recognizes what a cube looks like‚ able to identify the length of one side‚ know that a cube has six equal sides‚ and the students will needs to be able to calculate the area of a square in order to calculate the surface area of a cube. Students will also need to recall that 3-dimensional objects are measured out in “square units.” Forming the Cube First students will learn that 2-dimensional objects are flat and only deal with length and width; whereas 3-dimensional deal with length‚ width
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equiangular (all angles are congruent) and equilateral (all sides have the same length). Regular polygons may be convex or star. (5.01) 1) Describe the figure below. (convex / concave? …) [pic] regular quadrilateral – convex – rhombus - square 2) Describe the figure below. (convex / concave? …) [pic] irregular quadrilateral – convex – trapezoid 3) Describe the figure below. (convex / concave? …) [pic] irregular quadrilateral – concave 4) Describe the figure below
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ruler Value: Appreciation III.Learning Experience A.Preparatory Activities 1. Math Song 2. Drill Give the Product 1. 15x3 2. 10x4 3. 11x2 4. 12x4 5. 10x24 3. Review Find the area of the following square. 1. 2. 3 cm 4 cm 3. 4. 2 in 9 in 5. 7 cm B. Developmental Activities 1. Motivation * Do you have a vegetable garden in your backyard? * What vegetables do you have in your garden?
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Michael Brause CMIS 102-6387 May 30‚ 2015 Program description: I calculated the usable area in square feet of a house. Assume that the house has a maximum of four rooms‚ and that each room is rectangular. I wrote pseudo code statements to declare 4 Integers and labeled them homesqft‚ room1‚ room2‚ room3‚ and room4. Each room will have its length and width to calculate its area. Analysis: Test Case # Input Expected Output 1 Room1: length=10‚ width=14 Room2: length=9‚ width=10 Room3: length=12
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Conducting a z-Test Psychological Statistics Module 2: Assignment 2 Argosy University Gemini Dickerson 3/12/14 A film was shown to 36 students to see if the attitudes of students toward the mentally ill would change. The results of the class of 36 that watched the film had a score of 70. The results of the class that did not watch the film had a score of 75. The standard deviation is 12. When the alpha is set to 0.05. .05 is a mid-probability. It means we’re using to reduce the likelihood
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are equal and the opposite angles are equal. 2. Prove that diagonals of a rhombus bisect each other at right angles. 3. Two adjacent angles of a parallelogram are as 2:3. Find the measure of each of its angles. 4. Prove that the diagonals of a square are equal and bisect each other at right angles. 5. If an angle of a parallelogram is two-third of its adjacent angle‚ then what is the smallest angle of the parallelogram? 6. The length of diagonals of a rhombus are 16cmand12cm. Find the length
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[CHRISTMAS REVISION SHEETS] 4. Look at these five numbers: 5. ABDF is a rectangle and BCDE is a parallelogram. Work out the area of: J.Camenzuli | www.smcmaths.webs.com 2 Form 2 [CHRISTMAS REVISION SHEETS] 6. Look at this square. What fraction of the whole square is shaded? 7. Change: 8. J.Camenzuli | www.smcmaths.webs.com 3 Form 2 [CHRISTMAS REVISION SHEETS] 9. 10. Show all your working: Non Calculator J.Camenzuli | www.smcmaths.webs.com 4 Form 2 [CHRISTMAS
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SYLLABUS MATHEMATICS(041) SA-II (2012-13) Annexure ‘E’ Second Term UNITS II III V VI ALGEBRA GEOMETRY (Contd.) MENSURATION (Contd.) STATISTICS AND PROBABILITY TOTAL Marks: 90 MARKS 16 38 18 18 90 The Question Paper will include value based question(s) To the extent of 3-5 marks. The Problem Solving Assessment will be conducted for all students of class IX in Jan – Feb 2013 and the details are available in a separate circular. The `Problem Solving Assessment’ (CBSE-PSA) will
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(–2) × (–2) × (–2) (–2)5 base –2‚ exponent 5 Example 1: Write the following in exponential form. a. Minus nine to the power of six b. One fourth to the power of five c. Three square to the power of five Solution: a. Minus nine to the power of six = (−9)6 b. One fourth to the power of five = c. Three square to the power of five = (32)5 Example 2: Write the base and the exponent for the following. a. b. (–2.5)5 Solution: a. Here‚ base = ‚ exponent = 2 b. (–2
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Consecutive angles are supplementary 4. Shorter diagonal is bisected Isosceles Trapezoid 5. Diagonals bisect each other Rhombus Rectangle 1. Four congruent sides 1. Four right angles 2. Diagonals are perpendicular 2. Diagonals are congruent Square All of the above (12) 3. Diagonals bisect opposite angles (vertices) 1. Base angles are congruent 2. Diagonals are congruent 3. Legs of trapezoid are congruent
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