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    National Diploma in Mechanical Engineering Section A: COMPULSORY Answer ALL questions 1-12 1. A resistance temperature device has a resistance R0 = 100 Ω at 0o C. If the resistance RT = 197.7 Ω in an oil bath‚ what is the temperature of the oil in the bath‚ given that RT = R0(1+αT)? Take R0 = 100 Ω R0 = resistance at 0o C α = 3.9083 x 10-3 /o C (2 marks) NDE Thermodynamics and Heat Transfer Exam 2008 Name: _______________________________________ Read all the instructions before starting Do

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    Strontium Manganese Oxide Introduction The ternary inter oxide SrMnO3 was first characterized by XRD by Negas and Roth []. This perovskite type inter oxide crystallizes in the hexagonal form with the space group P63/mmC(194). This inter oxide is of considerable interest to materials scientists owing to its ability to accommodate a high degree of anion vacancies‚ crystal structure and its high Neel Temperature (TN). It also exhibits polymorphism with two different cubic and hexagonal structures

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    Biology IB Study Guide 1: Communities and Ecosystems 5.1 Communities and Ecosystems (Core) 5. 1. 1 Define species‚ habitat‚ population‚ community‚ ecosystem‚ and ecology. Species – A species is a group of organisms with similar characteristics‚ which can interbreed and produce viable‚ fertile offspring. Habitat – A habitat is the environment in which a species normally lives or the location of a living organism. Population – A population is a group of organisms of the same species‚ who

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    was 2508 J whereas the heat gained by the calorimeter was 173.4 J. Therefore the number of joules released per mole of water formed was 47.6. Kj/mol. In the heat of neutralization of HC2H3O2-NaOH‚ the heat gained by the solution was 2549.8 J‚ and the heat gained by the calorimeter was 176.3 J. The number of joules released per mole of water formed = 47.4 kJ/mol. The total number of joules released in reaction B (2384.6 J) was more than those released in reaction B (2372.7 J) a difference of 11.9 J

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    Study of Solubility Equilibrium of Potassium Hydrogen Tartrate Wang Haina 1. Aim 1. To determine the solubility of potassium hydrogen tartrate (KHT) at various temperatures from 10°C to 50 °C‚ and determine the corresponding Ksp at these temperatures. 2. To obtain the changes in enthalpy and entropy of the dissolution of KHT from the dependence of Ksp on temperature. 2. Results and discussion 2.1 Collection of data A portion of KHT (1 to 1.5 g) was added into about 100 mL of deionised

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    Diploma Programme Chemistry data booklet First examinations 2009 Diploma Programme Chemistry data booklet First published March 2007 Revised edition published September 2008 International Baccalaureate Peterson House‚ Malthouse Avenue‚ Cardiff Gate Cardiff‚ Wales GB CF23 8GL United Kingdom Phone: +44 29 2054 7777 Fax: +44 29 2054 7778 Website: http://www.ibo.org © International Baccalaureate Organization 2008 The International Baccalaureate (IB) offers three high quality and

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    University of Nebraska at Omaha Bomb Calorimetry Physical Chemistry 3354 Enthalpy of Combustion: 1‚2-diphenylethane January 6‚ 2014 Author: Jon D. Paul Signature Professor: Dr. Edmund Tisko Date Abstract Experimentation involving constant volume calorimetry produces the heat of reaction for many substances. When choosing adiabatic conditions we are allowed to focus on the reaction system while neglecting everything else. The reactions that are studied should proceed relatively

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    spend the rest of my life with my best friend is the best feeling EVER! Even after being married for years‚ my love still grows every day! I know I am with my soul mate and still can’t believe we have made it and have overcome so much in our life njkj kj kj Knowing that I would get to spend the rest of my life with my best friend is the best feeling EVER! Even after being married for years‚ my love still grows every day! I know I am with my soul mate and still can’t believe we have made it and have overcome

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    and Ethanol can be represented through: Methanol: 2CH3OH(l) + 3O2(g) 2CO2(g) + 4H2O(l) 2(358+463+(414x3)) + (498x3) (804x2x2) + (463x2x4) 5620 6920 6920-5620= 1300 1300/2= -650 KJ/mole Ethanol: CH3CH2OH(l) + 3O2(g) 3H2O(l) + 2CO2(g) 346+358+463+ (414x5) + (498x3) (804x2x2) + (463x2x3) 4731 5994 5994-4731= -1263 KJ/mole Note: Combustion values are not exact to the book due to different values of bond energies. Risk Assessment Methanol: Inhalation and ingestion may be fatal. Inhalation also

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