How do the total masses of the reactants and products compare?______________equal_________________ Section 11.1 continued In your textbook‚ read about mole ratios. Answer the questions about the following chemical reaction. sodium iron(III) oxide → sodium oxide iron 6Na(s) Fe2O3(s) → 3Na2O(s) 2Fe(s) 15. What is a mole ratio? A mole ratio is a ratio
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Mini-Report: How Do Scientists Report Data? “Determination of the Empirical Formula of an Unknown Lead Oxide” By: Dr. C. Steven Joiner In this paper‚ they walk through and explain the process known as smelting. The experiment demonstrates the historical process known as smelting and could theoretically be used to determine the empirical formula of other metal oxides found in nature. This paper explains how the process of smelting and how metals can be extracted from their ores. This is because
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then fuse them in the melting pot of 130O-140OnC‚ and finally cool them into solid soluble glass. Considering the differences of alkali metal oxide‚ soluble glass can be divided into sodium silicate and potassium silicate‚ and sodium silicate is often used. Among the components of sodium silicate (Na2O*nSiO2)‚ the ratio of silicon oxide molecules to sodium oxide molecules is known as the module of soluble glass‚ generally between 1.5 to 3.5. And the number of module decides the properties and performance
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Reflectance Calculated Stability Factor SOLE HEATED OVEN: (52/2) % Moisture % - 6 Mesh BDT ET Contraction 52/2 DRY BASIS: 27.45 9.47 63.08 14‚078 7821 0.86 MAF MINERAL ANALYSIS: Silicon Dioxide SiO2 Aluminum Oxide Al2O3 Iron Oxide Fe2O3 Calcium Oxide CaO Magnesium Oxide MgO Sodium Oxide Na2O Potassium Oxide K2O Titanium Dioxide TiO2 Phos. Pentoxide P2O5 Sulfur Trioxide SO3 DRY BASIS 55.75 26.81 7.39 1.70 1.03 0.56 2.59 1.33 0.37 1.27 15‚551
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population‚ is factors contributing toward the growing air pollutants. In today’s time it is critical that solutions must be found to better the air. The main and major air pollutants found in most city areas are carbon monoxide‚ nitrogen oxides‚ sulfur oxides‚ hydrocarbons‚ and particulate matter‚ liquid or solid form. These pollutants are isolated throughout the world’s atmosphere in areas high enough to increasingly cause serious health risks. Serious health problems can take place rapidly when
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(NH4)3PO4 c. ammonium phosphate SnS2 d. tin(IV) sulfide HNO2 e. nitrous acid 2. Write the Stock names for the following compounds: magnesium perchlorate a. Mg(ClO4)2 iron(II) nitrate b. Fe(NO3)2 iron(III) nitrite c. Fe(NO2)3 cobalt(II) oxide d. CoO nitrogen(V) oxide e. dinitrogen pentoxide 3. 13 atoms a. How many atoms are represented by the formula Ca(HSO4)2? 4.0 mol b. How many moles of oxygen atoms are in a 0.50 mol sample of this compound? +6 c. Assign the oxidation number to sulfur in the
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40 – 60 % propene is used for the manufacture of 2-propanol. A large number of catalysts for 2-propanol dehydrogenation have been studied‚ including copper‚ zinc‚ and lead metals‚ as well as metal oxides‚ e.g.‚ zinc oxide‚ copper oxide‚ chromium-activated copper oxide‚ manganese oxide‚ and magnesium oxide. Inert supports‚ such as pumice‚ may be used. CH3CH=CH2 CH3CH(OH)CH3 CH3COCH3 +H2 (3) By catalytic oxidation of Propene (Wacker-Hoechst). The process is analogous
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acidic presents two different problems for crops. First‚ the amount of necessary minerals in the soil such as potassium and calcium decreases. Second‚ aluminum and manganese levels increase to potentially toxic levels below a pH of roughly 5.5.Calcium oxide‚ addresses the problem. It reacts in water to release calcium ions and hydroxide ions‚ which raise the pH of the soil.The soil which is too acidic will be neutralised by the lime which is alkaline. H2O + CO2 -> H2CO3 2SO2 + H2O + O2 -> 2H2SO4
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explode. It reacts with non-metallic elements except for nitrogen‚ oxygen‚ noble gases‚ silicon and halogens. It oxides them to their highest oxidation states(3) as acids with the formation of nitrogen dioxide for concentrated acid and nitric oxide for dilute acid. Chromium (Cr)‚ iron (Fe) and aluminium (Al) dissolve in dilute nitric acid‚ which the concentrated acid forms a metal oxide layer that protects the metal from further oxidation‚ and it is called passivation. Nitric acid can be made
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experiment. Keeping that in mind‚ I checked the information of each reactants and products on online resources. Not only did that help me realize the Aluminum was oxidized‚ it helped me understood that the product was the gray Copper (II) Oxide instead of the red Copper (I) Oxide. This was one of the problems that I was able to solve by careful observation and checking additional
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