for conclude that the vinegar removes the shell but leaves the membrane or skin. The water stretches the membrane which is thick. This allows the egg to “bounce.” How does it work? Egg shell is made of calcium carbonate. Vinegar is an acid - acetic acid. When calcium carbonate is exposed to an acid it reacts. The calcium carbonate egg shell dissolves‚ but the membrane inside the shell‚ surrounding the egg‚ remains intact. This makes the egg feel rubbery. Not only does the vinegar dissolve the
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1. Disposing of Waste - Teachers should be aware of the appropriate method of disposal for any chemical used in the school laboratory. When in doubt‚ refer to the MSDS‚ a disposal manual‚ or the source of the chemical. a. Classification of Hazardous Waste The Environmental Protection Agency classifies wastes as: Ignitable: has a flash point below 140°C‚ is an oxidizer‚ or is an ignitable compressed gas. Corrosive: has a pH equal to or below 2.0 or a pH equal to or greater than 12.5. Reactive:
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Acetanilide Aim : To observe how an Aromatic electrophilic Substitution reaction takes place via the nitration of Acetanilide i.e. how hydrogen on a carbon chain is replaced with a nitro group. Reagents and Chemicals: • Acetanilide (5g) • Glacial acetic acid (5mL) • Concentrated sulphuric acid (10mL &1.5mL) • Concentrated Nitric acid (2.0mL) • Methanol (30-50mL) Modification to experimental procedure: The experimental procedure was conducted as per instructions from the chemistry 220 manual
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C C Br sp CBr4 sp3 4. (10 pts) Malonic acid‚ HO2CCH2CO2H‚ is a diprotic acid. The pKa for the loss of the first proton is 2.83; the pKa for the loss of the second proton is 5.69. (a) Explain why malonic acid is a stronger acid than acetic acid (pKa = 4.75). (b) Explain why the anion‚ -O2CCH2CO2H‚ is so much less acidic than malonic acid itself. (a) electron withdrawing –CO2H group stabilizes charge of conjugate anion (b) molecules doesn’t want to be dianion 5. (11 pts) Carey. All
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4.1 & 4.2: General properties of aqueous solutions and Precipitation Reactions: 1. (Brown 4.11) When asked what causes electrolyte solutions to conduct electricity‚ a student responds that it is due to the movement of electrons through the solution. Is the student correct? If not‚ what is the correct response? 2. (Brown 4.15) Specify what ions are present in solution upon dissolving each of the following in water: a. ZnCl2 c. (NH4)2SO4 b. HNO3 d. Ca(OH)2 3. (Brown 4.16 ) Specify
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Determination of : Titration of a Weak Acid Introduction: We will be using the LoggerPro and LabPro in order to help us determine our data. The purpose of this experiment is to follow the changes of pH during the titration of an acid and a base in order to determine the of the weak acid‚ . is a constant for a given acid at a given temperature. In this experiment we determined the Ka using two different methods: 1) the measurement of the pH of a solution containing a known concentration of a weak
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Sample Loading Buffer DNA ladder standard Electrophoresis chamber Power supply Gel casting tray and combs DNA stain Staining tray Gloves Pipette and tips Recipes: TAE Buffer 4.84 g Tris Base 1.14 ml Glacial Acetic Acid 2 ml 0.5M EDTA (pH 8.0) - bring
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Formic acid is the simplest carboxylic acid. Its chemical formula is HCOOH or HCO2H. It is an important intermediate in chemical synthesis and occurs naturally‚ most notably in ant venom. Wikipedia Formula: CH2O2 Boiling point: 213.4°F (100.8°C) Density: 1.22 g/cm³ IUPAC ID: Formic acid Molar mass: 46.02538 g/mol Melting point: 47.12°F (8.4°C) When methanol and carbon monoxide are combined in the presence of a strong base‚ the acid derivative methyl formate results‚ according to the chemical
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ICSE X | CHEMISTRY Board Paper – 2015 ICSE Board Class X Chemistry Board Paper – 2015 Time: 2 hrs Max. Marks: 80 Answers to this Paper must be written on the paper provided separately. You will not be allowed 10 write during the first 15 minutes. This time is to be spent in reading the Question Paper. The time given at the head of this paper is the time allowed for writing the answers. Section I is compulsory. Attempt any four questions from section II. The intended marks for questions or parts
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Procedure The procedure stated in Chem 2120 experiment 6 Williamson Ether Synthesis of Phenacetin laboratory manual was followed without any major changes. Data and results Compound Amount used MW (g/mol) Moles Stoichiometry/Comments acetaminophen 0.354 g 151.16 2.34 x 10-3 limiting reagent ethyl iodide 0.3mL 155.97 3.75 x 10-3 1.6 equiv ’s sodium ethoxide 2.6mL 68.05 3.3 x 10-2 catalyst‚ reaction solvent crude product obtained: phenacetin 0.32g
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