Preview

6.03 Calorimetry Lab

Good Essays
Open Document
Open Document
531 Words
Grammar
Grammar
Plagiarism
Plagiarism
Writing
Writing
Score
Score
6.03 Calorimetry Lab
In the first week of the experiment, the goal was to find the moles of NaOH, as well as a 0.1 molarity, while in the second week to goal was to determine the percent KPH in the sample. The first week titrations were successful and had very similar amounts of pink, which shows the precision of the results. The best trials were in the sample trial and the second and third trials. The average molarity calculated for the first week was 0.1017 M. This very close to the 0.1 M that was supposed to be made. The standard deviation in the average molarity was 8.9710-4 M. and for the percent variation in average molarity it was 88%. The standard deviation illustrates the percision of the experiment for week one. Being that it is so low, it shows how consistent the results that were taken were. The percent variation shows the accuracy, which was below the 1% maximum. Since the results were both percise and accurate, this shows that the results are reliable …show more content…
The goal was to use the known molarity value of 0.1017 M 8.9710-4M to determine what the percent KHP was in the unknown mixture. In these trials, the colors did vary a little more than in the first week. Trials 1, 2, and 3 were used to get the most accurate results. The average mass of KHP in the sample was 30.705%, and the standard deviation of the average percent KHP was 0.58259. However, the percent variation in the average percent KHP was 1.8%. This percent variation was much higher than was expected and was only allowed because the accuracy of the experiment was very good. The actual percentage of KHP in the sample (given by the instructor) was 30.48%, while the calculated percentage was 30.705%. The percent error was 0.74%, which showed that the accuracy was very good. While our precision, which can be seen from the percent variation was not as good, which meant that the titrations were not set to similar enough colors shown by the

You May Also Find These Documents Helpful

  • Good Essays

    The results for example 2 might have been off, when titrating the solution we added too much HCl and turned the solution yellow instead of green. So instead of boiling the solution until it turned blue again, we had to boil the solution to evaporate the water. That may have thrown off the amount of NaCl that was supposed to form after the water…

    • 420 Words
    • 2 Pages
    Good Essays
  • Good Essays

    Nahco3 Hydrochloric Acid

    • 1247 Words
    • 5 Pages

    From my results I can see that the accurate result was 0.98 and our estimated was 0.1M but I rounded up my answer to 1 decimal places to see so there was not that much of a difference. Overall my experiment went well because I have followed instruction and I archived my hypothesis because I calculate that the chemical will have more concentration because it is a hydrochloric acid which will react with a methyl orange indicator solution and cause colour change from yellow to pink in my experiment I could clearly see the change of the colour. Form my results table I can see that my results were close to 0.1M which means that I have used the accurate amount of standard solution in my experiment If I was to improve my experiment I could attempt to read the burette to the bottom or top of the meniscus by doing this it might give me accurate results for my experiment. Another way of improving my experiment could be that I use volumetric pipettes for measuring.…

    • 1247 Words
    • 5 Pages
    Good Essays
  • Satisfactory Essays

    6.03 Calorimetry Lab

    • 323 Words
    • 2 Pages

    With my test result, it clearly shows that the concentration of sulfuric acid is 0.05 mol/dm3 using the concentration equation, c= n/v. 25 cm3 of the volume with sodium hydroxide is equal to 0.025 dm3 by dividing a thousand with cm 3 and multiply it with 0.1 mol/ dm3 which is the concentration of sodium hydroxide. With the ratio between sulfuric acid and sodium hydroxide is 1 to 2 so, 0.0025 should be divided by 2 and 0.00125 moles of sulfuric acid is come out. Finally, using c = m/v, 0.00125 mole/0.025 dm3 and the answer for concentration of the acid is 0.05 mole/ dm3We started our experiment with the initial volume of 0 cm3 in four trial and all of the trials ended up with the final volume of 25.00cm3 All four indicators with phenolphthalein…

    • 323 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    To begin the experiment, the unknown needs to be determined as an acid or a base by using litmus paper or a pH strip. For the rest of the experiment, if the substance is being handled, gloves and goggles must be worn. Use a clean and dry Erlenmeyer flask and weigh it. Then, some of the unknown will be measured and poured into the flask. Also way the flask and the unknown.…

    • 275 Words
    • 2 Pages
    Good Essays
  • Good Essays

    6.03 Calorimetry Lab

    • 380 Words
    • 2 Pages

    Class average for a 80 and 120 drop count was recorded to be 0.041+/- 0.005 mL/drop. If a graduated cylinder is not available there is another way of adding more of the solution. The disposable pipet can transfer 0.5mL of the solution to the chemical reaction. When comparing a 10mL graduated cylinder, a 100mL beaker, and a 50mL graduated cylinder, the most precision peace of glass wear would be the 10 mL graduated cylinder with the true volume of water (calculated), class average, and uncertainties being 9.7896 +/- 0.05mL. The 50mL graduated cylinder comes in second place with a true volume of water(calculated), class average, and uncertainties being 50.0001 +/- 0.22mL. The third peace of glassware coming in as the least accurate would be the 100 mL beaker with a true volume of water(calculated), class average, and uncertainties being 59.9999 +/- 0.82mL.…

    • 380 Words
    • 2 Pages
    Good Essays
  • Satisfactory Essays

    6.03 Calorimetry Lab

    • 199 Words
    • 1 Page

    Percent error of copper: (8.933 - 8.4) / 8.933 x 100 = 5.96% Percent error of water: (1 - 1) / 1 x 100 = 0% Conclusion - The experiment went as planned, with…

    • 199 Words
    • 1 Page
    Satisfactory Essays
  • Good Essays

    6.03 Calorimetry Lab

    • 2193 Words
    • 9 Pages

    1. The final yield of the cells can be determined by use of an automated cell counter or by use of a hemocytometer (Neubauer chamber). In our laboratory, we determine the number of purified cells in a Neubauer-improved, bright line chamber with V-slash with a depth of 0.1 mm and a counting area of 0.0025 mm2 from Marienfeld (Lauda Königshofen, Germany, PN # 0650030). 2. For determination of the final cell yield, mix a 10 µl aliquot of the purified cells (Figure 9D) with 10 µl of trypan blue solution (Figure 9E).…

    • 2193 Words
    • 9 Pages
    Good Essays
  • Powerful Essays

    MICRO BIOLOGY

    • 1277 Words
    • 6 Pages

    We used the dilution of 10-6 in the calculation to achieve the mean value against concentration as it was the most appropriate dilution…

    • 1277 Words
    • 6 Pages
    Powerful Essays
  • Powerful Essays

    Although the hypothesis was accepted, there are still possibilities of errors while conducting this experiment. Rounding off the digits of the calculations and not using the appropriate amount of sig figs could have thrown the data off. The other limitations to look at is the possible limitation of the actual equipment. While conducting the experiment, the measurements could have been off or the containers the solutions were put in could have not been dried completely. The excess of water might have caused an error in the data…

    • 2144 Words
    • 9 Pages
    Powerful Essays
  • Good Essays

    As a result, the precision of the data is lowered, and thus, becomes less reliable. One incident where this may have occurred is seen in the average shoot height calculated for the sample with 0.40% Aquasol in the first week of the experiment, where the average shoot height was lower than that of the sample with 0.25% Aquasol. Inconsistent measuring of the 0.50% Aquasol solution could also be an inconsistent error, as if more or less than 100mL of the 0.50% Aquasol was used during dilution, the formula y/100=0.50/(x+100) would have not been valid, and thus, the concentration of each Aquasol solution would have not been as assumed. The final concentration of Aquasol for each solution may have been different to that of what was expected, and hence, the shoot heights measured would have not corresponded to the assumed concentrations. This would result in unreliable data with very low precision.…

    • 1663 Words
    • 7 Pages
    Good Essays
  • Good Essays

    Naoh Synthesis Lab Report

    • 414 Words
    • 2 Pages

    The first step was to prepare 400 mL of an 0.1 M solution of NaOH. This was done by diluting from the 6 M solution that was provided. Next, 0.715g of KHP was weighed using the glazed paper and the triple beam balance. The KHP was then transferred to the 250 mL Erlenmeyer flask. Using a graduated cylinder, 50 mL of deionized water was measured and added to the flask.…

    • 414 Words
    • 2 Pages
    Good Essays
  • Good Essays

    In this lab, the percent relative average deviation can be used as an indicator of preciseness. Percent relative average deviation is a measure of how tightly clustered a set of data points is around a mean. A low percent relative average deviation indicates that the data points are tightly clustered around the mean; moreover, if the…

    • 644 Words
    • 3 Pages
    Good Essays
  • Good Essays

    Based on calculations #7 made above for solving the molecular weight, it was identified that the unknown liquid was Butanoic acid: 88.1g/mol. Since the calculated value was 83.5 g/mol, it was assumed that Butanoic acid was the only solute out of all that were listed that shared a similar value. In reference to the results and data used for calculation the molecular weight (MW) for the unknown was successfully proven to match the accepted value of 88.1 g/mol. More specifically, this was evident due to the percent error that was calculated to be approximately 94.8 %. This value significantly shows how close the value is to the actual molecular weight.…

    • 687 Words
    • 3 Pages
    Good Essays
  • Good Essays

    that ranged from 0.04% to 19.15% were calculated. This large difference in error was due to…

    • 1917 Words
    • 8 Pages
    Good Essays
  • Satisfactory Essays

    Acid Base

    • 849 Words
    • 4 Pages

    | 37.2 | 37.8 | 37.5 | C. Analysis of KHP Sample Trials | 1 | 2 | 3 | Mass of KHP sample (g) | 0.7059 | 0.7345 | 0.7189 | Final Reading NaOH (ml) | 24.5 | 24.2 | 24.8 | Initial Reading NaOH (ml) | 0 | 0 | 0 | Volume NaOH used (ml) | 24.5 | 24.2 | 24.8 | | | | |…

    • 849 Words
    • 4 Pages
    Satisfactory Essays