Geo Test #1eCalculators PermittedName________________________ Time: 70 minutes100 points 1) Solve the system of simultaneous linear equations . 2)Find the equation of the line that is perpendicular to the line with equation and that passes through the point with coordinates (2‚ 1). What is the perpendicular distance from the origin to the line with equation ? 3) Solve the inequality 2 4)Consider the vectors a = i − j + k‚ b = i + 2 j + 4k and c = 2i − 5 j − k. (a)Given that c = ma
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: the study of a chemical reaction experiment 19 kinetics : the study of a chemical reaction Results Part A [I-] / mol dm-3 | [S2O82-] / mol dm-3 | [S2O32-] / mol dm-3 | Time /s | Rate of I2 formation / mol dm-3 s-1 | 0.2 | 0.2 | 0.01 | 1.25 | 0.1600 | 0.2 | 0.15 | 0.01 | 13.37 | 0.0150 | 0.2 | 0.10 | 0.01 | 26.00 | 0.0077 | 0.2 | 0.05 | 0.01 | 66.25 | 0.00075 | Part B [I-] / mol dm-3 | [S2O82-] / mol dm-3 | [S2O32-] / mol dm-3 | Time /s | Rate of I2 formation / mol dm-3 | 0
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of laboratory assignment 3 was to measure the rate at which a chemical reaction takes place. For the purpose of this lab we measured the rate a balanced oxidation/reduction reaction between iodine‚ hydrogen‚ and bromate ion occurs. The above reaction occurs slowly so we used a coupled iodine clock reaction to measure the rate of the oxidation/reduction reaction because it occurs much faster but is still dependent upon the other reaction. To accomplish this‚ two mixtures were prepared in separate
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financial position of Smith construction as of May 31. During May the following transactions occurred: 1-May Smith received $10‚000 as an inheritance and used it to buy stock in the company. 7-May Smith paid his accounts payable balance. 15-May Smith replaced some windows for a client and received $5‚000 cash for his services 17-May Smith collected $1‚200 from a customer for a job
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Abstract This experiment is to study the effect of temperature on the rate of reaction between potassium permanganate with oxalic acid. We used 2cm3 of 0.02M potassium permanganate and 4cm3 of 1M sulphuric acid into a test tube. In another test tube‚ we placed 2cm3 of oxalic acid. We placed the test tubes in a water bath at 40‚ 45‚ 50‚ 55 and 60oC respectively. When the solutions have attained these temperatures pour the oxalic acid into the acidified permanganate solution and recorded the time
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By rearranging this equation and taking logs we can form “log(Par/(1-Par))=[A]-logKA” from which we can see that plotting log (Par/1-Par)) against log [A] forms what is known as a hill plot‚ which consists of a straight line with a slope of unity. If the relationship between drug concentration and tissue response is directly proportional‚ the relationship between occupancy and response can be denoted as Y/100= Par which can be substituted into the previous equation to provide log(y/(100-y))=log[A]-log[KA]
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Lab #4: Aqueous Reactions Introduction: In this experiment we studied the two different types of aqueous chemical reactions‚ double replacement and single replacement. In a double replacement reaction one or both of the products is an insoluble ionic compound or otherwise known as a precipitate; or a non-electrolyte; or a gas. In a single replacement reaction there is typically a metal and an ionic compound consisting of a metal cation and a non-meatl anion. Singel replacement ractions occur when
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Diagonally Implicit Block Backward Differentiation Formulas for Solving Ordinary Differential Equations 1.0 Introduction In mathematics‚ if y is a function of x‚ then an equation that involves x‚ y and one or more derivatives of y with respect to x is called an ordinary differential equation (ODE). The ODEs which do not have additive solutions are non-linear‚ and finding the solutions is much more sophisticated because it is rarely possible to represent them by elementary function in close
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7 Ordinary Differential Equations Matlab has several different functions for the numerical solution of ordinary differential equations. This chapter describes the simplest of these functions and then compares all of the functions for efficiency‚ accuracy‚ and special features. Stiffness is a subtle concept that plays an important role in these comparisons. 7.1 Integrating Differential Equations The initial value problem for an ordinary differential equation involves finding a function
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quadratic equation is an equation that has a second-degree term and no higher terms. A second-degree term is a variable raised to the second power‚ like x2. When you graph a quadratic equation‚ you get a parabola‚ and the solutions to the quadratic equation represent where the parabola crosses the x-axis. A quadratic equation can be written in the form: quadratic equation‚ where a‚ b‚ and c are numbers (a ≠0)‚ and x is the variable. x is a solution (or a root) if it satisfies the equation ax2 +
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