Determining Laminar and Turbulent Flow
2203ENG ENGINEERING FLUID MECHANICS
Performed on April 12, 2013
Due date April 19, 2013
Laminar and Turbulent Flow
Experiment #6 joe blog
Table of Contents Introduction pg3 Summary pg3 Objectives pg3 Method pg4 Results pg5 Discussion. .pg6-7 References pg8 Appendix pg 9-11
Introduction
In this experiment we used water in a Venturi as this was interpretive of the characteristics of all flowing fluids. The water was conveyed through a conduit in the form of a venturi metre and a copper pipe, however, the general characteristics of fluid flow including the transition from undisturbed laminar flow to disturbed turbulent flow are exhibited by fluid flow in a pipeline transporting liquefied natural gas, a microchannel transporting hydrogen in fuel cell, and the flow of fluid over any solid surface. Thus flow of air over the ground and flow in any pipe, tube, or duct that is completely filled with flowing fluid, all display similar characteristics. (Elger. DF, Williams. CB, Crowe. CT, Roberson, 10th Edition)
Sometimes it is hard to put a finger on exactly the type of flow a fluid is moving in, this begs for an expression that numerically describes the flow. The results can be best understood by expressing the flow characteristic in terms of non-dimensionless numbers which measure the ratio of the magnitude of force associated with inertia to the forces arising from fluid viscosity which gives rise to the Reynolds number. If one were to increase a fluid’s inertia - increased mass and acceleration – relative to solid surface and holding other factors constant then Reynolds number would increase (Achela, F, 2013, Lecture Notes) . In the aid of a glass tube we were able to estimate Reynolds number judging on how well the dye mixed in with the flowing water. Also, the loss of flow pressure head along the venturi metre into the copper pipe paved the way to deduce the shear stress the water flow experienced in the long
Performed on April 12, 2013
Due date April 19, 2013
Laminar and Turbulent Flow
Experiment #6 joe blog
Table of Contents Introduction pg3 Summary pg3 Objectives pg3 Method pg4 Results pg5 Discussion. .pg6-7 References pg8 Appendix pg 9-11
Introduction
In this experiment we used water in a Venturi as this was interpretive of the characteristics of all flowing fluids. The water was conveyed through a conduit in the form of a venturi metre and a copper pipe, however, the general characteristics of fluid flow including the transition from undisturbed laminar flow to disturbed turbulent flow are exhibited by fluid flow in a pipeline transporting liquefied natural gas, a microchannel transporting hydrogen in fuel cell, and the flow of fluid over any solid surface. Thus flow of air over the ground and flow in any pipe, tube, or duct that is completely filled with flowing fluid, all display similar characteristics. (Elger. DF, Williams. CB, Crowe. CT, Roberson, 10th Edition)
Sometimes it is hard to put a finger on exactly the type of flow a fluid is moving in, this begs for an expression that numerically describes the flow. The results can be best understood by expressing the flow characteristic in terms of non-dimensionless numbers which measure the ratio of the magnitude of force associated with inertia to the forces arising from fluid viscosity which gives rise to the Reynolds number. If one were to increase a fluid’s inertia - increased mass and acceleration – relative to solid surface and holding other factors constant then Reynolds number would increase (Achela, F, 2013, Lecture Notes) . In the aid of a glass tube we were able to estimate Reynolds number judging on how well the dye mixed in with the flowing water. Also, the loss of flow pressure head along the venturi metre into the copper pipe paved the way to deduce the shear stress the water flow experienced in the long
References: Reference Achela, F, 2013, Lecture Notes, Module 4 Laminar and Turbulent Flows – Week 6, 2203 ENG Engineering Fluid Mechanics, Griffith School of Engineering, Griffith University, Australia Y = (0.0123)x^(0.5321) Q=y=0.012288*50^0.532057=0.086085 L/s