Pallagani Investigating Stoichiometry with sodium salts of carbonic acid 4/2/14 A summary of the concepts: The purpose of this lab is to better understand “stoichiometry”. We will be reacting sodium carbonate (NaHCO)3 and sodium carbonate (Na2CO3) with hydrochloric acid to produce sodium chloride‚ water‚ and carbon dioxide. The balanced chemical reaction looks like this: NaHCO3 + HCl = NaCl + H2O + CO2 CAUTION: Be especially careful when handling the 6M HCl (aq)‚ as it can cause chemical
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HCl with Sodium Carbonate: Na2CO3 + 2HCl 2NaCl + H2O + CO2 (2) Concentration of Sodium Carbonate (Na2CO3) Molar mass of Na2CO3 : 22.99*2+12.01+16*3=105.99 Mass of Na2CO3 : 1.3 g Number of moles : n=mM =1.3 105.99=0.012265308 mol Volume Na2CO3 solution : 250 mL : 0.250 L Concentration: Concentration of Sodium Carbonate is 0.049 mol L-1 c=nV = 0.012265308 0.250=0.049061232 mol L-1 (3)Concentration of HCl Volume of Na2CO3 solution : 20 mL : 0
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CaCO3 product on the labeled watch-glass. 17. Leave your labeled watch glass out for drying overnight (low temperature). 18. Record the mass of the dry filter paper + CaCO3. Record mass Questions and answers for Limiting Reactant 1. The mole of Na2CO3 used is n= m÷M = 3.01g÷105.99 =0.028mol 2. The moles of CaCO3 n= m÷M = 4g÷100.09g/mol =0.040 mol 3a: mass of CaCO3 produced is m=n×M = 0.028mol×100.09g/mol
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Sodium Carbonate (Na2CO3) Introduction: To determine the total amount of carbonate in unrefined sodium carbonate‚ soda ash‚ a titration is done using a standardized solution of HCl. Aqueous HCl is a strong acid and therefore almost completely disassociates into H+ and CL-. Therefore‚ when HCl is used in a titration‚ the H+ is the titrant. Carbonate in aqueous solution is able to accept a proton‚ i.e. it acts as a base. When carbonate accepts the H+ a bicarbonate ion is formed. Na2CO3(aq) + HCl(aq)
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to the first reactant and it will give you a full reaction. To figure out what you need you have to use stoichiometry. My calculation for the second reactant was: 1.0g CaCl2*2H2O(1mol CaCl2*2H2O/147g CaCl2*2H2O)(1mol Na2CO3/1mol CaCl2*2H2O)(106g Na2CO3/1mol Na2CO3) = 0.72g Na2CO3. The final‚ when its dried in the paper filtered weighed at 1.6 grams. Experiment and Observations: As I performed the lab‚ I had to retrieve all my equipment’s from my labpaq. As I started to setup‚ I had to weigh out
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Materials Mass (g) Clean and dry test tube 15.1632 Clean test tube + NaHCO3 17.1647 Amount of NaHCO3 added 2.0015 After heated test tube + NaHCO3 16.4500 Amount of solid product (NaHCO3 + any unreacted NaHCO3) 1.2868 Part 2: Titration of Na2CO3 with Hydrochloric acid (HCl) First Reading Second Reading Third Reading Initial
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The decomposition of sodium carbonate is definitely‚ Na2CO3(s)+CO2(g)+H2O(g). The was the only equation that matched up exactly with my data in terms of percentage. To start off with‚ when I balanced out the equation‚ I got 2 NaHCO3→ 1 Na2CO3(s)+ 1 CO2(g)+ 1 H2O(g). Therefore when I set up my stoichiometry problem I got 3.2 grams NaHCO3 over 1 x 1 mol NaHCO3 over 84.007g NaHCO3 x 1mol Na2CO3 over 2 mol NaHCO3 x 105.987g Na2CO3 x 1 mol Na2CO3. Hence‚ I multiplied 3.2 x 1 x 1 x 105.987 and got 339
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experiments in determining the quantities ∆Hᶿ for the reactions of NaHCO3 and Na2CO3. The reaction are as follow: 2NaHCO3 (s) + H2SO4 (aq) Na2SO4 (aq) + 2CO2 (g) + 2H2O (l) [1] ∆Hᶿ = Y kJmol-1 Na2CO3 (s) + H2SO4 (aq) Na2SO4 (aq) +H2O (l) + CO2 (g) [2] ∆Hᶿ = Z kJmol-1 _____________________________________________________________________________________________________ [1] – [2’] 2NaHCO3 (s) Na2CO3 (s) +H2O (l) + CO2 (g) [3] ∆Hᶿ = X kJmol-1 The enthalpy‚ H is defined as
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Neutralization Titrations: The Determination of Sodium Carbonate from Unknown Soda Ash Unknown # I. Purpose: The goal of this experiment is to determine the weight % of Na2CO3 through the preparation of NaOH and HCl standards. The molarity of the standards will be found through titration of KHP for NaOH‚ HCl vs the known NaOH‚ and the unknown Soda Ash sample vs the known HCl. II. Equations and Sample Calculations: Titration of HCl with NaOH: Complete Equation: HCl (aq) + NaOH (aq)
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7 INVESTIGATING STOICHIOMETRY WITH SODIUM SALTS OF CARBONIC ACID Introduction In this experiment we are going to get a better understanding of chemical stoichiometry. We are going to be reacting sodium bicarbonate (NaHCO3) and sodium carbonate (Na2CO3) with hydrochloric acid (HCl). To start off the mass of two unknown substances (being the sodium bicarbonate and sodium carbonate) will be taken. We will need to construct balanced equations for both of the reactants with the HCl and use this to guide
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