b) Write the anode and cathode half-reactions‚ and the net cell reaction for the above diagram. [ T/I / 2 ] Oxidation: Zn (s) Zn2+ (aq) + 2e- Reduction: Cu2+ (aq) +2e- Cu(s) Zn (s) + Cu2+ (aq) +2e- Zn2+ (aq) + 2e- + Cu(s) Zn (s) + Cu2+ (aq) Zn2+ (aq) + Cu(s) c) Write the cell notation for the above galvanic cell drawn. [ T/I / 1 ] Cu(s) | Cu2+(aq) || Zn 2+(aq) | Zn (s) d) Calculate the percent error of the cell potential for the above galvanic cell. Show all
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The purpose of this experiment was to determine the speed at which a reaction took place between an iodine and hydrogen peroxide solution. In addition to a change in concentration‚ a change in temperature and a catalyst variable was also introduced to conclude whether or not their presence affected the overall speed of the reaction. In order to determine the effects of these variables‚ several iodine and hydrogen peroxide reactions were prepared‚ (all at varying temperatures‚ volumes‚ and concentrations)
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Experiment 11 Title: Spectrophotometric analysis of caffeine and benzoic acid in soft drink. Name: Tan Herh Lim Name of partner: Sia Ting Wai‚ Chong Zheng Yee Date: Lecturer: Dr. Neo Kian Eang Practical class: P1 Objective: To obtain the absorbance of the caffeine and benzoic acid in soft drinks. Introduction Soft drinks that commonly found in our daily life contain caffeine and sodium benzoate. The caffeine act as a stimulant and the sodium benzoate acts as a preservative
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this reaction at 25(C. A. 1020 kJ/mol B. -1.22 ( 103 kJ/mol C. 2.00 ( 103 kJ/mol D. -1.42 ( 103 kJ/mol E. -198 kJ/mol 2. For the reaction H2(g) + S(s) ( H2S(g)‚ (H( = -20.2 kJ/mol and (S( = +43.1 J/K·mol. Which of these statements is true? A. The reaction is only spontaneous at low temperatures. B. The reaction is spontaneous at all temperatures. C. (G( becomes less favorable as temperature increases. D. The reaction is spontaneous
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From the results recorded it was identified that activity A and C had exothermic reactions‚ whilst activity B had an endothermic reaction. Each of the activities had initially begun with 23.4/8/9oC‚ however‚ within one minute of adding the 2nd reactants‚ the results began showing‚ as seen from the graph. Activity A and C had risen in temperature‚ with A gaining 4oC and in total of 2 minutes having the temperature of 27.9oC along with C increasing by 2.2oC and within 2 minutes of the experiment having
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Acid-Base Strengths of Organic Compounds By: Chris Frankmore Due Date: February 15‚ 2011 Resonance Benzenesulfonic Acid Benzoic Acid Benzyl Alcohol Benzylamine P-Cresol P-Toluidine Acid/Base | Structure | pH | Why It is a strong/weak acid/base | Benzenesulfonic Acid | | 1 | This is a strong acid because it has a pH of 1. Another reason why this is a strong acid is that its conjugate base has strong resonance stabilization
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the rate constants‚ k1‚ for the methyl acetate hydrolysis reaction at 25 °C and 35 °C‚ as well as the overall activation energy of the reaction. Methods Methyl acetate was placed in an HCl solution‚ in which it reacts with water to form acetic acid over time. At each time interval‚ an aliquot of the mixture was removed for titration against NaOH to determine the concentration of the acetic acid produced. From the amount of acetic acid produced overtime‚ the rate constant‚ k1‚ can be determined
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Title: Surface Area vs. Rate of Reaction Research question: How can different temperatures affect the rate of reaction‚ when the reactant is in powder form? Hypothesis: If the temperature of the water is increased‚ the rate of reaction will also increase as the heat given off to the particles will increase leading to more movement and frequent collisions. Background information: Chemical reactions occur when two or more molecules interact with each other‚ but that can only occur when they
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Abandoned Acid Mine Drainage at Shoup’s Run Introduction Acid mine drainage (AMD) is an industrial waste which is the result of the extraction process of the mineral coal from the ground. It causes widespread pollution in the streams above and below the coals fields. AMD is caused when water flows through sulfur-bearing materials forming acidic solutions. It is formed when pyrite (FeS2)‚ an iron sulfide‚ is exposed and then reacts with air (O2) and water (H2O) to form sulfuric acid. 2FeS2 (s)
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Step 1: Pb (NO3) 2 (aq) + CaCl2 (aq) PbCl2 (aq) + Ca (NO3) 2 (aq) (double displacement reaction) According to the solubility guidelines lead (II) chloride (PbCl2) is a possible precipitate. This is because even though most chlorides are soluble‚ lead chloride is considered insoluble (p.2‚ Lesson 17). Step 2: PbCl2 ↔ Pb2+ + 2Cl- Q = [Pb2+] [Cl-] 2 Step 3: Ksp = 1.2 x 10-5 (from table 17.1‚ p.5) Step 4: V2 = 20.0 mL (volume of Pb (NO3)2) + 45.0 mL (volume of CaCl2) = 65.0
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