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6.03 Calorimetry Lab

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6.03 Calorimetry Lab
With my test result, it clearly shows that the concentration of sulfuric acid is 0.05 mol/dm3 using the concentration equation, c= n/v. 25 cm3 of the volume with sodium hydroxide is equal to 0.025 dm3 by dividing a thousand with cm 3 and multiply it with 0.1 mol/ dm3 which is the concentration of sodium hydroxide. With the ratio between sulfuric acid and sodium hydroxide is 1 to 2 so, 0.0025 should be divided by 2 and 0.00125 moles of sulfuric acid is come out. Finally, using c = m/v, 0.00125 mole/0.025 dm3 and the answer for concentration of the acid is 0.05 mole/ dm3We started our experiment with the initial volume of 0 cm3 in four trial and all of the trials ended up with the final volume of 25.00cm3 All four indicators with phenolphthalein
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