A PROJECT REPORT ON “Market analysis of jeans industry in surat” In Partial Fulfillment Of The Degree Requirements Towards The Bachelor in Business Administration Submitted By: Ritu Mishra Roll no -28 (Marketing) Sem -6th Submitted To: Mr.Ashish Sukhadiya SURAT 2009-2010 ACKNOWLEDGEMENT This report is written in accordance with the Bachelor of Business Administration course prescribed by Veer Narmad South Gujarat
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Determination of Equilibrium Constants Introduction Bromothymol blue is an indicator for many acid-base titrations. When adding different solutions within the indicator it is to react and change colors‚ in this experiment the different colors were blue‚ green‚ and yellow. In the following experiment‚ obtaining the absorbance levels for each one makes it possible to calculate the equilibrium constant. Materials and Methods For this specific experiment there are a few materials that are crucial
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Indian two-wheeler industry has seen spectacular growth. The country stands next to China and Japan in terms of production and sales respectively. Majority of Indians‚ especially the youngsters prefer motorbikes rather than cars. Capturing a large share in the two-wheeler industry‚ bikes and scooters cover a major segment. Bikes are considered to be the favorite among the youth generation‚ as they help in easy commutation. Large variety of two wheelers are available in the market‚ known for their
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CHM 096 TUTORIAL 2 (Chemical Equilibrium) Jan 2013 1. Write the equilibrium constant expression‚ Kc‚ for each of the following reactions: a) b) c) d) e) f) 2NO(g) + O2(g) ⇄ 2NO2(g) The decomposition of solid potassium chlorate to solid potassium chloride and oxygen gas. 4HCl(g) + O2(g) ⇄ 2H2O(g) + 2Cl2(g) 2NO2(g) + 7H2(g) ⇄ 4H2O(l) + 2NH3(g) H2O(g) + C(s) ⇄ CO(g) + H2(g) The reduction of solid copper (II) oxide with hydrogen gas to produce copper metal and water at o 500 C. 2H2(g) + O2(g)
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Introduction: Chemical equilibrium is when the concentrations of the reactants and products have reached a state where reactions occurring in one direction are at the same rate of reactions occurring in the opposite direction. This process‚ called dynamic equilibrium‚ is the main subject of Le Chatelier’s Principle. Le Chatelier pointed out that if a system at equilibrium is subjected to a stress that momentarily causes the system to be not in equilibrium‚ a spontaneous change will occur to
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DISCUSSION Chemical equilibrium and its different applications were studied in this experiment. The Le Chatelier’s principle‚ which is the main principle behind chemical equilibrium‚ states that‚ “If an external stress is applied to a system at equilibrium‚ the system adjusts in such a way that the stree is partially offset as the system reaches a new equilibrium position.”[1] The “stress” can be a change in concentration‚ volume‚ pressure‚ or temperature that disturbs the equilibrium
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at equilibrium 2. To observe shifts in equilibrium concentrations as stresses are applied to the systems. 3. To observe a shift in equilibrium concentrations associated with changes in temperature. 4. To explain the observations obtained by applying Le Chatelier’s principle. Materials Refer to page 209 of Heath Chemistry Laboratory Experiments. Procedure Refer to pages 209 – 211 of Heath Chemistry Laboratory Experiments. Data and Observations Part I: Equilibrium Involving
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Physics lab:9 Equilibrium of parallel force 11/09/2012 By: Camilo Salazar Jillian Ellis Purpose: To understand the conditions need for a rigid body to be in equilibrium when there are forces acting on the body from different sides. Theory: When force is applied on a rigid body for example a ruler it can either be in equilibrium or it can be unbalance. When the force is unbalance what would happen is this motion the body can be either translational or rotational. “A body in translational
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07.04 Equilibrium: Lab Report Equilibrium Lab Report Before You Begin: You may either copy and paste this document into a word processing program of your choice or print this page. Data and Observations: Insert data tables for each part of the lab (Part I‚ Part II‚ and Part III). Part I Round Reactants Products 1 25 15 2 19 21 3 17 23 4 16 24 5 16 24 6 16 24 7 16 24 8 16 24 9 16 24 10 16 24 25+19+17+16(7)=173 15+21+23+24(7)=227 Product/Reactants==227/213=1
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The First and Second Conditions for Equilibrium The first condition for equilibrium: The second condition for equilibrium: • • ΣF = 0 ΣΓ = 0 • In when both of these conditions are satisfied in static systems all forces and torques sum to zero. In problems where the first and second conditions of equilibrium are satisfied‚ the best strategy is to create FBD’s for both the first and second conditions‚ derive equations based on these FBD’s and then see what useful information may be gleaned from
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