equation by adding a correct coefficient to it. Question 1 __ SnO2 + __ H2 → __ Sn + __ H2O Question 2 __ KOH + __ H3PO4 → __ K3PO4 + __ H2O Question 3 __ KNO3 + __ H2CO3 → __ K2CO3 + __ HNO3 Question 4 __ Na3PO4 + __ HCl → __ NaCl + __ H3PO4 Question 5 __ TiCl4 + __ H2O → __ TiO2 + __ HCl Question 6 __ C2H6O + __ O2 → __ CO2 + __ H2O Question 7 __ Fe + __ HC2H3O2 → __ Fe(C2H3O2)3 + __ H2 Question 8 __ NH3 + __ O2 → __ NO + __ H2O Question 9 __ B2Br6 + __ HNO3 → __ B(NO3)3 + __ HBr Question 10 __ NH4OH
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Abstract By using acid-base titration‚ we determined the suitability of phenolphthalein and methyl red as acid base indicators. We found that the equivalence point of the titration of hydrochloric acid with sodium hydroxide was not within the ph range of phenolphthalein’s color range. The titration of acetic acid with sodium hydroxide resulted in an equivalence point out of the range of methyl red. And the titration of ammonia with hydrochloric acid had an equivalence point that was also out of
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Analytical Chemistry Experiment 2b: Determination of the ASA Content of Aspirin Due Date: September 16‚ 2013 Experiment#: 2b Title: Determination of the ASA Content of Aspirin Aim: To determine the Molar Concentration of NaOH and HCl acid used in their Standardization processes and to determine the acetylsalicylic acid (ASA) content in Aspirin. Materials/Apparatus: materials used are the same as that outlined in the laboratory procedure prepared by the laboratory instructor. Procedure:
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Chemistry Lab Report (Design) Factors affecting Rates of a Reaction (Kinetics) KINETICS DESIGN LAB Research Question: Does the concentration of Potassium Iodide (KI) affect the rate of its reaction with hydrogen peroxide (H2O2) (of a fixed concentration)? Introduction: There are several factors that affect the rate of a reaction. Some of them being Pressure (if the reactants are Gases)‚ Temperature‚ Presence of a Catalyst‚ Surface Area of the reactant‚ and Concentration. According to
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Chemistry is a big part of your everyday life. You find chemistry in daily life in the foods you eat‚ the air you breathe‚ your soap‚ your emotions and literally every object you can see or touch. Here ’s a look at some everyday chemistry. Elements in the Human Body Steve Allen‚ Getty Images Your body is made up of chemical compounds‚ which are combinations of elements. While you probably know your body is mostly water‚ which is hydrogen and oxygen‚ can you name the other elements that make
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Pre Lab Experiment 8 DETERMINATION OF % COMPOSITION OF PENNIES USING REDOX AND DOUBLE DISPLACEMENT (PRECIPITATION) REACTIONS Objectives: 1. Learn how to determinate the percent composition 2. Learn how to get the percent using oxidation reduction and double reactions 3. To become more familiar with the use titration techniques 4. To learn how to get the salt out of an quimical Background: To develop and utilize procedures to determine the percent composition‚ of ZnCI2. As well titrating
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is ambidentate. The following reactions show how linkage isomers can be prepared. [Co(NH3)5Cl]Cl2(s) + dilNH3(aq) → [Co(NH3)5(OH2)]Cl2 [Co(NH3)5Cl]Cl2 + NaNO2 + conc. HCl → [Co(NH3)5(NO2-N)]Cl2 (yellow or orange-brown) [Co(NH3)5Cl]Cl2 + NaNO2 → [Co(NH3)5(NO2-O)]Cl2 (red/ salmon-pink crystal) [Co(NH3)5(NO2-O)]Cl2 + warm HCl → [Co(NH3)5(NO2-N)]Cl2 (yellow or orange-brown) [Co(NH3)5(NO2-N)]Cl2 + UV → [Co(NH3)5(NO2-O)]Cl2 (red/ salmon-pink crystal) The complexes [Co(NH3)5(NO2-N)]Cl2 and [Co(NH3)5(NO2-O)]Cl2
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Standard Hydrochloric Acid Solution Abstract The aim of the experiment was how to determine the molarity of a solution. My hypothesis was if I have to determine the molarity of a NaOH solution‚ then I would have to use a standard solution of HCl solution because I would need to neutralize each other to determine the concentration of the solution of NaOH. The method that I used for this experiment was titration. Titration helped me achieved the result on figuring out the unknown molarity of
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PAHANG TRIAL 2009 EXAMINATION CHEMISTRY PAPER 2 MARKING SCHEMES SECTION A - Structural Questions: Question 1. (a) (i) The presence of isotopes 1M (ii) Let the abundance of 63X be a %. The % abundance of 65X. = ( 100 – a ) 1M Relative atomic mass = ( 62.93 x a) + ( 64.93 x ( 100 -a) ) 1M
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Chemistry 101 General Chemistry Fall 2013 –Syllabus S. Bakshandeh Office Hours: MW‚ 12:00–12:35 pm & T; 1:40-2:15 pm Room 92032 and/or Lab 92011. Email: sbakshandeh@yahoo.com – The best way to reach me is by email. Please indicate your full name and section number in the “Subject/Re” box. I will not open emails without proper identification. Blurb: Welcome to your first course in college chemistry. In this course‚ we will be exploring laws‚ theories‚ and principles of chemistry as related
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