the limiting reagent Methyl benzoate= (0.4095 g)/ (136.15 g/mol) = .0030 mol Theoretical yield= (181.15 g/mol) x .0030 mol = 0.54345 g Mass of crude product= 0.6981 g % Yield = ( 0.6981 g/0.54345 g) x 100%= 128.46 % Possible by-product: Methyl 3‚5-dinitrobenzoate: (C8H6N2O6)‚ Average mass= 226.14 g/mol‚ melting pt.=107-109 °C(lit.) theoretical yield= (226.14 g/mol) x .0030 mol= 0.67842 g % yield =( 0.6981 g /0.67842 g) x 100% = 102.90 % The methyl benzoate was the limiting reagent
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Abstract This work describes the extraction of caffeine from tea leaves to determine its % caffeine. The extraction process selectively dissolves one or more compounds in a mixture into an appropriate solvent. In this experiment‚ it was visible in the process wherein the components of the tea leaves were dissolved in two solvents‚ water and dichloromethane (DCM)‚ with DCM used for multiple extractions. The organic layer was evaporated and the determined % caffeine was 0.12%. Furthermore‚ the purified
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Epoxidation Reactions Lab Report 2 Abstract An oxygen atom is transferred from a peroxy acid to the carbon=carbon double bond thus forming an epoxide. Scheme 1. Oxone Epoxidation. Scheme 2. mCPBA Epoxidation. The percent yield for the Oxone epoxidation reaction was 65% yield and the mCPBA epoxidation reaction was 70% yield. Oxone is the greener alternative because using mCPBA is twice as expensive as Oxone and leaves behind the epoxide plus m-chlorobenzoic acid while Oxone creates non-toxic
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Experiment 15 & 16: Preparation of 1-bromobutane‚ an SN2 reaction Preparation of 2-chloro-2-methylbutane‚ an SN1 reaction Introduction The purpose of this experiment is to synthesize 1-bromobutane from 1-butanol and sodium bromide. In order for this reaction to reach completion there are four major operations that need to be performed. The four major operations include refluxing‚ simple distillation‚ separation‚ and drying. To begin‚ in order for the compounds to react they will be dissolved
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Sodium borohydride Reduction of Benzil Introduction: The Purpose of this experiment is for the students to learn how to use sodium borohydride to reduce benzil to its secondary alcohol product via reduction reaction. This two-step reaction reduces aldehydes by hydrides to primary alcohols‚ and ketones to secondary alcohols. In order for the reaction to occur and to better control the stereochemistry and yield of the product‚ the metal hydride nucleophile of the reducing agents such as LiH‚ LiAlH4
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Cellulose Cellulose is an organic compound with the formula (C6H10O5)n‚ a polysaccharide consisting of a linear chain of several hundred to many thousands of β(1→4) linked D-glucose units. Cellulose is an important structural component of the primary cell wall of green plants‚ many forms of algae and the oomycetes. Some species of bacteria secrete it to form biofilms. Cellulose is the most abundant organic polymer on Earth. The cellulose content of cotton fiber is 90%‚ that of wood is 40–50% and
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Chemistry 1035 – General Chemistry I Fall Semester‚ 2013 3 hours credit‚ CRN 91627 Office Hours (Randolph 144) Preston Durrill‚ Instructor M 8:00-9:00‚ 1:30-5:00 Randolph Hall‚ Room 144 Tu 9:00-11:00‚ 4:00-5:00 Office phone: 540-231-6774 W 8:00-9:00‚ 1:30-5:00 Home phone: 540-961-5179 Th 9:00-12:00‚ 4:00-5:00 e-mail: pdurrill@vt.edu F 8:00-9:00‚ 1:30-3:00 Class times: 2:00-3:15 Tuesday and Thursday in McBryde 100. Evening help sessions: Wednesdays 5:00-6:30 p.m. in Hancock
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Actual: Melting pt (or bp) 81-83 C N/A Literature: 312-315 C N/A Experimental: Percent Yield Calculation: Limiting Reagent: 1 mg= .001 g‚ 100 mg= .1 g vanillin Moles vanillin = .1g/152.15 g/mol= 6.57x10^-4 moles Density H2O2= 1.45 g/mL Mass H2O2= 1.45 g/mL x .75mL = 1.088g Moles H2O2= 1.088g/34.015 g/mol =.032 moles Limiting reagent = Vanillin Theoretical Yield: 1 mol Divanillin= 2 moles Vanillin Moles divanillin= .5 mol vanillin= 6.57x10^-4 mol/ 2 = 3.29x 10^-4
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considering that the photoreduction period took a couple extra days due to lack of sunlight‚ loss of product can be attributed to this since we only could get 2.11g/3.0g of benzpinacol from the start of the lab. And since benzpinacol was the limiting reagent‚ before starting part 2 of the lab this already set us up for some loss in % yield. Also when we transferred our product from the filtration funnel to the watch glass there was product loss because many of the crystals were stuck in the flask
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in water and will produce a blue solution. solutioAluminum is the compound that has a chemical formula of Al. This is a silver solid that can be easily formed‚ machined‚ or cast. In this lab‚ we will be finding the limiting reactant between Copper(II) Chloride and Aluminum. The limiting reactant is‚ reactant is‚ the reactant in a chemical reactant that limit’s the amount of the product that can be formed. We will also need to find the molarity of Copper (II) Chloride in the solution. The molarity
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