78 D 4 $635.52 1). The yield to maturity on bond A is . a. 10% b. 11% c. 12% d. 14% e. none of the above 2). The yield to maturity on bond C is . a. 10% b. 11% c. 12% d. 14% e. none of the above 3). A coupon bond that pays interest annually is selling at par value of $1‚000‚ matures in 5 years‚ and has a coupon rate of 9%. The yield to maturity on this bond is a. 6.00% b. 8.33% c. 9.00% d. 45
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Mass of filter paper and dry calcium carbonate __1.7__g Net mass of the dry calcium carbonate ___0.7_g (This is the actual yield) Step 11: Show the calculation of the theoretical yield of calcium carbonate. .0068 mol of CaCO3 *100.06 g CaCO3/1mol of CaCO3 =.6804 g of CaCO3 Show the calculation of the percent yield. (Actual yield/theoretical yield)*100 = (.7/.68)*100 =102% Conclusion: The objectives of this experiment were to use stoichiometry as a method to predict
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to complete. OBJECTIVE 1. Predict the amount of product produced in a precipitation reaction using stoichiometry 2. Accurately measure the reactants and products of the reaction 3. Determine the actual and theoretical yield 4. Calculate percent yield PROCEDURE Please complete the entire experiment as instructed in the lab manual except for any modifications noted below. Fill out the report below‚ insert your digital photograph(s) into the report‚ and submit it me electronically
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evaporated 1.00 g of sodium carbonate and 1.00 g of lead II nitrate was given to start the lab out with. To calculate the percent yield of lead II carbonate‚ the limiting reactant must be identified first. 1.00 g Na2CO3 x 1 mole106 g = 0.00943 mole Na2CO3 1.00 g Pb(NO3)2 x 1 mole331 g = .00302 mole Pb(NO3)2 Limiting reactant: lead II nitrate Next‚ the theoretical yield of lead II
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Preparation and SN1 Reactivity of 2-Bromobutane Whitney Bellido Department of Chemistry‚ Illinois State University‚ Normal‚ IL 61790-4160 Submitted: April 4th‚ 2013 Introduction The overall goal of this experiment is to understand and be familiar of SN1 reactivity. We also learned how to prepare 2-Bromobutane by learning how to distill and extract this product from its organic layer. Finally‚ another goal was to specifically understand the relative reactivity of alkyl halides under SN1 conditions
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turned blue - Postlab Questions 1. Whas is the theoretical yield of casein based on the table of Milk Composition Analysis? 3.3 % 2. What is your percent yield? 3.2g/3.9g x 100= 82% 3. Why might your percent yield be lower than expected? More fat has a decrease in protein which would cause a lower percent yield. 4. Why might your percent yield be higher than expected? Less fat causes an increase in protein‚ thus giving a higher percent yield. 5. In the precipitation of casein‚ why is it important
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Data Collection and Processing Aspect One -2.00grams of Sr(NO3)2 used -2.00grams of CuSO4 -Reactants: Sr(NO3)2 and CuSO4 Trial Mass of Beaker (g) Mass of Beaker with Sr(NO3)2 (g) Mass of Beaker (g) Mass of Beaker and CuSO4 (g) Mass of Filter Paper (g) Mass of Filter Paper and Contents (g) 1 111.08±0.01 113.08±0.01 111.1±0.01 113.1±0.01 1.28±0.01 2.93±0.01 2 111.1±0.01 113.1±0.01 111.23±0.01 113.23±0.01 1.27±0.01 2.98±0.01 3 111.26±0.01 113.26±0.01 111.09±0.01 113.09±0.01 1.27±0.01
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years has a yield of 6%. A 10-year corporate bond has a yield of 9%. Assume that the liquidity premium on the corporate bond is 0.5%. What is the default risk premium on the corporate bond? Maturity = 10 years rtbond = 6% rcbond = 9% liquidity premium = 0.5% rd= r* + IP + DRP + LP + MRP Default Risk Premium (DRP) = 9% - 6% + 0.5% = 2.5% (5-7) Renfro Rentals has issued bonds that have a 10% coupon rate‚ payable semiannually. The bonds mature in 8 years‚ have a face value of $1‚000‚ and a yield to maturity
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Density of Bromine = 3.103 g/ml[2] Mass of Bromine = (0.25ml) X (3.103g/ml) = 0.78g Molar mass of Bromine = 79.9g/mol[2] Number of moles of bromine = (0.78g) / (79.9g/mol) = 0‚0097 mols Acetanilide is the limiting reagent -To find the heoretical yield of p-bromoacetanilide: Number of moles of p-bromoacetanilide =0‚0049 mols Molar
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acid (148.16g/mol) 2.5g/148.16g/mol=0.01687mol Stoichiometry ratio: 1:1 ratio Theoretical yield: Since 0.01687 moles of trans-cinnamic acid therefore following the 1:1 ratio one concludes that 2‚3-dibromo-3-phenylpropanoic acid will be of 0.01687 moles Molar mass = 307.97 g/mol Mass=(307.97g/mol)(0.01687mol)=5.20g Actual yield: Percent yield=actual yield (g) / theoretical yield (g) x 100 % yield = 3.28g/5.20g x100 = 63.08% Discussion This experiment involved the addition of trans-cinnamic
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