half-cells. The glass electrode is an ion selective electrode (ISE)‚ which only responds to the hydronium ion concentration / activity in a solution under a large range of conditions. In this experiment‚ we are measuring the fluoride ion concentration‚ which means our electrode responds to fluoride ion concentrations. Procedure And Data: |Standard Solutions | |Concentration (M) |Potential (mV) | |0
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61 grams and the volume decreased by 17.3 milliliters while the mass of the cup with the tubing holding glucose solution also decreased by 1.19 grams and the volume decreased by 2.2 milliliters (Emma Ricks and Allen Hansen). The movement of water into the protein solution bag caused the mass to increase by 7.95 grams and the volume to increase by 2.4 milliliters and the glucose solution bag increased by 1.97 grams in mass and 2.2 milliliters in volume (Emma Ricks and Allen Hansen). The water had a
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2032-Ch09-homework MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) In water‚ a substance that ionizes completely in solution is called a ________. A) weak electrolyte B) semiconductor C) strong electrolyte D) nonelectrolyte E) nonconductor 2) A solution with the same osmotic pressure as the blood is ________. A) isotonic to the blood B) molar to the blood C) hypotonic to the blood D) nontonic to the blood E) hypertonic to the
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increasing periods of time. - Method to test hypothesis: The hypothesis can be tested by first determining the amount of ascorbic acid needed to decolourize 3mL of DCPIP solution‚ and calculating the concentration of Vitamin C in the ascorbic acid. Next‚ determine the amount of fruit juice needed to decolourize 3mL of DCPIP solution‚ and calculating the concentration of Vitamin C in the fruit juice initially. Then‚ heat a few test tubes of fruit juice in a boiling water bath for different periods of
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------------------------------------------------- Spectrophotometry has various uses in different fields of science. It can be used in obtaining the concentration and the identity of a solution. In order to test that‚ an experiment was made using the basic concepts of spectrophotometry. This experiment used the properties of light and how much of it is absorbed by the unknown solution. In relation to this method was the so called principle‚ the Beer-Lambert’s Law‚ which was used in getting the relationship of the absorbance and the
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This is termed the hydrotropic effect. Examples of hydrotropic salts include ETH maleate‚ succinate‚ and oxalate2. The hydrotropic effect is achieved by adding an organic salt which will increase the saturation solubility of a drug in an aqueous solution by increasing hydrogen bonding. The mechanism of hydrotropism involves weak interactions between the hydrotropic agent and the insoluble drug. This method closely resembles complexation. Commonly used hydrotropic substances include caffeine‚ sorbitol
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Product Constant Q: Write the equilibrium equation for a saturated solution of the following salts and the corresponding solubility product expressions. a) BaSO4 (s) b) MgF2 (s) c) Ag2S (s) d) Cu(IO3)2 (s) [ ][ [ [ A: [ ( Q: ) ] ][ ][ ] ] What is the equilibrium concentration of Cd2+ ions in a saturated solution made by shaking CdS(s) with water? Ksp = 6.0x10-27 for CdS. [ A: [ Q: ][ ] ][ ] ; ][ ] √ √ A solution in equilibrium with a precipitate of AgCl was found to contain 3.4x10-6M
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test APPARATUS AND MATERIALS: 4% stock solution of glucose‚ water‚ 6 test tubes‚ ruler‚ water bath‚ solution of unknown concentration (Sample A)‚ Benedict’s reagent METHOD: 1. Solutions of different concentration were made from the stock solution and placed in test tubes. 2. All test tubes were labeled appropriately‚ according to table below‚ and Benedict’s test was carried out on the various dilutions for 5 minutes. 3. The colours of the solution were observed and heights of precipitate
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will decrease as the salt in the solution increases. This is because the solution around the potato will draw the water from the potato‚ causing it to decrease in size. Method: To begin this experiment‚ 1½ teaspoons of salt was added to a beaker containing 100 mL of distilled water. This was the 7% solution. 50 mL of this solution was poured into a second beaker and 50 mL of distilled water was added. This produced the 3.5% solution. 50 mL of this solution was added to a third beaker‚ then
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* In a solution‚ the positive hydrogen side of water is attracted to the negative parts if the compound it is dissolving while the negative oxygen is attracted to the positive parts * “Like dissolves like” – describes whether one substance will dissolve in another. Water for example can’t dissolve nonpolar substances Concentrations on Solutions * Solvent: The liquid in which a solute is dissolved to form a solution. * Solute: The minor component in a solution‚ dissolved
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