Pennies Color
1st Penny Red
2nd Penny White
3rd Penny Red
1st Penny White
2nd Penny Red
3rd Penny White
2. The next day Ms. Hernandez and her twins pass another gumball machine with three colors, red, white, and blue and again her twins want the same color. The most Ms. Hernandez might have to spend is 4 cents. This is because she could get the following:
Pennies Color
1st Red
2nd White
3rd Blue
4th White
3. Seven cents is the most Mr. Hodges might have to spend to get his triplets the same color gumballs at the same three-color gumball machine as Ms. Hernandez. This is because he could get the following:
Pennies Colors
1st penny Blue
2nd penny Red
3rd penny White
4th penny White
5th penny Blue
6th penny Red
7th penny Blue
4. The next day Mr. Hodges passes a two-color (red and white) gumball machine with his triplets again, they each want the same color. The most Mr. Hodges would have to spend is 5 cents. This is because he can get the following:
Pennies Color
1st penny Red
2nd penny White
3rd penny White
4th penny Red
5th penny white
5. The formula I found to solve these problems is: [(# of colors)(of kids)]- [(#of colors)-1]= how much money they need to spend. Ex of formula for question #1 is: [(2 colors)(2 kids)]-[(2 colors)-1]= 3 cents Ex of formula for question #2 is: [(3 colors)(2 kids)]- [(3 colors)-1]= 4 cents Ex of formula for question #3 is: [(3 colors)(3kids)]-[(3 colors)-1]= 7 cents Ex of formula for question #4 is: [(2