Balanced Chemical Equations

The goal for this experiment is to determine which out of the four balanced chemical equations best represent the thermal decomposition of sodium bicarbonate. The guiding question will be answered with the outcome of the sodium bicarbonates thermal decomposition and it being plugged in into the four balanced chemical equations. John Dalton atomic theory explains two fundamental laws of chemistry which are the law of conservation of mass and the law of definite proportions. The atomic theory states that a chemical reaction is simply a rearrangement of atoms and no atoms will be destroyed or any new atoms will be produced during the process. By doing the correct procedures I identified the II balanced chemical equation to have the correct thermal decomposition of sodium bicarbonate. The II balanced chemical equation was 2NaHCO3(S) > Na2CO3(s) + CO2(g) + H2O(g).
The procedure consisted of gathering measurements and observing. The first step was to gather all the necessary materials. Next we had to have the accurate measurements of the crucible with and without the substance that is Sodium bicarbonate. The Crucible had a mass of 11.53g and then 13.94g with Sodium bicarbonate. Subtracting it to find out the
the balanced chemical equation for this reaction was 2NaHCO3(S) > Na2CO3(s) + CO2(g) + H2O(g). As you can see in the tables below the decomposition of sodium bicarbonate was 1.51 grams and the solution for the second balanced equation was 1.52 grams of Sodium carbonate. The solutions gathered by other groups in the class had the same procedure I had. Looking at all the different outcomes and noticing that there was a difference in the measurements taken by groups it's obvious most had something different. No disagreements were made to the solution by my group if so they were