26 sec 2.05 sec 3.65 sec Classification Good Excellent Good CALCULATIONS Average velocity (10 – 20 m) = (10 m)/(time at 20 m- time at 10 m) = (10 m )/(3.65 sec〖- 2.05 sec〗 ) = 6.25 m/s Average velocity (0 – 5 m) = (5 m)/(time at 5 m) = (5 m )/(1.26 sec) = 3.97 m/s Average acceleration (0 – 5 m) = (Velocity at 5 m)/(time at 5 m)
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ball dropped from the top of the CN Tower is given by h(t)= -4.9t2+450‚ where t is time elapsed in seconds. (a) Draw the graph of h with respect to time (b) Find the average velocity for the first 2 seconds after the ball was dropped h(0)=(0‚450)‚ h(2)=(2‚430.4) = (430.4-450)/(2-0) = -9.8m/s √ (c) Find the average velocity for the following time intervals (1) 1 ≤ t ≤ 4 h(1)=(1‚445.1) h(4)=(4‚371.6) = (371.6-445.1)/(4-1) = -24.5m/s √ (2) 1 ≤ t ≤ 2 h(1)=(1‚445.1) h(2)=(2‚430.4) = (430.4-445.1)/(2-1)
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1. A football field is 120 yd long and 50 yd wide. What is the area of the football field‚ in m2‚ if 1 yd = 91.44 cm? (Points : 5) [pic]5.0 x 103 m2 [pic]2.4 x 103 m2 [pic]4.2 x 103 m2 [pic]3.7 x 103 m2 | | |2. Suppose that an object travels from one point in space to another. Make a comparison between the displacement and the distance| |traveled. (Points : 5) |
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force acting on it and takes place in the direction of the applied force. The mathematical expression of Newton’s second law of motion is F (mv-mu)/t F m(v-u)/t F ma Where m is the mass of a body‚ v is the final velocity of the body‚ u is the initial velocity of the body and t is
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and the hanging mass. 6. Connect data logger to your laptop and to the two light gates. 7. Put 500g (5 x 100g) on the trolley. Use sticky tape to hold it on if needed. 8. Click the “start” button and let go of the trolley. 9. Record the initial velocity‚
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during this inattentive period? [66.7 m] 2. A horse canters away from its trainer in a straight line‚ moving 160 m away in 17.0 s. It then turns abruptly and gallops halfway back in 6.8 s. Calculate (a) its average speed and (b) its average velocity for the entire trip‚ using “away from the trainer” as the positive direction. [10.1 m/s; 3.36 m/s] 3. A car traveling 90 km/h is 100 m behind a truck traveling 75 km/h. How long will it take the car to reach the truck? [24.0 s] 4. An
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Name Period Date Momentum – Ch. 12 Part A – Momentum 1) A moving car has momentum. If it moves twice as fast‚ its momentum is ____________ as much. 2) Two cars‚ one twice as heavy as the other‚ move down a hill at the same speed. Compared to the lighter car‚ the momentum of the heavier car is ____________ as much. 3) A steel ball whose mass is 2.0 kg is rolling at a rate of 2.8 m/s. What is its momentum? |given |work
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The attenuation constant of a zero dissipationless line is given by………………. ∝=0 ∝=1 ∝=-1 ∝≠0 The phase constant of a zero dissipationless line is given by………………. β=0 β=1 β=ω√LC β=ω√RC The velocity of propagation in zero dissipationless line is given by………………. v=1/√LC v=1/√4LC v=√(L/C) v=2√(L/C) The standing wave ratio is given by………………. SWR=1/|〖E_MAX E〗_MIN | SWR=√(|E_MAX |/|E_MIN | ) SWR=|E_MAX |/|E_MIN | SWR=4|E_MAX |/|E_MIN | The standing wave ratio is given by………………. In
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Chapter 18‚ it perform the relative motion analysis of a point on the body which states the calculation of the motion of an object with regard to some other moving object. Thus‚ the motion is not calculated with reference to the earth‚ but is the velocity of the object in reference to the other moving object as if it were in a static
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POLYNOMIALS IN DAILY LIFE Polynomials are a combination of several terms that can be added‚ subtracted or multiplied but not divided. While polynomials are in sophisticated applications‚ they also have many uses in everyday life. Although many of us don’t realize it‚ people in all sorts of professions use polynomials every day. The most obvious of these are mathematicians‚ but they can also be used in fields ranging from construction to meteorology. Polynomials in Construction and Material
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