Introduction: This experiment will investigate the factors that affect the rate of reaction of the enzyme catalyse‚ an enzyme found in food such as potato and liver. Catalyse is used to remove hydrogen peroxide from cells. The enzyme speeds up the rate of decomposition of hydrogen peroxide into water and oxygen. The reaction is: Catalyse is able to speed up the process because the enzyme lowers the activation energy of the reaction. This means that the free energy required for the reaction
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reaction of ethanoic acid and sodium hydrogen carbonate Cristina Li 17th April 2017 Introduction The hypothesis is the balloon will be bigger and bigger with the increase of vinegar. The chemical reaction between the baking soda and vinegar produces bubbles of carbon dioxide gas as part of this acid-base reaction. Sodium hydrogen carbonate (baking soda) reacts with
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of the Decomposition of Hydrogen Peroxide Emilio Lanza Introduction- In this experiment‚ the rate of reaction‚ calculated in kPa sec-1‚ of the decomposition of hydrogen peroxide will be investigated to see how the change in concentration of hydrogen peroxide and the change in temperature affect the rate of reaction. The data will be collected by measuring the gas pressure. The product of Hydrogen Peroxide is oxygen in a gas state thus it is mandatory to use the gas pressure sensor. By calculating
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Objective: To investigates the enzymatic effect of various materials in the hydrogen peroxide solution. Apparatus & Equipment: Beaker Test tubes Either: water bath (95oC) or Bunsen burner Materials: Fresh Liver Potato cubes Manganese dioxide Hydrogen peroxide** Wood splints **Caution: Hydrogen peroxide is formed continuously as a by-product of chemical reactions in living cells; it is a very toxic (poisonous) substance. [Note: using boiling tubes may provide
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64. Interpret the following results: A. The color of the medium remains purple or light blue-gray; there is also no change in the texture of the medium. * No change B. Change in the color of litmus from purple to pink or pink-red throughout the tube. Upon further incubation a white ring of litmus forms at the bottom of the tube at the pink-red color is now present only at the top of the tube. Still further incubation leads to the formation of a rennet curd at the bottom of the
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Assessment of Catalase Function Lab Introduction The purpose of this lab report was to test and measure the rate of substrate destruction by an enzyme‚ we tested the destruction of hydrogen peroxide by the enzyme catalase. Hydrogen peroxide is a poisonous by product of metabolism that can damage cells if it is not removed. Catalase is an enzyme that speeds up the breakdown of hydrogen peroxide into water and oxygen gas. H2O2 + catalase → H2O + O2 A catalyst is a substance that lowers the
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In this experiment the substrate is going to be hydrogen peroxide(H2O2) and the enzyme is going to be catalase. Hydrogen peroxide(H2O2) is a product of aerobic cellular respiration and is considered a free radical. This means that too much of hydrogen peroxide can affect the organelles. In order to stop damages caused by hydrogen peroxide‚ the enzyme catalase changes hydrogen peroxide(H2O2) to water(H2O) and oxygen gas(O2). Catalase is present most animal cells. The reaction is ………………
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This will be done by reacting the zinc with hydrochloric acid to form zinc ions in a single replacement reaction. The acid reacts with the zinc but not copper. The reaction of zinc metal with the hydrochloric acid (HCl) produces zinc chloride and hydrogen gas. Safety: Wear your safety goggles and apron If you spill Hydrochloric acid on yourself‚ rinse with water Procedure: DAY I 1. Take a post-1983 penny and‚ using a triangular file‚ etch an “X” on one side of the penny. Also etch a notch on the edge
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1. On analysis‚ a compound with molar mass 60 g mol–1 was found to contain 12 g of carbon‚ 2 g of hydrogen‚ and 16 g of oxygen. What is the molecular formula of the compound? A. CH2O B. CH4O C. C2H4O D. C2H4O2 2. What is the total number of atoms in 0.20 mol of propanone‚ CH3COCH3? a. 1.2×1022 b. 6.0×102 C. 1.2×1024 D. 6.0×1024 Assuming complete reaction‚ what volume of 0.200 mol dm–3 potassium hydroxide solution (KOH(aq))‚ is required to neutralize 25.0 cm3 of 0.200 mol dm–3 aqueous
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Why Use GIS in Petroleum? A free eBook from Exprodat Version 1.0 (May 2012) | download latest version | | | .. .... 000000 000000 exprodat www.exprodat.corn Why Use GIS in Petroleum? Table of Contents Section 1: Introduction to GIS 5 Welcome 5 What is GIS? 5 What Can GIS Do? 7 Why You Should Care 9 Benefits of GIS 9 GIS in Petroleum 10 When Bad Stuff Happens 11 GIS Vocabulary 12 Section 2: GIS in the Petroleum Industry 14 A Brief History 14 GIS and
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