aromatic and aliphatic
Abstract
The aliphatic and aromatic hydrocarbon are can be differentiate by .For example,in the experiment involving aliphatic hydrocarbon which is cyclohexane that undergo the reaction with bromine water in the presence of UV light.This reaction is known as substitution reaction.The cyclohexane that react with bromine under present of UV light will change to slightly brown while the other one has no changeous which is still brown.For baeyer’s test,the alkane which is heptanes will not undergo the oxidation reaction with potassium permanganate due to saturate bond .Thus,will forming two layer will form which the solution does not mix.While on the other hand,2-pentene will react with sulphuric acid to form penta-2,3-diol.The purple color of KmnO4 will change to brown
CH3CH=CHCH2CH3 + KMnO4 (cold) ---> CH3CH2(OH)CH2(OH)CH2CH3
For the experiment between alkane and alkene that react with sulphuric acid,alkene which is 2-pentene have react and change to ethyl hydrogen sulphate.The alkane,heptanes doesn’t react as the as the sulphuric acid will act as electrophile. C5H10 + H2SO4 ==> C5H11.HSO4
For the aromatic hydrocarbon,toluene doesn’t react with bromine water. This is because Br2 is electrophilic enough to attack double and triple bonds, but not electrophilic enough to attack the pi bond system of the benzene ring of toluene.For the reaction of between toluene and aqueous potassium manganate the reaction will change the toluene to benzanoic acid and the color of potassium manganate change from purple to slight purple
Objective
To compare the reaction of aliphatic and aromatic hydrocarbon. Aliphatic compounds are hydrocarbon chains - strings of carbon atoms connected to each other with hydrogen atoms hanging off the sides of the chain.Aromatic compounds are rings - so take the chain and connect the two ends together to form a continuous loop.aliphatic compound are easier to react than aromatic.Other than that,the aliphatic compound doesn’t require high energy
The aliphatic and aromatic hydrocarbon are can be differentiate by .For example,in the experiment involving aliphatic hydrocarbon which is cyclohexane that undergo the reaction with bromine water in the presence of UV light.This reaction is known as substitution reaction.The cyclohexane that react with bromine under present of UV light will change to slightly brown while the other one has no changeous which is still brown.For baeyer’s test,the alkane which is heptanes will not undergo the oxidation reaction with potassium permanganate due to saturate bond .Thus,will forming two layer will form which the solution does not mix.While on the other hand,2-pentene will react with sulphuric acid to form penta-2,3-diol.The purple color of KmnO4 will change to brown
CH3CH=CHCH2CH3 + KMnO4 (cold) ---> CH3CH2(OH)CH2(OH)CH2CH3
For the experiment between alkane and alkene that react with sulphuric acid,alkene which is 2-pentene have react and change to ethyl hydrogen sulphate.The alkane,heptanes doesn’t react as the as the sulphuric acid will act as electrophile. C5H10 + H2SO4 ==> C5H11.HSO4
For the aromatic hydrocarbon,toluene doesn’t react with bromine water. This is because Br2 is electrophilic enough to attack double and triple bonds, but not electrophilic enough to attack the pi bond system of the benzene ring of toluene.For the reaction of between toluene and aqueous potassium manganate the reaction will change the toluene to benzanoic acid and the color of potassium manganate change from purple to slight purple
Objective
To compare the reaction of aliphatic and aromatic hydrocarbon. Aliphatic compounds are hydrocarbon chains - strings of carbon atoms connected to each other with hydrogen atoms hanging off the sides of the chain.Aromatic compounds are rings - so take the chain and connect the two ends together to form a continuous loop.aliphatic compound are easier to react than aromatic.Other than that,the aliphatic compound doesn’t require high energy