<i>1. State the five assumptions of the Kinetic-Molecular Theory of gases.</i><br><br>a) Gases consist of large numbers of tiny particles. These particles‚ usually molecules or atoms‚ typically occupy a volume about 1000 times larger than occupied by the same number of particles in the liquid or solid state. Thus molecules of gases are much further apart than those of liquids or solids.<br><br>Most of the volume occupied by a gas is empty space. This accounts for the lower density of gases compared
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Kinetic Molecular Theory Basic Concepts The gas laws developed by Boyle‚ Charles‚ and Gay-Lussac are based upon empirical observations and describe the behavior of a gas in macroscopic terms‚ that is‚ in terms of properties that a person can directly observe and experience. An alternative approach to understanding the behavior of a gas is to begin with the atomic theory‚ which states that all substances are composed of a large number of very small particles (molecules or atoms). In principle‚ the
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Part B Now‚ suppose that Zak’s younger cousin‚ Greta‚ sees him sliding and takes off her shoes so that she can slide as well (assume her socks have the same coefficient of kinetic friction as Zak’s). Instead of getting a running start‚ she asks Zak to give her a push. So‚ Zak pushes her with a force of 125 \rm N over a distance of 1.00 \rm m. If her mass is 20.0 \rm kg‚ what distance d_2 does she slide after Zak’s push ends? Remember that the frictional force acts on Greta during Zak’s push and
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depression‚ personal discomfort‚ unpleasant emotions‚ anger‚ and resentment during this assessment. I noticed these symptoms during certain pictures (3BM‚ 4‚ 8BM‚ 12M‚ 13MF‚ and 16). The symptoms were documented for further evaluation. Kinetic House-Tree-Person The Kinetic House-Tree-Person (K-H-T-P) is a projective test in which the individual is asked to unconsciously draw a good picture of a house‚ tree‚ and person on three separate sheets of paper. The client can take as much time as
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Kinetic theory of gases Question: How does odor travel from one place to another? Kinetic theory of gases A gas is composed of atoms or molecules The gas particles are in constant random motion Kinetic energy is transferred between particles as they collide Pressure The force exerted per unit of area Formula: pressure/force area Measured by barometer A vacuum is empty space‚ with no particles or pressure. Atmospheric pressure is the collision air particles with objects Units of
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1 UNIT 9 CHEMICAL KINETICS 1. (c) mole 1–1 sec–1 The rate law for a reaction A + B →products‚ is rate = k [A]1[B]2. 7. Then‚ which one of the following statements is false ? (a) If [B] is held constant while [A] is doubled‚ the reaction will proceed twice as fast. (b) If [A] is held constant while [B] is reduced to one quarter‚ the rate will be halved (c) If [A] and [B] are both doubled‚ the reaction will proceed 8 times as fast. 2. Fro a first order reaction‚ a straight
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Kinetics of an SN1 reaction: the effect of solvent on rate Object The purpose of this experiment is to determine the rate of hydrolysis in acetone/water (50/50 v/v and 60/40 v/v). Background and Theory An SN1 reaction of tert-butyl chloride takes place in two steps. First‚ the Alkyl Halide will leave the molecule. In this step the bond is breaking‚ which takes a longer amount of time‚ so it will determine the rate of the reaction. As a result‚ it forms a tertiary carbocation‚ since this
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uniform disk of radius R = 0.25 m has a string wrapped around it‚ and a m = 3 kg weight is hanging on the string. The system of the weight and disk is released from rest. a) When the 3 kg weight is moving with a speed of 2.2 m/s‚ what is the kinetic energy of the entire system? KETOT = KEwheel+KEweight = (1/2)(I)(w2)+(1/2)(m*v2) =(0.5* v2)(m+1/2M) =0.5*(2.2^2)*(3+(.5*15)) J b) If the system started from rest‚ how far has the weight fallen?
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puck of mass m initially at speed u collides head-on (without rotation) with a stationary puck of mass M. Find the velocities of both puck after the collision if: i) the collision is fully elastic ii) the collision if fully inelastic. i) momentum: kinetic energy: mu = mv+MV (+ve in direction of initial u) 1 /2 m u2 = 1/2 m v2 + 1/2 M V2 2 eqns in 2 unknowns: V = (u - v) m/M substitute in K eqn: u2 = v2 + (M/m) V2 = v2 + (M/m) (u - v)2 (m/M)2 = v2 + (u - v)2 (m/M) let ρ = (m/M) ⇒ v2 (1 + ρ) - 2ρ
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In this essay‚ it will be discussed how the Kinetic Molecular Theory explains many gas law specifically Boyle’s gas law‚ Charles’ gas law‚ and Avogadro’s gas law. To understand what will be talked about is to first know what the Kinetic Molecular Theory is. In our textbook is says it is “A simple model for gases that predicts the behavior of most gases under many conditions.” First off‚ we will take a look at Boyle’s Law. As stated in our lab manual “at constant temperature the pressure which a given
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