Baldness and Probability Distribution Table.

1. USA Today reported that 70% of the people questioned said that they watched less T.V. than they did a year ago, 22% said they watch the same amount and 8% said they watch more. Find the probability out of a randomly selected group of five that exactly three will say they watch less T.V. this year than last.
a. Not binomial.
b. N/A
c. n=5 p=0.70 q=0.30 r: (0, 3.5)
2. There are 20 m&m’s candies in a dish. 8 are brown, three red, five green and four yellow. Two candies are picked from the dish at random. What is the probability that both are red?
a. Binomial
b. P(Success) = 6/20 = 3/10
P(Failure) = 14/20 = 7/10
c. n=20 p=0.30 q=0.70 r: (0, 6)
3. A multiple choice test is given which has 10 questions. Each question has 4 choices. You did not study and have no clue as to any of the questions, so you have to randomly guess each answer. What is the probability you guess exactly 6 correctly?
a. Binomial
b. P(success) = 0.00024
P(failure) = 0.99976
c. n=10 p=0.00024 q=0.99976 r: (0, 0.0024)
4. Using the information from the previous question regarding T.V. viewing and using the Binomial Table in your text:
a. Find the probability that in a randomly selected group of 5 people, exactly three will say they watch less T.V. this year than last. p(x < 3) = 0.472
b. Find the probability that between 2 and 4 (inclusive) people will say they watched less T.V. this year than last year. p(2 < x < 4) = 0.936
c. Find the probability that at least one will say they watched less T.V. this year than last year.
P(x > 1) = 0.969

1. In Upjohn Pharmaceutical clinical trials, 60% of those men tested remained bald after using Rogain, an anti-baldness cream. The cream will be tested on 5 men who have male pattern baldness.
a. Find the probability P(r) of r successes (remaining bald) for r ranging from 0 to 5. Make a probability distribution table. r P(r)
0
0.100
1
0.087
2
0.317
3
0.663
4
0.922
5
0.500

b. What is the expected number m, of