LECTURE 2 CALCULUS INTEGRATION 2.3 INTEGRATION References • • • Barnett‚ Ziegeler and Byleen 2000a‚ Chapters 6 and 7. Chiang and Wainwright‚ Chapter 14. Sydsaeter and Hammond‚ Chapter 9. Antiderivatives and Indefinite Integrals Many operations in mathematics have reverses – compare addition and subtraction‚ multiplication and division‚ and powers and roots. The reverse of differentiation is antidifferentiation. A function F is an antiderivative of a function f if . ‚ ‚ then the functions differ
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© Government of Tamilnadu First Edition-2005 Revised Edition 2007 Author-cum-Chairperson Dr. K. SRINIVASAN Reader in Mathematics Presidency College (Autonomous) Chennai - 600 005. Authors Dr. E. CHANDRASEKARAN Dr. C. SELVARAJ Selection Grade Lecturer in Mathematics Presidency College (Autonomous) Chennai - 600 005 Lecturer in Mathematics L.N. Govt. College‚ Ponneri-601 204 Dr. THOMAS ROSY Senior Lecturer in Mathematics Madras Christian College‚ Chennai - 600 059 Dr
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interest is the history of mathematics‚ and he has written and edited many works on fractals‚ chaos and computing. He is the author of the acclaimed biography of the English mathematician Arthur Cayley and popular maths book How Big is Infinity? Reflection 50 Ideas You Really Need To Know Maths‚ written by Tony Crilly‚ is one of the other books from the “50 Ideas You Really Need To Know” series‚ about Mathematics. It takes us on a journey from the Introduction of Zero to the Riemann’s Hypothesis
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PROPERTIES OF SINE AND COSINE FUNCTIONS: 1. The sine and cosine functions are both periodic with period 2π. 2. The sine function is odd function since it’s graph is symmetric with respect to the origin‚ while the cosine function is an even function since it’s graph is symmetric with respect to y axis. 3. The sine functions: a. Increasing in the intervals[0‚ π/2]and [3π/2‚ 2π]; and b. Decreasing in the interval [π/2‚ 3π/2]‚over a period of 2 π. 4. The cosine function is: a. Increasing in the interval
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Effect of using mathematics teaching aids in teaching mathematics on the achievement of mathematics students NAME: OGUNSHOLA STEPHEN ADESHINA MATRIC NO : 081004105 SUPERVISOR: MR OPARA CHAPTER ONE: INTRODUCTION 1.1 Background to the Study Mathematics is the foundation of science and technology and the functional role of mathematics to science and technology is multifaceted and multifarious that no area of science‚ technology and business enterprise escapes
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Week 9: The Black-Scholes Solution And The “Greeks” (see also Wilmott‚ Chapter 6‚7) Lecture VIII.1 Plain Vanilla The goal of the next two lectures is to obtain the Black-Scholes solutions for European options‚ which belong to the type of basic contingent claims called ‘vanilla options’. These lectures may seem a bit too technical. However‚ I think‚ it is important to have at least some idea about how the BS equation is solved for various financial instruments. I will try my best to keep things
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STRATEGY FOR TESTING SERIES 1. Check for known series. p-series converges if . diverges if . (Note: When ‚ the series is the harmonic series.) geometric series converges if . diverges if . telescoping series converges if a real number. diverges otherwise. 2. Use a test. NOTE: When testing a series for convergence or divergence‚ two components must be shown: (i) State the test that is used: “Therefore‚ the series [converges/diverges] by the [name of test].” (ii)
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Classic Koch Snowflake and a Variation of the Koch Snowflake Jarred Sareault Introduction: In this project‚ we need to find the area and perimeter of both the Classic and Variation Koch Snowflake for the first five levels. Also we need to create and implement general forms for the area and perimeter of the Classic/Variation Snowflakes to find the total area and perimeter of the final snowflake for each. For both the Classic and Variation Koch Snowflake‚ an equilateral triangle is used to start.
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Example 1: Does the curve y = 2x3 – 2 crosses the x-axis between x = 0 and x = 2? Solution: Solving for the given values of x‚ at x = 0‚ then y = 2(0)3 – 2 = -2‚ the curve is below the x-axis at x = 2‚ y = 2(2)3 – 2 = 16 – 2 = 14‚ the curve is above the x-axis‚ So the curve crosses the x-axis between x = 0 and x = 2 since y = 2x3 – 2 has a solution found between this interval. Example 2: From the curve y = x5 - 2x3 – 2‚ is there a solution between x = 1 and x = 2? Solution: Using the given
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Solutions to Graded Problems Math 200 Section 1.6 Homework 2 September 17‚ 2010 20. In the theory of relativity‚ the mass of a particle with speed v is m = f (v) = m0 1 − v 2 /c2 where m0 is the rest mass of the particle and c is the speed of light in a vacuum. Find the inverse function of f and explain its meaning. Solution. We simply solve for v: m= m0 1− v 2 /c2 =⇒ m 1 − v 2 /c2 = m0 =⇒ m2 1 − v2 c2 = m2 0 m2 v2 =⇒ 1 − 2 = 0 c m2 =⇒ v2 m2 =1− 0 c2 m2 m0 m m0 m 2 =⇒
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