lowering the activation energy of this process‚ the reaction of bonding‚ or in this case breaking apart‚ is sped up. An enzyme breaks apart the substrate in the active site of the enzyme; this is where the magic happens. Substrate is what is being broken apart by the enzyme. In this case‚ the enzyme is catalase and the substrate is hydrogen peroxide‚ or 2H2O2. As the catalase and the substrate interact‚ the substrate is brought into the catalase and broken apart into water and oxygen. This process
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In my coursework I will investigate about enzymes in potatoes reacting with Hydrogen Peroxide. In particular I will investigate the effects of changing the surface area of a potato when added to Hydrogen Peroxide. This is because‚ when increasing the surface area of the potatoes it will increase the rate of reaction because there will be more surface area on which particles from the potato and the Hydrogen Peroxide will collide on‚ and with more surface area there would be more particles carrying
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chemical reactions within the body without being denatured in the processes. Enzymes can be used continually by temporary binding to a specific substrate in the active site to convert the substrate into a product that the cell needs to perform a specific function. Without the use of catalyst enzymes‚ homeostasis wouldn’t be able to occur quickly enough which can result in many bodily functions unable to work properly. The focus of this study is to measure the effects of external factors of temperature
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Data When looking at my results i can safely say that the change in HCl concentration does affect the rate of reaction with the Calcium carbonate pebbles. The relationship between the change in HCl and reaction rate can be seen in the graph and raw data table presented above. If you compare the lowest concentration with the highest concentration you’d be able to see that there is a very large contrast between their averages. The average gas production of 0.1M HCl was 0.00693 kPa/s whereas the average
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Assignment 1 UNIT 1 Question 1 (5 marks): Discuss the rate-limiting factor. Why is it important to consider when studying exercise physiology and training? Provide one example to clarify your understanding. The rate-limiting factor is the “step” that limits performances (the “slow step”). If we know the rate-limiting step in a certain physiological pathway or training situation‚ we can manipulate the factors of this step to change and increase the rate of the pathway. This will improve overall training
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us to observe the conversion of hydrogen peroxide (H2O2) into water and oxygen gas. An enzyme known as catalase facilitates this decomposition reaction. The catalase enzyme acts as catalysis‚ helping lower the energy needed to activate the reaction while the enzyme itself is not affected. Catalase is a digestive enzyme used to break down hydrogen peroxide‚ which is a normal byproduct of cellular respiration. The reaction could take place without the help of catalase‚ but it would happen a lot more
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[Teacher] [Course] [Date] Catalase Lab Report An enzyme is something that helps to speed up a chemical reaction. The enzyme changes from reaction to reaction‚ but it always has the same impact. However‚ certain variables may cause the enzyme to have a more or less significant impact on the speed of each reaction. One of these variables that changes the effectiveness of an enzyme is temperature. There is an optimal functioning temperature for each enzyme in each reaction‚ depending on the desired
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The rate of reaction between sodium thiosulphate and hydrochloric acid Candidate name: Yeo Jin Kim (Kimberly Kim) Candidate number: 000791-021 Teacher: Yitao Duan 1.0 Aim The aim of this experiment is to investigate the changing of concentration effect the rate of reaction between sodium thiosulphate and hydrochloride. 2.1 Chemical Equation 2.0 Raw data 3.2 Qualitative Data 2.1.1 Before the experiment Substance | Color | State | Smell | Hydrochloride (HCl) | Colorless
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O2 production and reaction velocity increased with increasing catalase concentration‚ however‚ the 33% percent catalase concentration showed a drop of 0.175 mL O2/s compared to the 25% catalase concentration (figure 1.2). The velocity of 25% catalase was 0.275 mL/s‚ 33% was 0.1 mL/s‚ 50% was 0.435 mL/s‚ and 75% catalase was 0.575 mL/s (figure 1.1). The 50% catalase concentration produced the most O2 overall however the 75% catalase concentration had the fastest initial reaction velocity. Experiment
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to investigate the effect of substrate concentration Hydrogen Peroxide H O (in %) on the rate of reaction of the enzyme catalase (in 1/mean time). Prediction: As the substrate concentration (hydrogen peroxide) in % increases the rate of reaction in 1/mean rate increases until the solution becomes saturated with the substrate hydrogen peroxide. When this saturation point is reached‚ then adding extra substrate will make no difference. The rate steadily increases when more substrate is added because
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