11. Find the intervals in which f(x) = sin x + cos x ‚ o ≤ x ≤ 2 π‚ is increasing or decreasing. 12. Find the interval in which the function given by f(x)= is increasing. 13. Find the local maximum & local minimum value of function x3– 12x2 + 36x – 4 14. For the curve y = 4x3 - 2x5‚ find all the points at which the tangent passes through the origin. 15. Find the interval in which the function f(x)= 2x3 -9x2 -24x-5 is Increasing or decreasing. 16. Find the equation of the tangents
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oxygen is 1:6 The no. of mole of oxygen= 5.56x10-3 x 6 = 0.033mole Therefore‚ the theoretical oxygen demands for glucose =0.033 x (16x2) =1.067 g oxygen/g glucose CH3COONa + 2O2 2CO2 + H2O The no. of mole of sodium acetate =1/(12x2 + 16x2 + 3x1 +23)=0.012mole The ratio of sodium acetate and oxygen is 1:2 The no. of mole of oxygen=0.012 x2 = 0.024mole Therefore‚ the theoretical oxygen demands for sodium acetate =0.024 x (16x2) =0.768 g oxygen/g sodium acetate
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using interval notation. x -1 -2 -3 -4 -5 1 2 3 4 5 y -1 -2 -3 -4 -5 1 2 3 4 5 The correct answer is: domain =(−2‚ 5] range =[-3‚3} 6. Evaluating a piecewise-defined function Suppose that the function f is defined ‚ for all real numbers‚ as follows. =fx −−12x2 ≤if x−2 +x12 <−if 2<x1 3 ≥if x1 Find the following. f−4 f−2 f0 The correct answer is: =f−40 =f−2−1 =f01 7. Identifying functions from relations For each relation‚ decide whether or not it is a
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LINEAR PROGRAMMING FORMULATION PROBLEMS AND SOLUTIONS 7-14 The Electrocomp Corporation manufactures two electrical products: air conditioners and large fans. The assembly process for each is similar in that both require a certain amount of wiring and drilling. Each air conditioner takes 3 hours of wiring and 2 hours of drilling. Each fan must go through 2 hours of wiring and 1 hour of drilling. During the next production period‚ 240 hours of wiring time are available and up to 140 hours of drilling
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Answers: New GCSE Maths Edexcel Linear Homework Book Higher 2 1 Number: Using a calculator 1.1 Basic calculations and using brackets HOMEWORK 1A 1 a 195 b 300 2 a 28.08 b 48.18 3 a 24.5 b 38.3 c 326.9 d 11.3 4 14 days 5 Alfie 4.67; Becky 5.46; Chloe 6.14; Daniel 3.77 Daniel is correct. 6 75 Euros is approximately £65.79; $100 is about £67.11‚ so $100 is worth more 7 a 15.26 b 194.88 8 a 1.7 b 4.8 9 a 533.05 b 5.221096 1.2 Adding and subtracting fractions with a calculator
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share(iii) the percentage of the total amount that Breceives (5 marks) May 1990 Calculators‚ slide rules and mathematical tables must NOT be used to answer thisquestion. Show ALL steps clearly.(a) Calculate the exact value of 4⅓ - 1⅚__ 1 3/7x1⅔(3 marks)(b) Calculate the value of 0.023/0.351 giving your answer correct to 2 significantfigures(3 marks)(c) (i) Some years ago‚ US$1.00 (one United States dollar) was equivalent to J$3.50(the dollars and fifty cents‚ Jamaican currency). Calculate
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Chapter 14 (Cost Planning) Problem 14.16 part A only (LO8) Cash budget – comprehensive. Following are the budgeted income statements for the second quarter of 2010 for Marine Tech‚ Inc.: | |April |May |June | |Sales……………………….. |$224‚000 |$272‚000 |$304‚000 | |Cost of goods sold*............... | 153‚600 | 182
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PVer FVN = 100‚000(e)0‚07=107 250‚82 b. Two years 4. Quarterly compounding FVN = PV(1+r/m)mN FVN = 100‚000(1+0‚07/4)4x2=114 888‚18 2012 Quantitative Business Methods 5. Monthly compounding FVN = PV(1+r/m)mN FVN = 100‚000(1+0‚07/12)12x2=114 980‚60 6. Contiuous compounding FVN = PVer FVN = 100‚000(e)0‚07x2=115 027‚38 Problem 3. A couple plans to set aside $20‚000 per year in a portfolio that earns 7% a year. If they make their first saving contribution one year from now‚ how
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The market forces of Supply and Demand. a.Plotting the Demand and supply Curve. The following Table Illustrates the values used in the plotted graphs. Price Per Unit ($)Quantity Demanded Quantity Supplied 81106284362441520.560 The resulting graph is illustrated below. Demand and Supply Curves for Comic Books 01234567890 1 2 3 4 5 6 7 8 9 10 Quantity of comic books P r i c e o f e a c h c o m i c b o o k DemandSupply b.Finding the Equilibrium point Plotted on the graph
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1. ht= -4.9t2+ 450‚ where t is the time elapsed in seconds and h is the height in metres. a) Table of Values t(s) | h(t) (m) | 0 | ht= -4.9(0)2+ 450= 450 | 1 | ht= -4.9(1)2+ 450= 445.1 | 2 | ht= -4.9(2)2+ 450= 430.4 | 3 | ht= -4.9(3)2+ 450= 405.9 | 4 | ht= -4.9(4)2+ 450=371.6 | 5 | ht= -4.9(5)2+ 450=327.5 | 6 | ht= -4.9(6)2+ 450= 273.6 | 7 | ht= -4.9(7)2+ 450= 209.9 | 8 | ht= -4.9(8)2+ 450= 136.4 | 9 | ht= -4.9(9)2+ 450=53.1 | 10 | ht= -4.9(10)2+ 450= -40 |
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