Result:
N of KMnO4-
N KMnO4 = trial 1:
M KMnO4= ((0.2492g N2C2O4 x 1000)/ (134g N2C2O4/mol))/ 36.6 ml
= 0.051 M
N KMnO4= b . M 2eq/mol x 0.051M = 0.1 N KMnO4
Trial 2
M KMnO4= ((0.2389g N2C2O4 x 1000)/ (134g N2C2O4/mol))/35.7 ml
= 0.05 M
N KMnO4= 2 eq/mol x 0.052M =0.1 N KMnO4
Trial 3
M KMnO4= ((0.2125g N2C2O4 x 1000)/ (134g N2C2O4/mol))/ 32.8ml
= 0.048M
N KMnO4= 2eq/mol x 0.048M =0.097 N
% Fe in razor blade
Post lab # 3:
3.) Other oxidizing agents are also employed for the determination of iron in an unknown sample. What is one obvious advantage of KMnO4 over