Background Knowledge: ‘Iron tablets’ are prescribed to patients suffering from anaemia. They contain 200mg (0.200g) of iron (II) sulphate FeSO4
We are going to analyse iron tablets to find out how much Iron (II) sulphate they contain. The procedure we will use is a REDOX reaction, by oxidising the Fe2+ contained in the Iron (II) sulphate to Fe3+. We will use potassium manganite (VII) as the oxidising agent. The active part of this is the manganite ion, MnO4-1. The SO4-2 in the FeSO4 and the K+ in the KMnO4 do not react, we say they are ‘spectator’ ions and so we will ignore them.
Apparatus:
* 2 Iron tablets * Pestle & Mortar * 1M Sulphuric acid * 100cm3 Volumetric flask * Weighing scales * Dropping Pipette * Potassium Manganate (VII) – KMnO4 * Burette * 10cm3 Volumetric pipette * Conical Flask * White tile
Potassium Manganate (VII) solution
Potassium Manganate (VII) solution
Iron sulphate solution
Iron sulphate solution
Method: 1. Weigh the 2 iron tablets separately 2. Crush them firmly using the pestle and mortar until the tablets become crystals 3. Using a dropping pipette, add a few drops of sulphuric acid to the iron crystals and stir into a paste with the pestle 4. Transfer the iron solution into a volumetric flask carefully while using a funnel 5. Use the sulphuric acid to rinse out the mortar and pestle into the volumetric flask so all the Iron is collected 6. Rinse out the funnel as well 7. Add more sulphuric acid to a little before the mark, then use the dripping pipette to add the sulphuric acid up to the mark and cork it 8. Shake the volumetric flask 9. Rinse out the burette with the KMnO4 solution then fill it up to the zero mark 10. Rinse out the Volumetric pipette with the Iron Sulphate + Sulphuric acid solution 11. Use the volumetric pipette to measure out 10cm3 of the