Matt Ridley. Matt Ridley says that a gene called CYP17 found on chromosome 10 codes for an enzyme that catalyzes cholesterol to form the hormone called cortisol. The higher levels of cortisol in the blood stream indicates that the
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DISCUSSION: Bromelian added to Gelatin: Bromelian is an enzyme found in pineapples. When Bromelian is added to gelatin it breaks down the protein and does not allow the gelatin to solidify. There are several factors that can cause an enzyme to slow down or to completely stop reacting. For example‚ temperature and pH can effect enzyme activity. Canned pineapple juice and fresh pineapple juice were used to see how the enzyme would react differently. In fresh pineapple juice the Bromelian have would
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CHEMICAL KINETICS 1Y.S. MATBA 1Department of Materials‚ Mining‚ and Metallurgical Engineering‚ College of Engineering Date Performed: December 3‚ 2013 Date Submitted: December 09‚
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Temperature Affecting Enzyme Activity Introduction The basic properties of life revolve around chemical reactions. Without the presence of enzymes some of life’s processes would not come so easily. Enzymes are basically proteins‚ which have specific shapes for different substrates. Enzymes change the rate in chemical reactions. It does this without having to change its own shape‚ which makes enzymes different from other proteins. A common enzyme that we have is catalase‚ which breaks down
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Vaishnavi Kothapalli Mrs. Manning Honors Biology 30 November 2012 TITLE: The Reaction Rate of Catalase in Various Concentrations of Hydrogen Peroxide QUESTION: How long does the catalase take to float to the top of a cup filled with different amounts of hydrogen peroxide concentration? PREDICTION: A prediction that can be made for this experiment is that the higher the concentration‚ the faster time it takes the catalase to react with the solution. As the concentration increases from
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Practical One: Quantitative Kinetic and Kinematic Analysis of Human Movement: The Inverse Solution Tacita Thorogood Student number: 12593352 Subject: SP2011 Advance Biomechanics Lecturer: Sara Brice Group: Even Week‚ Group 1 Introduction Within the field of sports and exercise science the use of digitizing video footage is used to track human movement. Markers are placed on anatomical landmarks of the human body to track movements which the body undergoes‚ this procedure is fundamental
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AIM The aim of this investigation is to explore the effect of different concentrations of bile salts on the time taken for the lipase enzyme to break down fat. BILE Bile is a brownish bitter alkaline fluid produced by the liver and made by the hepatocytes from water‚ bile salts‚ bile pigments cholesterol and phospholipids and stored in the gall bladder. Bile is directly connected with digestion. It is released sporadically into the small intestine (duodenum) which is part of the gut in order
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and Measure of Enzymes Activity Abstract This experiment investigates the effect that temperature has on the rate of activity of enzyme β-galactosidase and also the rate of β-galactosidase activity in different concentration of substrate over time. Ο-nitrophenylgalactoside (ONPG) is used as a substrate for β-galactosidase. A spectrophotometer is used to detect the change in colour of the substrate. Results show that increase in temperature up to 50oC speeds up the rate of enzyme activity and any
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March 17‚ 2013 Name : Ryan annasdass arokiasamy ID : 1206875 Group Members : Chan Pei Qie‚Chong Ven Yen Name : Ryan annasdass arokiasamy ID : 1206875 Group Members : Chan Pei Qie‚Chong Ven Yen experiment 19 kinetics : the study of a chemical reaction experiment 19 kinetics : the study of a chemical reaction Results Part A [I-] / mol dm-3 | [S2O82-] / mol dm-3 | [S2O32-] / mol dm-3 | Time /s | Rate of I2 formation / mol dm-3 s-1 | 0.2 | 0.2 | 0.01 | 1.25 | 0.1600 | 0.2 | 0.15
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(Justification-2 Enzyme Inhibition) By quantitative balance‚ the total amount of Enzyme is [E] 0= [E] + [EI] + [ES] + [ESI]. By using a=1+[I]/KI and a′=1+[I]/K′I‚ it is followed by [E]0=[E]a+[ES]a′ This equation can be written like this‚ [E]0=(Km[ES])/([S]0)a + [ES]a′=[ES]( aKm/[S}0+a’)‚ because of Km=[E][S]/[ES] and [S]≈[S]0. V=kb [ES] =kb [E] 0/ (aKm/[s] 0+a’). Kb [E] 0 is Vmax. This is why V=Vmax/(a^’+aKm/[S]0). This equation can be rearranged like this‚ 1/V= a’/Vmax+(aKm/Vmax)1/[S]0‚ which is
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