colligative properties and to use them to determine the molar mass of a substance. Materials and chemicals: 800mL beaker balance weighing paper Thermometer 400mL beaker wire stirrer ring stand unknown solid 15x150mm test tube clamp watch acetone Ice cyclohexane sodium chloride Lab Safety: Wear protective googles‚ apron‚ and gloves. Procedures: Prepare ice/salt/water bath Place 50g of solid NaCl in a 400mL beaker and add just enough water to dissolve the salt. Fill an 800mL beaker
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1. The partial molar volumes of acetone and chloroform are 74.16 cm3 mol-1 and 80.23 cm3 mol-1 respectively. Calculate the volume of a mixture containing 25.00 moles of acetone and 75.00 moles of chloroform. 2. Acetone has a molar mass of 58.1 g mol-1 and a density of 0.787 g cm-3. Chloroform has a molar mass of 119.4 g mol-1 and a density of 1.499 g cm-3. Estimate the volume of the above mixture using this information. 3. Calculate the molal freezing point depression constant Kf for
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Contents Part One Investigation of a Workplace Incident Investigation Policy PURPOSE The purpose of this policy is to ensure that: all hazards‚ near misses and injuries are reported to management. investigations are carried out in a sensible manner with preventative actions identified and put into practice in due course. follow up monitoring is undertaken to ensure hazards are removed or reduced as much as possible and that no new hazards will be introduced to the workplace
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study the test of identification of alkyl halide Chemicals and Apparatus: ~18.0 g 1-butanol‚ ~20.0 g sodium bromide‚ 15 ml of concentrated sulfuric acid‚ anhydrous magnesium sulfate‚ ~10 ml of 5% aqueous sodium bicarbonate‚ ~1 ml of sodium iodide – acetone reagent‚ 1 ml of bromine in chloroform‚ 1 piece of 100 cm3 round-bottomed flask‚ 1 piece of 50 cm3 of beaker‚ 1 piece of 50 cm3 of conical flask‚ 1 piece of 250 cm3 of separating funnel‚ 1 piece of 10 cm3 of measuring cylinder‚ 1 piece of electronic
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the 3 tubes of solution that we received were individually tested to determine its composition. Next‚ we created a solution of tube A mixed with acetone and tested it through gas chromatography. The reason this was done‚ is because if tube A really did contain acetone the tallest peak on the gas chromatography results would be at the position for acetone but only
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helps to remove the dichloromethane. Then‚ you’re only left with the caffeine‚ effectively isolating it. In order to bring it back from the current state its in due to the evaporation however‚ acetone hot acetone and petroleum ether are needed2. These cause the caffeine to “bottom out”‚ and turn to a solid. Acetone is polar so it’ll allowed for the dissolving of the caffeine‚ and the cooling is what helped form the
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GRAM STAIN THEORY: The most widely used staining procedure in microbiology is the Gram stain‚ discovered by the Danish scientist and physician Hans Christian Joachim Gram in 1884. Gram staining is a differential staining technique that differentiates bacteria into two groups: gram-positives and gram-negatives. The procedure is based on the ability of microorganisms to retain color of the stains used during the gram
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In this experiment the substances that were used were acetone‚ methanol‚ water‚ 1- butanol and ethyl acetate. Acetone is the organic compound with the formula (CH₃)₂CO. It is a colorless‚ volatile‚ flammable liquid‚ and is the simplest ketone. It takes 21 seconds for it to completely disappear. It was the first to evaporate among all tested substances. The reason for this is that this molecule is not attracted to another molecule of Acetone by hydrogen bonding because although there are hydrogen
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Likeness of polarity of solutes and solvents Compound Ethanol V. Oil Acetone Water MISCIBLE IMMISCIBLE MISCIBLE Ethanol ------------- IMMISCIBLE MISCIBLE Acetone MISCIBLE IMMISCIBLE -------------- V. Oil IMMISCIBLE ------------- IMMISCIBLE Table 3. Miscibility of some liquid substances with each other. Compound Ethanol (Polar) V. Oil (Non-polar) Acetone (Polar) Water (Polar) LIKE UNLIKE LIKE Ethanol (Polar) ----------- UNLIKE LIKE Acetone (Polar) LIKE UNLIKE ------------ V. Oil (Non-polar) UNLIKE -------------
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reactions are an important class of reactions because of their synthetic utility and importance in understanding the mechanism of a variety of organic reactions. Materials & Methods: (Effect of Structure of the Alkyl Halide) 2mL of 15% of NaI in acetone was put into three test tubes. Two drops of 1-bromobutane were added to the first test tube. Two drops of 2-bromobutane were added to the second test tube. Two drops of 2-methyl-2-bromobutane were added to the third test tube. The test tubes were
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