Ethanol and Overall Material Balance
ChE 101 Lab Exercise 4 05 December 2012
Materials Balance (Non-reacting Systems) THR/WRU
1. A 40-mol-% aqueous ethanol solution is to be distilled into two streams: a distillate with 98% ethanol and a side stream with 60%. 98% of the alcohol in the feed is to be recovered in these two products; only 2% goes into the bottoms. If the bottoms product contains 2% ethanol, calculate the amount of the different streams per 1000 kmol of feed stream.
Given: Recovery = 98% of ethanol in feed to distillate and side stream
Feed, F xF = 0.40
Side stream, S xS = 0.60
Distillate, D xD = 0.98
Bottoms, B xB = 0.02
Required: D, S and B
Solution:
2% of the ethanol in the feed goes to the bottoms
Overall material balance: →
Component material balance: →
System of Linear Equations with D and S unknown
2. Shown below is a flowchart of a process in which acetic acid (A) is extracted from a mixture of acetic acid and water (B) into 1-hexanol (C), a liquid immiscible with water.
R xA = 0.005 xB = 0.995
F, 400 g/min zA = 0.115 zB = 0.885
S
pureC
E
yA = 0.096 yC = 0.904
Figure 1
Calculate E, R, and S based on the given mixture feed rate F.
Given: Figure 1
Required: E, R, S
Solution:
Basis: 400 g/min F
Tie component in F and R: water (B)
Component Material Balance for acetic acid (A): →
Overall Material Balance: →
3. A simplified flowsheet for the manufacture of sugar is shown in Figure 1. Sugarcane is fed to a mill where a syrup is squeezed out, and the resulting “bagasse” contains 80% pulp. The syrup (E) containing finely divided pieces of pulp is fed to a screen which removes all the pulp and produces a clear syrup (H) containing 15% sugar and 85% water. The evaporator makes a “heavy” syrup and the crystallizer produces 1000 lb/hr of sugar crystals. a. Find the water removed in the evaporator, lb/hr. b. Find the composition of the waste stream G. c. Find the rate of feed of
Materials Balance (Non-reacting Systems) THR/WRU
1. A 40-mol-% aqueous ethanol solution is to be distilled into two streams: a distillate with 98% ethanol and a side stream with 60%. 98% of the alcohol in the feed is to be recovered in these two products; only 2% goes into the bottoms. If the bottoms product contains 2% ethanol, calculate the amount of the different streams per 1000 kmol of feed stream.
Given: Recovery = 98% of ethanol in feed to distillate and side stream
Feed, F xF = 0.40
Side stream, S xS = 0.60
Distillate, D xD = 0.98
Bottoms, B xB = 0.02
Required: D, S and B
Solution:
2% of the ethanol in the feed goes to the bottoms
Overall material balance: →
Component material balance: →
System of Linear Equations with D and S unknown
2. Shown below is a flowchart of a process in which acetic acid (A) is extracted from a mixture of acetic acid and water (B) into 1-hexanol (C), a liquid immiscible with water.
R xA = 0.005 xB = 0.995
F, 400 g/min zA = 0.115 zB = 0.885
S
pureC
E
yA = 0.096 yC = 0.904
Figure 1
Calculate E, R, and S based on the given mixture feed rate F.
Given: Figure 1
Required: E, R, S
Solution:
Basis: 400 g/min F
Tie component in F and R: water (B)
Component Material Balance for acetic acid (A): →
Overall Material Balance: →
3. A simplified flowsheet for the manufacture of sugar is shown in Figure 1. Sugarcane is fed to a mill where a syrup is squeezed out, and the resulting “bagasse” contains 80% pulp. The syrup (E) containing finely divided pieces of pulp is fed to a screen which removes all the pulp and produces a clear syrup (H) containing 15% sugar and 85% water. The evaporator makes a “heavy” syrup and the crystallizer produces 1000 lb/hr of sugar crystals. a. Find the water removed in the evaporator, lb/hr. b. Find the composition of the waste stream G. c. Find the rate of feed of