Effusion: escape of gas from a container to a region of vacuum Gas Pressure P= Force/area Force: Newton or kg x m/s2 Pressure: Pascal or N/m2 Standard atm pressure P= hdg H: height‚ d: density; g: 9.80665 m/s2 1 atm* = 101‚325 Pa = 760 mmHg* = 760 torr* = 1.01325 bar = 14.7 psi barometer: measure atmospheric pressure Monometer: measure pressures other then atm pressure Gas Laws Boyles law: P at constatnt T is iversely prop to V P1V1=P2V2 EX:Calculate the volume of a sample of gas at 5.75 atm if
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Chemistry June Exam Notes Quantities in Chemical Reactions Molecular and formula mass o The mass of one unit of a compound (a molecule or a formula unit) o The sum of the mass of all the atoms in a compound o With knowledge of the mass of each individual atom‚ the percentage composition by mass can be determined The Mole (mol) o A counting unit‚ one mole refers to 6.02 x 1023 particles of any given substance o Known as Avogadro’s Constant and given the symbol NA Molar Mass o The
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Experiment : 1 Tittle : Preparation of bis(acetylacetonato)copper(II) complex Objective : To synthesis the bis(acetylacetonato)copper(II) complex Introduction : A complex ion is usually form with high charge density metal ion as a central and formation of coordinate covalent bond (dative bond) with high electron molecules or ions. These molecules or ions are functioning as ligands (electrophile in organic compounds). They are easily attracted by electrophile (electron deficiency
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Plant derives their power from gas burning. LNG Power Plant can use gas engine or gas turbine as their power generating unit. Generally gas turbine design for simple & combine cycle with rugged components for base load utility service but also can start & stop easily for peaking application. In the other hand‚ gas engine design for wide variety of application‚ and provide fast and flexible capacity with multiple unit. This comparation of gas engine and gas turbine advantages and disadvantages
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important principles of physics: the ideal gas law and Archimedes’ principle are the reasons hot air balloons fly. The mathematical relationship between the volume pressure and the temperature of a gas is called the ideal gas law. When a gas is heated‚ as in a hot air balloon‚ then its volume will increase. However‚ there is a heater located in the balloon’s basket that heats the air inside the balloon and blows hot air into the balloon. As the volume of gas increases‚ it fills the balloon. As soon
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In other words‚ a mole of a 12 amu carbon atom will weigh 12 grams. The gram formula mass can be used as a conversion factor in stoichiometric calculations through the following equation: Moles = Converting between Volume of a Gas and Moles The Ideal Gas Law is PV = nRT ‚ with nrepresenting the number of moles. n = Mass to Moles Moles to Mass (same!) Atoms to Mass Divide by 6.022x10^23‚ then multiply by atomic mas To convert mass to atoms: Find the atomic mass of
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Chapter 3 The second law Physical Chemistry. Atkins 9th ed. 1 Outcomes • Concepts 1. The second law of thermodynamics: Spontaneous changes‚ Entropy (ΔS)‚ Heat engine (Carnot cycle)‚ Clausius inequality. 2. Entropy changes: ΔS of expansion‚ ΔS of phase transitions‚ ΔS during heating‚ measuring entropy‚ the 3rd law of thermodynamics‚ 3rd law entropies. 3. Criteria for spontaneity: Helmholtz energy (A)‚ Gibbs energy (G)‚ Maximum work (ΔA)‚ maximum non-expansion work (ΔG). 4. Combining
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produced‚ applying Dalton’s Law and the Ideal Gas Equation along with the application of the stoichiometric ratio between the electron and the gases‚ the fundamental electronic charge will be determined. THEORY H+ ions will join together at the cathode (the negative electrode) to produce H Atoms‚ and the H atoms will join to form molecules of H2 gas. At the positive electrode (the anode)‚ H20 molecules will decompose to replace the H+ ions lost and release O2 gas. The reactions appear below
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before ?? = 6??is clockwise. Immediately after A is connected to D‚ the current in R is 10A. (D) Q = 2 × 10−3 C. Answer (C) and (D) A light source‚ which emits two wavelengths ??1 = 400 ???? and ??2 = 600 ????‚ is used in a Young’s double slit experiment. If recorded fringe widths for ??1 and??2 are??1 and??2 © number of fringes for them within a distance yon one side of the central maximum are m1 and m2‚ respectively‚ then 2. (A)??2 > ??1 (B)??1 > ??2 (C) From (D)The the central maximum‚ 3rdmaximum
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embargo was skyrocketing energy prices as a result of limited supply and heavy demand. Rationing went into effect‚ with supplies of petroleum products being carefully doled out with ration cards and flag systems‚ in which people could take turns buying gas and other fuels on the basis of license plate numbers. At the same time‚ the stock market contracted radically‚ an event that foreshadowed future stock market instabilities linked to the price of oil. The 1970s was also an era in which environmentalism
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