structure. Ferrocene has the properties of both an activated benzene (undergoes electrophilic substitution reactions) and a ferrous ion (oxidation reaction). Glyme and DMSO are used as solvents as they have moderate polarity so they would break up KOH into K+ and OH-‚ without breaking the hydrogen bonding in the hydroxide ion. Cyclopentadiene is relatively acidic so a strong base would be needed to abstract
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Cellular Respiration Lab - The Bean Lab lntroduction In today’s lab‚ you will be investigating cellular respiration. Cellular respiration as you know is the process that cells use to use to obtain energy from organic molecules. Typically‚ you will see the equation for cellular respiration represented in the equation below. CeHrzOo + 6 Oz+ 5CO2 + SHzO + EnergY This equation represents aerobic cellular respiration. Aerobic respiration occurs in the mitochondria of eukaryotic cells
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expectation of a male or female gender. Max could have been known as a man to many‚ but he decided that he was an intersex. Because many people are unaware of this intersex identity‚ they would find it very confusing. For Koh‚ she felt like she was a female. After she transitioned into a katoi‚ Koh would get certain treatments by her loving partner and his family. They would treat her as a beautiful and fragile girl who needs a lot of protection. Because of those actions that culture has assigned to women‚
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We were given KOH and KNO3 as our salts. We weighed the calorimeter and water then subtracted accordingly o get the mass of the calorimeter and that of the water. The lab instructed on the amounts of water and salt to be used. The initial temperature of the water in the KOH reaction was 22.8 degrees Celsius and the final temperature of the mixture determined from the graph was 37.0 degrees Celsius. The graph of the KOh showed it to be an exothermic salt and the KNO3
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with the reaction of aluminum (Al) and potassium hydroxide (KOH). The potassium hydroxide is used to dissolve some of the traces of various metals present in the sample of scrap aluminum and when reacting with the aluminum produces hydrogen gas and aluminate ions 2 Al(s) + 2 KOH(aq) + 6 H2O(l) 2 KAI(OH)4(aq) + 3 H2(g) The limiting reagent in this reaction is aluminum since we are producing “alum” crystals. The excess reagent is KOH. This excess is necessary to help accelerate the reaction
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do. It can be concluded through looking at the evolutionary theories of why people bully‚ that bullies behave in the way they do to reach a goal‚ whether that goal is to gain recourses‚ to achieve good mental health or to gain physical protection (Koh & Wong‚ 2015). When children with autism or other exceptionalities exhibit similar behaviours such as aggression‚ they are not doing so to reach a goal. The behaviours that children with autism spectrum disorder (ASD) exhibit are not always behaviours
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Trial | 1st | 2nd | 3rd | 4th | 5th | Start | 3.00 | 3.20 | 5.20 | 18.55 | 1.90 | 14.65 | Finish | 17.35 | 18.10 | 18.10 | 31.50 | 14.65 | 27.65 | Titre | 14.35 | 14.90 | 14.90 | 12.95 | 12.75 | 13.00 | Average titre = 12.90cm3 NH2SO3H + KOH – NH2SO3K + H20 Sulphamic Acid Standard Solution Moles from mass weighed Moles = Mass Mr = 2.42 97.1 = 0.0249mol Molarity of solution Concentration = Moles Volume
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patel (rmp932) – Post-Lab 5 Acid/Base Titration – lyon – (51730) This print-out should have 25 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Answer the question to at least six significant figures. A solution of sodium hydroxide is standardized against potassium hydrogen phthalate (KHP‚ formula weight 204.2 g/mol). From the following data‚ calculate the molarity of the NaOH solution: mass of KHP 1.404 g; buret reading
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saponifiable lipids are triacylglycerols‚ waxes‚ sphingolipids and phospholipids. Unsaponifiable lipids on the other hand are those with fused rung compounds such as steroid and cholesterol. [8] Molecular weight can be calculated by MW= (3 x g sample)/(mol KOH) (1) Lipids of natural origin are usually obtained from their esters by alkaline hydrolysis. Such procedures allow the yield of complex mixtures of fatty acids which are resolvable with relative difficulty. Description of fatty acids therefor is
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the solution of known concentration are reacted to the point where the number of acid equivalent equals the number of base equivalents ‚ the equivalent point is reached . For example‚ the reaction between potassium hydroxide and hydrochloric acid : KOH + HCl .The equivalent point of a strong acid or strong base will occur at pH7 . However‚ for the weak acids and bases ‚ the equivalent point will usually no occur at pH 7 .The indicator can be used to estimate the equivalent point by observing the colour
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