TITLE PAGE Laboratory Title: 2D Strain Rosette Analysis Contents Page 1 Title page Page 2 Contents Page 3 Nomenclature Page 4 Summary Page 4 Literature Search Page 5-6 Theory Page 7 Apparatus Page 8 Procedure Page 9 Tabulated Experimental Results Page 10-13 Sample Calculations Page 14 Tabulated Calculated Results Page 14 Error Analysis Page 14 Conclusions Page 15
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turesRule of Mixtures Composite stiffness can be predicted using a micro-mechanics approach termed the rule of mixtures. Assumptions 1. 2. 3. 4. 5. 6. Fibers are uniformly distributed throughout the matrix. Perfect bonding between fibers and matrix. Matrix is free of voids. Applied loads are either parallel or normal to the fiber direction. Lamina is initially in a stress-free state (no residual stresses). Fiber and matrix behave as linearly elastic materials. Longitudinal Modulus Equal strain
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hand dare seize the fire?” (Line 8) is a memorable quote in the poem “The Tyger”‚ by William Blake‚ that shows that the tiger’s aggressive nature must have been at mind when the author was describing the savage tiger. This poem showcases the tigers shear force and power as making it apparent that the tiger is a perfect weapon. It also shows that tigers are so fierce that they prey on the helpless‚ such as lambs. Deeper analysis of the poem reveals that the true meaning of “The Tyger” is just a microcosm
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Notes For the First Year Lecture Course: An Introduction to Fluid Mechanics School of Civil Engineering‚ University of Leeds. CIVE1400 FLUID MECHANICS Dr Andrew Sleigh May 2001 Table of Contents 0. 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 CONTENTS OF THE MODULE Objectives: Consists of: Specific Elements: Books: Other Teaching Resources. Civil Engineering Fluid Mechanics System of units The SI System of units Example: Units 3 3 3 4 4 5 6 7 7 9 1. 1.1 1.2 1.3 1.4 FLUIDS MECHANICS AND
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1 = ⎛ − νσ + σ − νσ ⎞ ⎜ x y z⎟ E⎝ ⎠ 1 = ⎛ − νσ − νσ − σ ⎞ ⎜ x y z⎟ E⎝ ⎠ ε = x ε ε y z τ xy ε = xy 2G τ ε = xz xz 2G ε yz = τ yz 2G Where E = Young’s modulus‚ ν = Poisson’s ratio‚ and G = shear modulus. A typical E for rock is between 10 and 60 GPa. A typical ν for rock is between 0.15 and 0.25. Note: isotropic means the properties do not depend on direction‚ and homogeneous means the properties are the same at every point in the material
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∴ = = 90 KN So‚ = 50 + 70 + 20 = + 90 = 50 KN Modifications for UDL: Taking moments around: [(12 x 10) x 5] = 8 x (additional ) ∴ Additional = 75 KN So‚ additional = 120 = + 75 = 45 KN So = 95 KN and = 165 KN 1.2 Draw the beam’s Shear Force diagram. 1.3 Determine the position of the maximum bending moment‚ measured from . Maximum bending moment is where the force diagram crosses 0‚ at 8m and between 2m and 6m. Bending Moment (BM) at 8m: (95 x 8) – (50 x 6) – (70 x 2) - [(12
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http://helpyoustudy.info Answers to Selectecj Problems Given here are the answers to problems for which there are unique solutions. Many of the problems for solution in this book are true design problems‚ and individual design decisions are required to arrive at the solutions. Others are ofthe review question form tor which the answers arc in the text ofthe associated chapter It should also be noted that some ofthe problems require the selection ot design factors and the use of data from charts
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1. Characteristic Loads-Characteristics‚ Importance‚ Applications Actions By E.C. An action (F) is a force (load) applied to the structure (direct action ) or an imposed deformation ( indirect action ) ex. Temperature effects. Actions are classified: a) by variation in time permanent actions G ( self-weight of structure). b) by their spatial variations: fixed actions ( self weight ) variable actions Q wind loads/snow. free actions which results in different actions accidental actions
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Hoop stress (cyl.) Longitudinal (sph.) P=Int. pressure‚ t=thickness σ1 = Prt σ2 = Pr2t σ1 = 2σ2 Shear Stress & Strain Pure shear Mod of rigidity τ = shear force vx-area A εx= εy= εz = 0 Strain in rads. γxy= τxyG G =E2(1+v) G = τγ γxy = τxyG γyz = τyzG γzx = zxG Torsion circular
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Materials * Helical spring * support * rods * weight hanger * slotted masses * vertical scale * stopwatch. Procedure Part I: Determination of k from Hooke’s Law 1. Suspend the spring from its support. 2. Hook the weight hanger from the bottom loop of the spring and determine the vertical scale reading of the bottom of the weight hanger. 3. Record this as the equilibrium position of the system. 4. Add 5 g to the weight hanger and again record the actual
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