SOLUTIONS 1) Ralph Edmund loves steak and potatoes. Therefore‚ he has decided to go on a steady diet of only these two foods for all his meals. Ralph realizes that this is not the healthiest diet‚ so he wants to make sure that he eats the right quantities of the two foods to satisfy some key nutritional requirements. He has obtained the following nutritional and costs data: Grams of Ingredient Per Serving. Ingredient Steak Potato Daily Requirement (g) Carbs 5 15 >=50
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expenditures (in P100‚000/month) for radio x1 = peso expenditures (in P100‚000/month) for magazines x1 = peso expenditures (in P100‚000/month) for newspapers x1 = peso expenditures (in P100‚000/month) for outdoor advertising Obj. Max Z = 22x1 + 12x2 +15x3 +10x4 +5x5 Subject to: x1 +x2 +x3 +x4 +x5< 10 x1 + x2< 5 x1< 3 x2< 3 x3< 3 x4< 3 x5< 3 10x1 + 5x2 +x3 +x5> 25 10x1 + 5x2 +x3 +x5 <35 6x1 + 4x2 +7x3 +2x4 +2x5> 40 3x1 +2x2 +4x3 +5x4 +x5> 35 Z‚ xi>
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Question 1 a) What is meant by a load path? A load path is the transfer of loads and forces from the through the building to the bottom of the building‚ following the most direct structural path. b) Sketch an example of a load path from roof cladding to foundation for a brick veneer dwelling with trussed roof. Label clearly and indicate the load path with arrows. Diagram 1.b Page 3 Question 2 Outline the roles of the following people in the design of a building: Architect:
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Chandrasekharappa T.G.S et al. / International Journal on Computer Science and Engineering (IJCSE) S-boxes generated using Affine Transformation giving Maximum Avalanche Effect Chandrasekharappa T.G.S.‚ Prema K.V. and Kumara Shama Department of Electronics and Communication Engineering Manipal Institute of Technology Manipal - 576104 INDIA tgscmpl@gmail.com Abstract: The Advanced Encryption Standard (AES) was published by National Institute of Standards and Technology (NIST) in November
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JEPPE HIGH SCHOOL FOR BOYS GRADE 9 POLYNOMIAL MATHS LESSON PLAN DATE: Term 2 2012 TIME: 1 HOUR Objective of the lesson Revision of how to: • Use the four basic mathematical operators on various polynomials • Factorise a polynomial depending on its structure • Solve an equation by factorising a polynomial Basic operator use on polynomials Time required: 20 Minutes Method: • Show how each operator works on a polynomial • Show exceptions
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+ dy) = acx + (ad + bc)xy + bdy 2 2 The product of a binomial by another binomial is obtained as follows: • • • Examples: 1. (3x – 2y)(4x + 3y) 2. (m3 – 5) (m3 – 2) 3. (3a – 5x)(6b + 7y) = = = = = = 3(4)x2 + [(3)(3)+(-2)(4)]xy + (-2)(3)y2 12x2 + xy – 6y2 (m3m3) + (- 5 – 2)m3 + 10 m6 - 7m3 + 10 (3a)(6b) + (3a)(7y) + (-5x)(6b) + (-5x)(7y) 18ab + 21ay – 30bx – 35xy The first term of the product is the product of the first terms of the multiplicand and the multiplier; The second or the middle
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William Lloyd Garrison‚ Religious Patriot William Lloyd Garrison believed that slavery was the “greatest evil of all” (Hollitz 136)‚ and that “there could be no compromise with evil” (Hollitz 136). Garrison strived to “persuade the entire nation of the sinfulness of slavery” (Hollitz 137)‚ he became a supporter of the abolition movement‚ fought against slavery‚ and advocated for human rights; William Lloyd Garrison was a religious patriot. Garrison was raised by his mother after his alcoholic
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3. Algebra of Polynomials By now‚ you should be familiar with variables and exponents‚ and you may have dealt with expressions like 3x³ or 6x. Polynomials are sums of these "variables and exponents" expressions. Each piece of the polynomial‚ each part that is being added‚ is called a "term". Polynomial terms have variables which are raised to whole-number exponents (or else the terms are just plain numbers); there are no square roots of variables‚ no fractional powers‚ and no variables in the denominator
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Number Systems Base 2: The Binary Number System Base 8: The Octal Number System Base 16: The Hexadecimal Number System Learning Objectives • At the end of the lesson the student should be able to: – Identify the different number base system – Convert base ten numbers to base two‚ eight or sixteen – Convert base two‚ eight or sixteen numbers to base ten – Perform basic operations on various base numbers Number Base • What is a number base? A number base is a specific collection
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sec 4.76 GBytes 136 Mbits/sec [ 2] 0.0-300.0 sec 4.78 GBytes 137 Mbits/sec [ 3] 0.0-300.0 sec 4.77 GBytes 137 Mbits/sec [ 4] 0.0-300.0 sec 4.75 GBytes 136 Mbits/sec [ 5] 0.0-300.0 sec 4.75 GBytes 136 Mbits/sec [ 6] 0.0-300.0 sec 4.78 GBytes 137 Mbits/sec [ 7] 0.0-300.0 sec 4.76 GBytes 136 Mbits/sec [ 8] 0.0-300.0 sec 4.74 GBytes 136 Mbits/sec [ 9] 0.0-300.0 sec 4.79 GBytes 137 Mbits/sec [ 10] 0.0-300.0 sec 4.76 GBytes 136 Mbits/sec [ 11]
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