Experiment 4 Projectile Motion Introduction We examined projectile motion by observing a ball rolling down then leaving the ramp‚ thus becoming a projectile with a horizontal initial velocity. We measured the horizontal initial velocity using the photogate and computer. We measured the horizontal and vertical distances that the projectile traveled from the end of the ramp to when it hit the floor my using a meter stick to measure Experimental Set-Up In our experiment‚ we used the following:
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PROJECT IN PHYSICS (Problems Compilation) Submitted by: KIMBERLY L. RECARE IV- HOPE Submitted to: CECIL SIERVO PROBLEM SOLVING 1. To go from your house to a nearby store‚ you must walk 4 m east and then 20 m 30° north of east. What is your displacement? Use polygon method and parallelogram method. Check you result by sine law and cosine law. COSINE LAW SINE LAW R²= a² + b² - 2 AB
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Introduction Rectilinear Motion: Position‚ Velocity & Acceleration Determination of the Motion of a Particle Sample Problem 11.2 Sample Problem 11.3 Uniform Rectilinear-Motion Uniformly Accelerated RectilinearMotion Motion of Several Particles: Relative Motion Sample Problem 11.4 Motion of Several Particles: Dependent Motion Sample Problem 11.5 Graphical Solution of RectilinearMotion Problems Other Graphical Methods Curvilinear Motion: Position‚ Velocity & Acceleration Derivatives of Vector Functions
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path. In order to find the object’s velocity‚ one needs to find its displacement vector over the specific time interval. The change in position‚ or the object’s displacement‚ is represented by the change in r. Also‚ remember that a position vector is a displacement vector with its tail at the origin. It is already known that the average velocity of a moving object is ᐃd/ ᐃt‚ so for an object in circular motion‚ the equation is ᐃr/ ᐃt. IN other words the velocity vector has the same direction as the
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straightforward mathematical relationships. These mathematical relationships are a recurring concept in the fields of Kinematics and Dynamics which focuses on ways in which objects/matter move whilst evaluating behaviours like displacement‚ acceleration and velocity (Wise Geek‚ 03-13). Kinematics derives its name from the Greek word for “motion” (kinema) (Sparknotes‚ 2011). This field is centred under a sub branch of mechanics which deals with pure motion‚ without reference/implication to the forces and masses
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temperature‚ angle‚ area‚ speed‚ distance‚ volume and density are examples of scalar quantities. * Vector Quantities: Quantities that require both magnitudes and direction to specify them are called vector quantities or vectors. Displacement‚ velocity‚ force‚ momentum‚ weight etc. are the examples of vectors. Q5: A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds? Answer: As
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Physics 111 N Final Exam Please answer all problems on the blank paper provided. Clearly print your name and student ID on every sheet you use. Please hand in your formula sheet along with your answers Course ID : 10076 Prof. Jozef Dudek Unless instructed otherwise‚ you must show working‚ or explain how you came to your answer for all questions. You cannot get full credit on a question unless working is shown. Partial credit will be awarded for working which is partially correct
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related basic laws. The same considerations will help you understand the motions of Earth satellites‚ of which there is one natural one and many artificial ones. Angular Measure Motion is described as a time rate of change of position. Angular velocity involves a time rate of change of position‚ which is expressed by an angle. It is important to be able to relate the angular description of circular motion to the orbital or tangential description‚ that is‚ to relate the angular displacement to
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Diameter 1 2 3 4 5 6 Average Time (s) Velocity m/sec 2mm 1.62 1.54 1.60 1.63 1.55 1.78 1.62 0.155 3mm 1.10 1.15 1.11 1.19 1.20 0.97 1.12 0.225 4mm 0.89 0.86 0.84 0.82 0.81 0.88 0.85 0.296 Six trials were conducted to measure the time for the ball to reach to the bottom of the container. The following is a sample calculation done for 2 mm diameter. The Average time for (2mm) ball =(1.62+1.54+1.60+1.63+1.55+1.78)/6=1.62 sec Terminal Velocity = Distance/(Time (avarge) ) = (0.252
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Problems and Solutions in Elementary Physics by C. Bond The following sections include solutions to a number of my favorite problems in elementary physics. Some of the solutions bear aspects resembling that of a magician pulling a rabbit out of a hat. Others simply demonstrate the remarkable power of a few seminal concepts to reveal the inner workings of the real world. Most of the problems yield to solution strategies other than the ones shown‚ but these represent my own preference. At some point
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