This experiment was a Landolt Iodine clock reaction - Oxidation of Bisulphite by Iodate. It involved conducting three measured experiments. The first variable tested was concencentration. This was tested by conducting two experiments‚ each varying the concentration of either the NaHSO3 or KIO3. The varying of NaHSO3 involved using 0.1 Molar of KIO3 against decreasing concentrations of NaHSO3 (0.25 M‚ 0.125 M‚ 0.0625 M and 0.03125 M). When decreasing the concentration of KIO3‚ 0.25 M of NaHSO3 was
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rate law constant for the reaction of hydrogen peroxide and potassium iodide. In this experiment‚ the goal will be to try to measure the rate law constant at low acidity‚ since at low acidity‚ anything less than 1.0 x 10-3M‚ the effect of the hydrogen ion is negligible. To calculate the rate‚ the experiment will have to utilize the rate equation‚ which is expressed as Rate = k[H2O2]a[I-]b. At low acidity‚ the rate of the Hydrogen ion will not change‚ from our equation: H2O2 (aq) + 2I- (aq) + 2H+ (aq)
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created and how the rate will change when we use different initial concentrations. We do use a catalyst in this reaction to speed up the process and lower the activation energy needed to run the reaction. The catalyst is the Iodide ion that will be used in the form of potassium iodide (KI). Results at the end of the trails will be used to compose a rate of law for the reactions. This law will show the “dependence of the rate on the concentration of both H202 and I-. The rate of reaction equation is as
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Analytical Chemistry Daniel C. Harris: 7-4‚ 8‚10‚12‚16 7-4) A 1.000g sample of unknown analyzed by Reaction 7-2 gave 2.500g of bis(dimethylglyoximate) nickel(II). Find the wt% of Ni in the unknown. 7-8) The man in the vat. Once upon a time‚ a workman at a dye factory fell into a vat containing a hot concentrated mixture of sulfuric and nitric acids‚ and he dissolved! Because nobody witnessed the accident‚ it was necessary to prove that he fell in so that the man’s wife could collect his insurance
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Reagent - 1.5 mL in Vial 2 Pipet‚ Empty Short Stem 1 Silver Nitrate‚ 0.1 N - 6 mL in White Dropper Bottle 1 Sodium Bromide‚ 0.1 M - 2.5 mL in Pipet 1 Sodium Carbonate‚ 0.25 M - 2.5 mL in Pipet 1 Sodium Chloride‚ 0.1 M - 2.5 mL in Pipet 1 Sodium Iodide‚ 0.1 M - 2.5 mL in Pipet 1 Sodium Phosphate‚ 0.1 M - 2.5 mL in Pipet 1 Sodium Sulfate‚ 0.1 M - 2.5 mL in Pipet 1 Sodium Sulfide‚ 0.1 M - 2.5 mL in Pipet 1 Unknown - 5 mL in Pipet 1 Lead Acetate Strips - 2 in Bag 2"x 3" – Assembly Procedure 1. Before
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90696 906960 For Supervisor’s use only 3 Level 3 Chemistry‚ 2008 90696 Describe oxidation-reduction processes Credits: Three 9.30 am Friday 28 November 2008 Check that the National Student Number (NSN) on your admission slip is the same as the number at the top of this page. You should answer ALL the questions in this booklet. A periodic table is provided on the Resource Sheet L3–CHEMR. If you need more space for any answer‚ use the page(s) provided at the back of this booklet and clearly
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molecular formula iv.both have the same physical properties a.i‚iv b.ii‚iii c.i‚ii‚iii d.ii‚iii‚iv paper 2 1.in an experiment‚bromine water is added drop by drop into the potassium iodide solution in a test tube until bromine water is in excess.the test tube is shaken. a.i.state the colour of the potassium iodide solution(1m) ii.what solution colour is produced after it is mixed and shaken with bromine water?(1m) b.a small amount of tetrachloromethane liquid is added to the product in the
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Chapter 2 22. A student heats 0.5585 g of iron with 0.3550 g of sulfur. She reports that she obtains 0.8792 g of iron sulfide and recovers 0.0433 g of unreacted sulfur. Show by calculation whether or not her results obey the law of conservation of mass. Total mass initial = 0.5585 g + 0.3550 g = 0.9135 g Total mass final = 0.8792 g + 0.0433 g = 0.9225 g These two values should be equal by the law of conservation of mass. These results do not obey the law of conservation of mass. Possibly she
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SALTS AND THEIR PREPARATION SALTS A salt is a compound formed when the hydrogen ions in an acid are replaced by metal ions or by ammonium ions. Compounds in which the H+ ions in an acid have been replaced by ammonium ions (NH4+) are called ammonium salts. NOTE: •An anion is a negatively charged ion. Hence:•Hydrochloric acid gives chlorides. E.g. sodium chloride‚ ammonium chloride. •Nitric acid gives nitrates. E.g. barium nitrate‚ copper nitrate. •Sulphuric acid gives sulphates. E.g. silver sulphate
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away/donate/release its (outermost) electron more | | | | | |easily/readily. | |1 | | | |or‚ Rb can form ion/cation/positive ion more easily/readily. | |(1) | | | |or‚ The strength of metallic bond between Rb atoms is weaker than that between K atoms/Rb can atomize more | | | |
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