sodium sulfate‚ sodium chloride‚ sodium bicarbonate‚ sodium carbonate and sodium hydroxide were added to the five vertical wells under columns 1-7. |cobalt(II)nitrate|copper(II)nitrate|iron(III)nitrate|barium nitrate|nickel(II)nitrate| sodium phosphate|Precipitated a purple color|Precipitated a light
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Tl+ = low solubility (insoluble) silver chloride‚ AgCl‚ forms a white precipitate + any other cation = soluble potassium bromide‚ KBr‚ is soluble Sulfate (SO42-) + Ca2+‚ Sr2+‚ Ba2+‚ Ag2+‚ Pb2+‚ Ra2+‚ Hg2+ = low solubility (insoluble) barium sulfate‚ BaSO4‚ forms a white precipitate + any other cation = soluble copper sulfate‚ CuSO4‚ is soluble sulfide (S2-) + alkali ions (Li+‚ Na+‚ K+‚ Rb+‚ Cs+‚ Fr+)‚ alkali earth metals (Be2+‚ Mg2+‚ Ca2+‚ Sr2+‚ Ba2+‚ Ra2+)‚ and H+(aq)
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conductimetric titration and by gravimetric determination. The conductivity was analyzed during the reaction between the sulfuric acid (H2SO4) and barium hydroxide (Ba(OH)2). Through the conductivity‚ the equivalence point can be determined; from there‚ the concentration of the Ba(OH)2 solution can be found. The final product of the reaction between sulfuric acid and barium hydroxide is insoluble. According to the lab manual‚ during the reaction‚ the total number of dissociated ions in solution is greatly reduced
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to green. Sodium sulphide forms H2S gas with rotten egg smell and also turns lead acetate paper silvery black. c)Sodium sulphide (Na2S)& Sodium sulphate (Na2SO4) using barium chloride(BaCl2) Ans: Sodium sulphate (Na2SO4) forms white ppt. with barium chloride (BaCl2)‚ Sodium sulphide (Na2S) does not form any ppt. with barium chloride(BaCl2) d)Sodium chloride (NaCl)&Sodium nitrate (NaNO3) using conc. Sulphuric acid Ans: Sodium chloride (NaCl) forms HCl gas with conc. Sulphuric acid
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Discussion The data supported the hypothesis that if Daphnia are placed in differently concentrated solutions of barium and calcium chloride‚ then the highest concentration of calcium chloride would affect them the most because of the production of hydrochloric acid and calcium oxide from the mixing of water and calcium chloride‚ two very dangerous acids‚ with the highest concentration having the biggest chemical reaction. Within five minutes of putting the Daphnia into the 10 (ppt) solution of
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