calculations‚ show clearly how you work out your answer. (JUN1443651H01) WMP/Jun14/4365/1H/E6w 4365/1H 2 Formulae Sheet: Higher Tier a 1 Area of trapezium = – (a + b)h h 2 b Volume of prism = area of cross section × length crosssection h lengt r 4 πr3 Volume of sphere = – 3 Surface area of sphere = 4 π r 2 1 Volume of cone = – π r2h l 3 h Curved surface area of cone = π rl r In any triangle ABC Area of triangle = 1 – 2 C ab sin C a b b a c Sine rule ––––– = ––––– = ––––– sin A
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Formulae – Higher Tier You must not write on this formulae page. Anything you write on this formulae page will gain NO credit. 1 Area of trapezium = 2 (a + b)h a cross section length Volume of a prism = area of cross section × length h b Volume of sphere = 4 r 3 3 Surface area of sphere = 4 r 2 r Volume of cone = 1 r 2h 3 Curved surface area of cone = rl l r h In any triangle ABC b A c a sin A b sin B C a B The Quadratic Equation The solutions of ax 2 + bx + c = 0 where
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6 7 8 Area of trapezium = 1 × sum of parallel sides × height 2 Circumference of circle = πd = 2πr 2 Area of circle = πr Curved surface area of cylinder = 2πrh 2 Surface area of sphere = 4πr Volume of right prism = cross sectional area × length Volume of cylinder = πr 2h Volume of cone = 1 2 πr h 3 4 3 πr 3 1 × base area ×
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9/29/2014 Data TABLE 4 DENSITY OF SALT SOLUTIONS-INDIVIDUAL GROUP’S RESULTS Concentration (%) Mass (g) Volume (mL) Density (g/mL) 0 9.9522 10.00 0.9952 4 10.1291 10.00 1.013 8 10.5233 10.00 1.052 12 10.7487 10.00 1.075 16 11.0297 10.00 1.103 Unknown # 10.6234 10.00 1.062 Calculations 1. Show all density calculations. Density : Mass / Volume 9.9522 / 10.00 = 0.9952 g/ml 10.1291 / 10.00 = 1.013 g/ml 10.5233 / 10.00 = 1.052 g/ml 10.7487 / 10.00
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*P42059A0128* 6/7/4/ GCSE Mathematics 1MA0 Formulae: Higher Tier You must not write on this formulae page. Anything you write on this formulae page will gain NO credit. Volume of prism = area of cross section × length Area of trapezium = 1 (a + b)h 2 a cross section lengt h h b Volume of sphere = 4 3 U 3 Volume of cone = 1 2 Uh 3 Surface area of sphere = 4 U 2 r Curved surface area of cone = UO l r h In any triangle ABC C b A c a B The Quadratic Equation
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mass of an object and its volume. Sometimes density can be easy to sense. If two objects have exactly the same shape and size‚ the denser one may feel heavier. If their densities are close together‚ it can be hard to tell the difference. It gets really tough if you are dealing with materials that have very different sizes or very different shapes. The only way to decide the density of an object is to measure its mass and its volume‚ then divide. Ex. Density= Mass/Volume Procedure: For Aluminum:
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the relationship between pressure exerted and volume of a gas. Materials: Lab simulation. Procedure: 1. Open animation file 2. Modify the number of books that press down on the piston starting from 0 books and increasing by 1 each time until 19 books. 3. Record the pressure (# of books) and volume for 19 different pressure values. 4. Record those values in a table 5. Using the data‚ plot a graph of pressure in function of volume. Conclusion: In this lab‚ the results show that
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Table 2: Density based on the displacement of water Trial 1 Trial 2 Trial 3 Units Mass of sample 70.5467 70.5465 70.5466 g Final volume of the water in the buret (Vf) 29.83 13.11 25.51 ml Initial volume of the water in the buret (Vo) 14.62 2.61 13.18 ml Volume of the water dispensed from the buret (Vb=Vf-Vo) 15.21 10.50 12.33 ml Volume of water level on graduated cylinder:
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Temperature of ice water 11°C Volume of water in 10-mL graduated cylinder 10 ML Volume of water in 50-mL graduated cylinder 10 ML Data Table 2 Measurement Data Inside diameter of 50-mL graduated cylinder 2.5 cm Height of 50-mL graduated cylinder 9.5 cm Water temperature 22°C Initial volume of water in 50-mL graduated cylinder 10.0 mL Mass of water in the 50-mL graduated cylinder (remember‚ 1 g of water weights 1 mL since its density is 1 g/mL) 10 g Volume of water and aluminum shot in
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remains the same no matter how much of it is present. The density is an intensive property because mass and volume changes at the same rate. Introduction: This experiment was designed to determine if density is an intensive or extensive property. The density of an object is found by dividing its mass by its volume. The volume of a regular shaped object can be measured with a ruler. The volume of an irregular shaped object can be measured by putting it in water and figuring out the displacement the
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