Momentum and Collisions: Problem Set Problem 1 Determine the momentum of … a. … an electron (m= 9.1 x10-31 kg) moving at 2.18 x 106 m/s (as if it were in a Bohr orbit in the H atom). b. … a 0.45 Caliber bullet (m = 0.162 kg) leaving the muzzle of a gun at 860 m/s. c. … a 110-kg professional fullback running across the line at 9.2 m/s. d. … a 360‚000-kg passenger plane taxiing down a runway at 1.5 m/s Audio Guided Solution Show Answer a. 2.0 x 10-24 kg•m/s b. 140 kg•m/s (rounded
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there will be more particles in a certain area (15cm3) so inevitably there will be more collisions which is backed up by the collision theory. The Collision Theory is based on the idea that for a chemical reaction to take place‚ it is necessary for the reacting particles to collide with each other with enough energy to break or form new bonds between the other particles‚ which is called a successful collision. If when they collide and they do not have enough energy to break or form new bonds then
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reaction rate. C. As the temperature increases‚ the reaction rate increases due to higher number of collisions 3. Yes doubling the concentration did double the reaction rate. Because if you look at the datatable above‚ it took the 6.0M half the time that the 3.0M to dissolve the metal‚ and this happened because with the higher concentration‚ you have more collisions‚ and with more collisions the reaction happens faster. 4. According to my table the flat piece of magnesium dissolved faster
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sure that the collision is under control and that the road is clear for the other drivers. While this is the taxpayers money being put to work‚ there is the traffic jam that can be caused to clear the collision site. People stuck in the traffic jam could be on their way to work or leaving work to pick up their kids. This can cause of lost wages or extra fees at a daycare for late pick-up. Living in Hawaii a small fender bender can back traffic up for hours. So an explosive collision from a Ford Pinot
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of given quantity with time. There are two ways to measure the rate of a reaction: 1. measure the rate at which a reactant is used up 2. measure the rate at which a product is formed Collision theory is used to explain how different factors affect the rate of chemical reaction. The collision theory states that for a reaction to take place between reacting particles (ions‚ molecules or atoms) it is necessary that they collide. Particles must also have a sufficient amount of energy
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* vf). 1.05=2.5 (vf) so the final velocity is 2.38 m/s. This collision would look like: 1.5 kg‚ 0.7 m/s 1 kg‚ 0m/s m1+m2=1.5 kg‚ vf=2.38 m/s Experimental Design The purpose of this lab is to determine the mathematical equation relating the total system momentum of 2 carts before a collision (Pi) to the total system momentum of the 2 carts after the collision (Pf.). Some constants may be: the weight of the bars‚ the carts
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is high concentration of gases. Importance of collisions between reacting particles: When there are more particles moving in faster speeds‚ more collisions will occur during the short period of time. Hence there will be a greater chance of better collision (higher chance to make successful products). The more collision that occur‚ the faster the reaction rate of the overall reaction becomes. Hence increase rate of reaction at which collision occur will defiantly increase the rate of reaction
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.............................5 1.0 Facts Of The Case The incident happened on August 2nd‚ 1926‚ it was just before midnight. The collision were occurred between the French mail steamer named Lotus and Turkish collier named Boz-Kourt. The Lotus was on their way proceedings to Constantinople. The collision happened between five and six nautical miles to the north of Cape Sigri in Mitylene‚ not within territorial waters but on the high seas. The Boz-Kourt was cut into
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consider interactions with other molecules in’ the neighborhood. In Fig. 0.3-1 we show the collision between the two homonuclear diatomic molecules‚ A and B‚ and in Fig. 0.3-2 we show the notation for specifying the locations of the two atoms of one molecule by means of position vectors drawn from an arbitrary origin. Total mass of the molecules entering and leaving the collision must equal. Here mA and mB are the masses of molecules A and B. Since there are no chemical
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Note: I couldn’t paste in pictures and diagrams so please excuse any large spaces. Planing my investigation Method 1.Firstly I will measure 20ml of Copper Sulphate solution (CuSO4) in a measuring cylinder‚ for precise accuracy‚ and then pour the solution into test tube. I will place the test tube into a beaker and insulate the test tube‚ for minimum heat loss. (As shown in the diagram above.) 2.Secondly I will measure the required amount of Zinc (Zn) on a weighing scale‚ again for precise accuracy
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