Experiment 4 Inelastic Collisions‚ Conservation of Momentum and Non Conservation of Kinetic Energy Preparation Prepare for this week’s experiment by studying Newton’s Laws‚ linear momentum‚ and kinetic energy. Principles In this experiment you will study a collision where a moving object strikes and sticks to an initially motionless object. When the colliding objects stick together the collision is said to be completely inelastic. The net momentum of the system should not change‚ but the
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Joppa for his temple (2 Ch. 2:16) and Ezra later brought supplies through Joppa for the rebuilding of the foundation of the temple (Ezra 3:7). Jonah never makes it from Joppa to Tarshish‚ but it is also a popular port city in the Ancient Near East (1 Ki. 10:22‚ 22:48). Several biblical accounts write of the gold and silver of Tarshish‚ indicating the wealth
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a brand-new Mac Plus to help out with his studying‚ he found out it could not display grayscale images on the monochrome monitor. Without waiting a moment he started writing his own code to do the job. John‚ was also working on image processing at ILM and during a
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Prominent UN system agencies are? the World Health Organization (WHO)‚ the World Food Programme (WFP) and United Nations Children’s Fund (UNICEF) * UN’s Most Prominent Position Is? Secretary General Who Has Been Held Of? Ban Ki-Moon Of South Korea Since 2007 * Ban Ki-Moon Is Declarated As Secretary General On ? 1st of January 2007 * The United Nations Headquarters resides in international territory is where? Further main offices? New York City. Geneva‚ Nairobi‚ and Vienna. * Six Official
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Marketing Initiatives[edit] Khushiyon Ki Doli The company launched a multi-brand rural marketing initiative called Khushiyon Ki Doli‚[73] in 2010 in three states – Uttar Pradesh‚ Andhra Pradesh and Maharashtra. Through this initiative more than 10 million consumers were contacted directly in more than 28‚000 villages across these three states. Through this initiative‚ the company also reached out to 170‚000 retailers in these villages.Through this initiative HUL engaged with 25 million rural
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Question Chemicals Reaction A NaHCO3 and HCI - C02 A bubble occurrence B HCI and BTB A deep yellow C NH3 and BTB A purple color D HCI and blue dye A deep blue E Blue dye and NaOCI A greenish color F NaOCI and KI A bright red G KI and Pb(NO3)2 A yellow H NaOH and phenolphthalein A light yellow I HCI and phenolphthalein A red color J NaOH and AgNO3 A black color K AgNO3 and NH3 No change L NH3 and CuSO4 A light whitish blue Observations:
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concentration levels. For this experiment we will also be using a catalyst to speed up the production of oxygen gas. The catalyst being used will be iodide ions‚ which will be introduced into the actual reaction through a mixture of potassium iodide‚ KI. Once all the reactions are complete the rate will be found by using the rate law‚ which shows the dependence of the rate of the reaction of both the iodine and the hydrogen peroxide. Procedure For this experiment we had to work in pairs.
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option. Te Reo Māori is one of the two official languages in New Zealand it’s also part of the school’s obligation to Te Tiriti o Waitangi. In Article two of Te Tiriti o Waitangi it states. “Ko te Kuini o Ingarani ka wakarite ka wakaae ki nga Rangatira ki nga hapū – ki nga tangata katoa o Nu Tirani te tino rangatiratanga o o ratou wenua o ratou kainga me o ratou taonga katoa.” (Busby‚ Wiremu 1840). The people and leaders of New Zealand have chieftainship of all lands‚ estate and treasures they own;
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| E1 | Blue dye and NaOCl | Solution remained Blue. When HCl is introduced‚ solution turned blue green | Blue-green solution | Blue-green solution | F1 | NaOCl and KI | Solution changed from clear to Green‚ with the addition of Starch‚ the solution turned Black | Black solution | Black solution | G1 | KI and PB(NO3)2 | Yellow precipitate formed | Yellow solution | Yellow solution | H1 | NaOH and Phenolphthalein | Solution changed from clear to Purple-red | Purple-red
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Making up Hydrogen Peroxide Volume required 250 cm3 and concentration required 0.1 moldm-3 Given concentration of H2O2 = 1.7 moldm¬-3 Number of moles (n¬¬¬¬¬¬¬¬¬¬¬) = Concentration (moldm-3) x Volume (dm-3) = 0.1 x 0.25 = 0.025 mol Volume (dm-3) = Number of Moles (n) X 1000 Concentration (moldm-3) = (0.025/1.7) x 1000 = 14.7 cm3 Distilled water required: 250 cm3 – 14.7
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