Catalase Experiment Research Question: How does the weight of a piece of liver (0.4g‚ 0.8g‚ 1.2g and 1.6g in this case) affect the amount of gas created after 2 minutes when combined with hydrogen peroxide? Aim: To see find out how the amount of catalase correlates with the amount of gas created when in combination with hydrogen peroxide. Materials: 15g of liver 25 ml of hydrogen peroxide 1 scale 1 bucket 1 100ml graduated cylinder 1 250ml flask with bung 1 50cm tube (able to fix onto top of flask)
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of this study was to test the rate of reactivity of the enzyme catalase on hydrogen peroxide while subject to different concentrations of an inhibitor. The hypothesis was that hydrogen peroxide will be broken down by catalase into hydrogen and oxygen‚ where a higher concentration of inhibitor will yield less oxygen‚ resultant of a lower rate of reaction. Crushed potato samples of equal weight were placed in hydrogen peroxide solutions of various temperatures. The results showed that less gas was produced
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Kinetics of Hydrogen Peroxide February 22‚ 2007 Chem. 1130 TA: Ms. Babcock Room 1830 Chemistry Annex PURPOSE OF THE EXPERIMENT Kinetics of Hydrogen Peroxide The major purpose of this experiment is to determine the rate law constant for the reaction of hydrogen peroxide and potassium iodide. In this experiment‚ the goal will be to try to measure the rate law constant at low acidity‚ since at low acidity‚ anything less than 1.0 x 10-3M‚ the effect of the hydrogen ion is negligible. To calculate
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Factors that Affect the Rate of Reaction of the Decomposition of Hydrogen Peroxide Emilio Lanza Introduction- In this experiment‚ the rate of reaction‚ calculated in kPa sec-1‚ of the decomposition of hydrogen peroxide will be investigated to see how the change in concentration of hydrogen peroxide and the change in temperature affect the rate of reaction. The data will be collected by measuring the gas pressure. The product of Hydrogen Peroxide is oxygen in a gas state thus it is mandatory to
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Effects of Different Concentration of Catalyse on Hydrogen Peroxide Aim: In this investigation I will try to find how long it takes for the filter paper disc to rise up whilst varying the amounts of concentration of catalyse. Prediction: I predict that the lower the concentration of catalyse the longer it will take for the filter paper disc to rise to the surface of the tube. Equipment: 1. Hydrogen peroxide in a container 2. Flat bottom tube 3. Tweezers 4. Filter paper
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Abstract The decomposition of hydrogen peroxide (H2O2) in a whole and diced wedges by with The enzyme catalase was observed. The catalase was able to break down the hydrogen peroxide In the diced banana wedge better than the whole banana because after the banana was diced that Increases the surface area allowing the breakdown to flow. The effects of temperature on enzyme In a liver sample were observed under iced‚ boiling‚ 37 degrees‚ and room temperature Conditions. The enzymes became completely
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Reaction of catalase with hydrogen peroxide AIM: I aim to find the rate of reaction between catalase and hydrogen peroxide. Enzymes such as Catalase are protein molecules that are found in living cells. They are used to speed up specific reactions in the cells. Each enzyme just performs one particular reaction so they are all very specific. Catalase enzymes found in living cells e.g. in yeast‚ potato or liver‚ speed up (in our case) the breaking down of hydrogen peroxide. The lock and key analogy…
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an issue throughout the whole experiment. We will wear goggles and an apron or lab coat to protect our eyes and clothes. As we are using enzymes and Hydrogen Peroxide we need to be extra careful‚ ensuring they don’t come into contact with our eyes‚ skin or clothes. Catalyse is an enzyme found in all living cells. It makes Hydrogen Peroxide decompose into water and Oxygen. We will be measuring the amount of Oxygen released from the Hydrogen Peroxide. In order to do this we will use
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Hydrogen peroxide and iodide ions Aim: To determine the rate equation for the reaction between Hydrogen peroxide and iodide ions‚ and to investigate the effects of a catalyst and temperatures on the reaction and to derive the activation enthalpy. Background knowledge: 1Hydrogen peroxide reacts with iodide ions producing iodine‚ when in an aqueous acid solution. H2O2 (aq) + 2I- (aq) + 2H3O+(aq) I2 (aq) + 2H2O(l) To detect iodine you can look at the color shown by the addition of starch
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Introduction: In liver cells‚ hydrogen peroxide is produced as a bi-product of some metabolic reactions. Hydrogen peroxide is a highly active chemical used in household products for bleaches and cleansing wounds. In a cell its build up would be highly toxic. However‚ liver cells contain an enzyme‚ catalase‚ which immediately breaks down hydrogen peroxide. It is a peroxidase and breaks up the toxic hydrogen peroxide to water and oxygen which are both nontoxic. The reaction is exothermic‚ meaning that
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