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Separation of Mixture of Solids

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Separation of Mixture of Solids
CHE 107
24 June 2013

Separation of a Mixture of Solids

Step 1: Separating out the Iron

Mass of weighing dish: 0.7g
Mass of weighing dish and mixture: 5.4g
Net mass of the original mixture: 4.7g

Mass of 10-cm square paper: 0.8g
Mass of 10-cm square paper and iron fillings: 2.0g
Net mass of iron filings: 1.2g

Step 2: Separating out the Sand

Mass of weighing dish: 0.7g
Mass of weighing dish and dry sand: 1.7g
Net mass of the dry sand: 1.0g

Step 3: Separating out the Benzoic acid

Mass of cup: 2.3g
Mass of filter paper: 0.9g
Mass of filter paper and dry benzoic acid: 1.6g
Net mass of the dry benzoic acid: 0.7g

Step 4: Separating out the salt

Mass of cup and sodium chloride: 3.3g
Net mass of dry sodium chloride: 1.0g

Data Table 1: Experiment Data
|Grams|Percent of Mixture|
Iron fillings|1.2g|30%|
Sand|1.0g|25%|
Table Salt|1.0g|25%|
Benzoic acid|0.7g|18%|
Total|3.9 g|72%|

A. In the beginning of the lab, I thought that in order to separate all of the solids that the iron would be taken out of the mixture through a magnet. I would first, placed the mixture of solids onto a piece of paper. The magnet’s force would pick up all the iron pieces. Continuing on, in order to separate the sand from the rest of the mixture I would heat the mixture with water in a beaker then would continue by pouring the heated liquid into a cup, which would leave sand at the bottom of the beaker. Lastly, to separate the benzoic acid and sodium chloride I would use a filtration system with the water drained into a cup while the benzoic acid remained on the filter, letting the sodium chloride drain with the water. I would then wait for the rest of the water to evaporate from the cup in order to obtain the weight of the sodium chloride.
B. Due to taking this class before, my producer that was assumed was almost the same as lab assignment because of doing this lab before. Due to the knowledge of the lab, there is little disadvantages/ advantages

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