Through this the appropriate reaction had to be determined out of the two possibilities. Through the use of a vacuum filtration system the mass of Cu was found to be 2.1726g which meant that through limiting reagent analysis Fe was determined to be the limiting reagent and the chemical reaction was determined to be as following:- CuSO4(aq) + Fe(s) Cu(s) + FeSO4(aq) Introduction: There were several purposes of this lab‚ the main ones were limiting reagent analysis‚ quantitative and analytical analysis
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with qualitative data beneath each product and reactant except H20‚ and a summary. The purpose of this experiment is to observe the qualitative aspects of a series of reactions involving copper. Procedure 1.Measure about 1g of solid copper. 2.Place Cu in Erlenmeyer flask and place flask under fume hood. 3.Add dropwise 15M HNO3 until solid copper is completely reacted. 4.Place flask in water bath. 5.Add 4M NaOH slowly until no more solid forms. 6.Mix contents by slowly swirling flask. 7.Place
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E) 2 | Question 3 A ligand is: | A) a molecule or ion that has at least one lone pair of electrons | | B) a nucleophile | | C) a Lewis base | | D) part of a coordination compound | | E) All of the above | Question 4 In K[Cu(CN)2]‚ how many 3d electrons does the copper ion have? | A) 10 | | B) 9 | | C) 8 | | D) 7 | | E) 6 | Question 5 Which of the following is a bidentate ligand? | A) cyanide
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Industria de artificii din China În februarie 1999‚ Jerry Yu şi-a petrecut sărbătoarea Anului Nou Chinezesc în oraşul Liuyang‚ situat în Provincia Hunan în China şi cunoscut ca „ţinutul petardelor şi artificiilor”. Jerry este un chinez născut în America. A absolvit un MBA‚ apoi a condus un mic lanţ de magazine de cadouri în Brooklyn‚ New York. Liuyang este oraşul natal al mamei lui Jerry. În timpul vizitei sale‚ rudele i-au propus să investească într-o fabrică de artificii. Domnul Yu a fost puternic
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FRANARE/ pagina 22 7. SCHEMA DE FORTA/ pagina 25 8. REALIZAREA SCHEMEI DE COMANDA/ pagina 26 9. ANEXE/ pagina 30 PREDAREA PROIETULUI TEMA 1. CERINTE SI DATE PRINCIPALE Sa se realizeze un convertor pentru alimentarea unui sistem de actionare cu motor asincron trifazat care are urmatoarele caracteristici: Puterea nominala PN= 2‚2+0‚5×N= 2‚2+0‚5×9= 6‚7[kW] Tensiunea nominal UN=3×380/220 [V] Frecventa nominala fN=50Hz Turatia nominal nN=1420 rot/min Randamentul nominal ηN=0‚82+0‚001×N= 0
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Hypothesis In this experiment the reaction equation will be: CuSO4?H2O + Ba(NO3)2 →Ba SO4+ Cu(NO3)2 In Lab#6 that we have done in Dec 15 2003; we have found out that the mole for hydrate in copper (II) sulfate is 5. Thus‚ by this experiment I will continue to use the answer that I have found in Lab#6. So by using the knowledge from Lab#6 the reaction equation will be: CuSO45H2O + Ba(NO3)2 →BaSO4+ Cu(NO3)2 We can measure the mass of copper (Ⅱ) sulfate and the mass of the barium nitrate. Thus
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1. Write out and balance each of the following equations. A. CuSO4 + Fe Cu + FeSO4 B. 3CuSO4 + 2Fe 3Cu + Fe(SO4)3 2. If Iron (III) Sulfate were formed‚ what mass of Copper would be expected and what is the limiting reagent? C. 2.26 g Cu D. Fe 3. If Iron (II) Sulfate were formed‚ what mass of Copper would be expected and what is the limiting reagent? E. 2.8 g Cu F. CuSO4 Driving Question: What compound is formed when you add 7 g of CuSO4
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Percent Mass of Copper in a Penny Introduction The purpose of this lab is to determine the percent mass of Cu in a penny and see if the fabricator that makes the planchets for the government is using the correct amounts of Cu in the pennies. The composition of a standard penny is 97.5% Zn and 2.5% Cu. In the lab we will be using Beer’s Law (A=elc+b where A is solution absorbance‚ e is a constant called molar absorbency‚ l is the length in cm‚ and c is the concentration). Using Beer’s Law in this
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Exemple de probleme rezolvate pentru cursul 11 DEEA Amplificatoare de tensiune cu AO Extinderea regiunii liniare de funcţionare prin introducerea unei reacţii negative în circuit Problema 1 Un amplificator operaţional AO este alimentat de la 2 surse de tensiune continuă‚ VCC = 11[V] si VEE = -11[V] si are o amplificare in tensiune AVAO=100000. a. Să se determine intervalul de valori al tensiunii de intrare diferenţiale vID în care AOul funcţionează în regiunea liniară. b. Dacă AOul se introduce
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placed into a solution of its own ions an equilibrium is set up. Cu Zn Zn2+(aq) Zn2+(aq) + 2e Zn(s) Cu2+(aq) Cu2+(aq) + 2e− Cu (s) You will recognise the half equations – the diagrams show the half cells. NB: In this work‚ half equations are always shown with electrons on the left. If these two half cells are connected then the same reaction takes place as when a piece of zinc is put into a copper solution: wire Zn salt bridge Cu Redox – revision When a piece of zinc is placed in a copper
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