the electrons as a back donation to the pi orbital in DMSO. In the first experiment‚ I had to synthesized CuCl2~2DMSO to determine which DMSO atom; Sulfur or Oxygen‚ combined to Copper (II) Chloride. I was able to determine it base on finding the melting point and observing the Infrared Spectroscopy. Since copper is a hard metal‚ it will most likely bond to an oxygen atom because they are both hard. In the second experiment‚ I also synthesized RuCl2~4DMSO to determine which DMSO atom; Sulfur or Oxygen
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Yield of CuCl2.2DMSO Formula weight (Mr) of CuCl2 = 63.55 + (35.45 x 2) =134.45g/mol Formula weight of product CuCl2.2DMSO = 134.45 + 2[16 + 32.06 + (12.01 x 2) + (1.0079 x 6)] = 290.704g/mol Mass of CuCl2= 0.850g Equation for reaction CuCl2 + 2DMSO -> CuCl22DMSO Mole ratio between CuCl2 and CuCl22DMSO = 1:1 Mole of CuCl2 = Mass/ Mr = 0.850/134.45 = 0.00632 moles Since the ratio between CuCl2 and CuCl22DMSO = 1:1‚ mole of CuCl2DMSO is also 0.0063 moles. To find theoretical yield of CuCl2
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Biotechnology‚ Mapua Institute of Technology ABSTRACT In this experiment‚ solubility class of various organic compounds are to be determined. The main objective of the experiment is to identify an unknown compound through the use of preliminary tests such as examination of physical state‚ color‚ odor‚ and ignition properties. Also‚ solubility tests were used to further examine an unknown compound’s solubility class. In this experiment‚ the apparatus used are micro test tubes and droppers for mixing
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hydrogen tartrate. (PL3) Calculate the theoretical solubility product‚ Ksp‚ of potassium hydrogen tartrate at 25C and at 100C. (PL4) Write a balanced equation showing the titration of potassium hydrogen tartrate solution with NaOH; Procedure : (1) Weigh out ~2.0g of finely powdered potassium hydrogen tartrate into 250.mL beaker. (2) Add 150.mL of distilled water and stir well. (3) Using a vacuum filtration‚ filter the solution into a clean‚ dry Erlenmeyer flask with a side arm. (4) Record
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EXPERIMENT 1 “HOW DO I LOVE THEE LET ME COUNT THE WAYS...” DETERMINATION OF AVOGADRO’S CONSTANT Techniques Calibration drop counting MSDS available for • • stearic acid‚ CH3(CH2)16COOH cyclohexane‚ C6H12 Principles molar volume molecular structures surface areas and volumes Avogadro’s constant percent error Recommended Advanced Reading Chapter 3 in Petrucci‚ Herring‚ Madura‚ & Bissonnette’s General Chemistry‚10th Ed. Avogadro Constant...1 INTRODUCTION
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Experiment 1 Calorimetry Chem 17 Univerity of the Philippines Diliman Discussion All chemical reactions involve energy. By understanding the behavior and connection of energy flow within a chemical reaction‚ we can understand and manipulate them to our advantage. The most common form of energy observed during chemical reactions is heat. The reaction may absorb (endothermic) or release (exothermic) heat‚ depending on the reacting substances. Calorimetry is the process of measuring the heat flow
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with a 12 percent coupon. Bond D is a 6 percent coupon bond currently selling at a discount. Both bonds make annual payments‚ have a YTM of 9 percent‚ and have five years to maturity. The current yield for Bonds P and D is percent and percent‚ respectively. (Do not include the percent signs (%). Round your answers to 2 decimal places. (e.g.‚ 32.16)) | If interest rates remain unchanged‚ the expected capital gains yield over the next year for Bonds P and D is percent and percent‚ respectively
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Experiment 1: Bromination of Acetanilide1 Precautions: Ethanol is flammable Sodium hypochlorite is an oxidizing agent and releases toxic fumes (handle in fume hood) Acetic acid is corrosive‚ harmful if inhaled‚ flammable and can cause burns (handle in fume hood) Gloves are recommended to avoid chemical contact with skin Reaction Scheme: Conversion of acetanilide to p-bromoacetanilide Procedure: To a 125 mL Erlenmeyer flask containing a mixture of 95% ethanol (6 mL) and acetic acid (5 mL)‚ dissolve
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Chapter 10 Bond Prices and Yields 1. a. Catastrophe bond: Typically issued by an insurance company. They are similar to an insurance policy in that the investor receives coupons and par value‚ but takes a loss in part or all of the principal if a major insurance claim is filed against the issuer. This is provided in exchange for higher than normal coupons. b. Eurobond: They are bonds issued in the currency of one country but sold in other national markets. c. Zero-coupon bond: Zero-coupon bonds
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Week 3 Time Value of Money and Valuing Bonds Chapter 6 55. Amortization with Equal Payments Prepare an amortization schedule for a five-year loan of $36‚000. The interest rate is 9 percent per year‚ and the loan calls for equal annual payments. How much interest is paid in the third year? Answer: $2‚108.52 56. Amortization with Equal Principal Payments Rework Problem 55 assuming that the loan agreement calls for a principal reduction of $7‚200 every year instead of equal annual payments. Answer:
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