"Standardization of sodium thiosulphate" Essays and Research Papers

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    oxygen in the water. If acid isn’t added the solution will quickly start to turn yellow due to formation of MnO2. If this happens anyway‚ add some more sulphuric acid to reverse the process. The solution should be clear with a slight green tinge. Chapter 15 – Volumetric analysis (Redox titrations) To prepare a standard solution of ammonium iron sulphate and use this solution to standardise a solution of potassium permanganate. Potassium permanganate (KMnO 4 ) is a powerful oxidizing agent and is

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    acidified ascorbic acid to form colourless iodide ion: ← Equation I The excess iodine is then back titrated by standard sodium thiosulphate solution‚ by using a burette and starch solution (used as end point indicator) Similarly‚ iodine can also be decolourized by thiosulphate ion: 2S2O32- + I2 → S4O62- + 2I- ← Equation II Any iodine present will react

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    trivalent state. 8OH-(aq) + 4Mn2+(aq) + 2H2O(l) --> 4Mn(OH)3(s) The analysis is completed by titrating the iodine produced from potassium iodide by manganese(III) hydroxide. 2Mn(OH)3(s) + 2I-(aq) + 6 H+(aq) --> 2Mn2+(aq) + I2(aq) + 6H2O(l) Sodium thiosulphate is used as the titrant. Success of the method is critically dependent upon the manner in which the sample is manipulated. At all stages‚ every method must be made to assure that oxygen is neither introduced to nor lost from the sample

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    "CHEMISTRY REVIEW" PROJECT PAGES This Project Page first appeared in the November 1996 issue of Chemistry Review‚ Volume 6‚ Number 2‚ Pages 14 and 15. Chemistry Review is published four times during the academic year by Philip Allan Updates and is a journal for post-16 students. It contains a variety of interesting and colourful articles aimed at 16-19 year-olds taking mainly AS and A2 courses in chemistry. NOTE: Project Page is designed to help you think about your investigation. It is not

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    UNIVERSITI MALAYSIA SABAH SCHOOL OF FOOD SCIENCE & NUTRITION LABORATORY REPORT NT20903 FOOD CHEMISTRY AND BIOCHEMISTRY Determination of free fatty acid(FFA) and iodine value (IV)in oil LECTURER NAME : MOHD NAZRI BIN ABDUL RAHMAN LAB SESSION : 3 OCTOBER 2011 (GROUP 4‚ MONDAY) Group Member Title: Determination of free fatty acid (FFA) in oil and determination of iodine value (IV) in oil Introduction Acid value or free fatty acid content is an important characteristic commonly

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    Antacid tablets are used to relieve heartburn and neutralise stomach acid. Planning Aim To determine how the surface area of the tablets affects the rate of the reaction. To determine which form of tablets gives the biggest surface area resulting in the fastest reaction rate. Investigation question: What is the relationship between the total surface area of the tablets and the rate of the reaction? Hypothesis: The rate of reaction will be the fastest when the tablets crushed into powder

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    Vibrio spp. The growth of intestinal flora other than Vibrio spp. is prevented by the high pH (8.5-9.5) of TCBS. TCBS agar consist off yeast extract‚ bacteriological peptone‚ sodium thiosulphatesodium citrate‚ ox bile‚ sucrose‚ sodium chloride‚ ferric citrate‚ Bromothymol blue/ thymol blue and agar. Sodium thiosulphatesodium citrate and ox bile are the components that inhibit the growth of Gram-positive microorganisms. The disadvantage of TCBS agar is that it may not support good growth for all

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    Science Coursework-Rates of Reactions Introduction Investigating how the concentration of sodium-thiosulphate (STS) and hydrochloric acid (HCL) affects the rate of reaction in the experiment. In addition I am also checking how different variables affect my experiment and also how I can make my test more precise‚ reliable and accurate. Strategy According to my results‚ as the concentration of STS solution increased the rate of reaction of my experiment was increased. Also as the concentration

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    H2O2 + 2I - + 2H +  I2 + 2H2O If the reaction doesn’t contain Sodium Thiosulphate (Na2S2O3) then the reactants would gradually go from clear to a yellow/brown colour when the iodine appears‚ this would make the reaction hard to time accurately. When Sodium Thiosulphate is present it means there is a second very fast reaction between the iodine formed and the Thiosulphate ion: I2 + 2S2O3 2-  2I - + S4O6 2- The S2O3 2- ions consume the I2

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    In this experiment‚ the combination of hydrochloric acid and sodium thiosulphate‚ which are two aquatic solution‚ creates four substances‚ first there is sodium chloride which is a dissolved solution‚ the other one is sulfur dioxide‚ a gas‚ the there is‚ water‚ a liquid and the last one‚ Sulphur‚ is a solid. Sulphur is the focus of the experiment. Temperature

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