Test for Carbohydrates Result Starch suspension When the yellowish-brown iodine was added into the starch suspension‚ the starch suspension was changed into dark blue. Potato slide Discussion Starch suspension When the yellowish-brown iodine was added into the starch suspension‚ the starch suspension was changed into dark blue. This is due to the yellowish-brown iodine changed into dark blue when there is a presence of starch. This shows a positive test for
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of substrate can fit to the enzyme’s active site. The action of enzymes is reversible and enzymes can be reused. This means that an enzyme can catalyze lots of substrates. Materials Starch solution‚ sodium chloride solution‚ amylase solution‚ iodine solution Apparatus Test tubes‚ droppers‚ white tile‚ stopwatch‚ water bath controller Procedure 1. A water bath is set up at 30°C. 2. 3cm3 starch solution added into a test tube labeled A. 1cm3 of sodium solution is added into the test tube
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curcas seed fats and oil‚ and (2) Identification and characterization of unknown oil. After the fats and oil was extracted from seeds of Jathropa curcas‚ the percent yield was reported as 40-41%. The specific gravity‚ refractive index‚ acid value‚ iodine value‚ peroxide value‚ and the saponification value of the unknown oil sample were determined. The computed values were 1.05‚ 1.5765 ± 5.7735 x 10-5‚ 0.328 ± 2.31 x 10-3 mg acid / g oil‚ 10. g I2 / 100 g oil‚ 22 ± 2 ml / g oil‚ and 208 ± 8.49 mg
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gram-positive. The gram staining procedure consists of fixing a colony of bacteria onto a slide and then flooding the colony with various chemicals. First‚ crystal violet dye was dropped onto the bacterial cells‚ staining gram-positive cells purple. Iodine was added to fix the violet dye into place and then ethanol was used to wash the dye off the unstained cells. Finally‚ a red dye called safranin was used to stain any gram-negative cells present so that they were visible. Once the gram stain procedure
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Manual. Vol. 2013-2014. Plymouth: Hayden-McNeil. 32-35. Data/Results: Part A: In the potassium iodide solution‚ I think there were potassium atoms as well as iodine atoms. In the lead nitrate solution‚ I think there were lead and nitrate ions. The potassium atoms and the lead atoms can be classified as cations‚ since they are metals. The iodine atoms and the nitrate ion can be classified as anions since they are nonmetals. Upon mixing‚ the solution turned into a cloudy yellow color. Evidence that a
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determined by analyzing the amount of iodine (I2) formed. Two chemical reactions are useful to determining the amount of iodine is produced. I2(aq) + 2S2O32-(aq) 2I-(aq)+S4O62-(aq) (3) I2(aq) + starch I2 *starch(blue complex) (4) Reaction (4) is an iodine-starch reaction‚ used solely to determine when the production of iodine is occurring by turning a clear colorless solution to a blue color. Without reaction (4) it would be very difficult to determine how much iodine is being produced‚ due to how
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The Effects on Enzymes By Bailey Rose The Effects on Enzymes Bailey Rose 10/31/2011 Abstract In this lab exercise‚ the study of enzyme catalase‚ we viewed the breakdown of hydrogen peroxide into water and oxygen. The purpose was to isolate catalase from starch and measure the rate of activity under different conditions. Changes in temperature and pH along with Substrate Concentration and Enzyme Concentration were the conditions tested in the experiment. Our class performed
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chemical reaction but does not become part of the end product. Amylase digests starch by catalyzing hydrolysis‚ which is splitting by the addition of a water molecule. The presence and absence of starch can be confirmed by several tests such as the iodine test‚ Benedict’s and Fehling’s test. In general‚ a blue-black color indicates the presence of starch. The objectives of this experiment are to examine the enzymatic activity and specificity of salivary amylase depending on changes temperature and
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chloroplasts‚ where the photosynthesis occurs. During experiment‚ two leaves were tested for the presence and localization of starch. One leaf was a light-grown plant with mask‚ and the other was a dark-grown plant with mask. Both leaves were soaked in iodine solution and then rinsed in order to observe the pattern of staining. According to the result‚ the light-grown leaf’s masked areas had no blue-black coloration and the unmasked area turned blue-black in color. The blue-black coloration of the leaf
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Part I: Reaction between zinc and iodine Watch the Video. http://www.youtube.com/watch?v=xT9V7Y1iKYc Observations: Describe what happened when the water was added. A reaction happened and the iodine exploded into a purple gas Questions and conclusions: 1. Balance the equation‚ if necessary‚ for the reaction between zinc and iodine. Zn + I2 ZnI2 It is balanced 2. Classify the reaction that occurred between the zinc and iodine. redox 3. What evidence was there
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