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    Npv Calculation

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    this online NPV Calculation Tool http://finance.thinkanddone.com/online-n… we get the following NPV at 15% Net Cash Flows CF0 = -3000000 CF1 = 1100000 CF2 = 1450000 CF3 = 1300000 CF4 = 950000 Discounted Net Cash Flows DCF1 = 1100000/(1+0.15)^1 = 1100000/1.15 = 956521.74 DCF2 = 1450000/(1+0.15)^2 = 1450000/1.3225 = 1096408.32 DCF3 = 1300000/(1+0.15)^3 = 1300000/1.52087 = 854771.1 DCF4 = 950000/(1+0.15)^4 = 950000/1.74901 = 543165.58 NPV Calculation NPV = 956521.74 +

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    Acct 505 Course Project B

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    ACCT505 Part B Capital Budgeting problem Clark Paints‚ Inc. Data: Cost of new equipment $200‚000 Expected life of equipment in years 5 Disposal value in 5 years $40‚000 Life production - number of cans 5‚500‚000 Annual production or purchase needs 1‚100‚000 Initial training costs 0 Number of workers needed 3 Annual hours to be worked per employee 2‚000 Earnings per hour for employees

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    Student Unit Record System Within the Integrated Postsecondary Education Data System Research and Development Report March 2005 Alisa F. Cunningham Institute for Higher Education Policy John Milam HigherEd.org‚ Inc. Cathy Statham Project Officer National Center for Education Statistics U.S. DEPARTMENT OF EDUCATION Margaret Spellings Secretary INSTITUTE OF EDUCATION SCIENCES Grover J. Whitehurst Director NATIONAL CENTER FOR EDUCATION STATISTICS Grover J. Whitehurst Acting Commissioner

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    Part I A. Present Value with Discount rate of 7% = 15000/(1+7%) = 15000/1.07 = $14‚018.69 Present Value with Discount rate of 4% = 15000/(1+4%) = 15000/1.04 = $14‚423.08 B. Account A - Present Value with Discount rate of 6% = 6500/(1+6%) = 6500/1.06 = $6‚132.08 Account B - Present Value with Discount rate of 6% = 12600/(1+6%)^2 = 12600/1.1236 = $11‚213.96 C. Present Value of Gold Mine 7% = 4900000/1.07 + 61‚000‚000/(1.07)^2 + 85‚000‚000/(1.07)^3 = 45‚794‚392.52 + 61‚000‚000/1.1449 + 85

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    MATH533 Project B

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    Chanelle Henderson Math533 Applied Managerial Statistics Prof. Lisabeth Goble Week 6: Project B: Testing Hypothesis Testing and Confidence Intervals A. The average annual income was less than $50‚000 Null Hypothesis: The average annual income was greater than or equal to $50‚000H₀: µ ≥ 50‚000 Alternate Hypothesis: The average annual income was less than $50‚000. (Claim)Ha: µ <50‚000 Analysis Plan: Significance Level‚ α=0.05.Since the sample size‚ n > 30 I will use z-test for mean to test the

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    PROJECT PART B

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    PROJECT PART B: Hypothesis Testing and Confidence Intervals Math 533 Applied managerial Statistics. Instructor: Mr. Patrick Mayers. April 12‚ 2015 Guillermo H. Quintela. a. The average (mean) sales per week exceeds 41.5 per salesperson. The Null Hypothesis: The average (mean) sales per week is greater than or equal to 41.5 per salesperson. Ho:µ >= 41.5 The alternate Hypothesis: The average (mean) sales per week is less than or equal than 41.5 per salesperson. Ha:µ < 41.5 For a significance

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    Project: Retention Period

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    Litigation Hold Notice David Hamburg Jr. Final Project IS 3350 Introduction It is Premier College’s policy to maintain complete‚ accurate and high quality records. Records are to be retained for the period of their immediate use‚ unless longer retention is required for historical reference‚ contractual‚ legal or regulatory requirements or for other purposes as may be set forth below. Records that are no longer required‚ or have satisfied their required periods of retention‚ shall be destroyed. No officer

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    Npv of Ocean Carriers

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    comparison for 15 and 25 year term (NY) 9 Figure 2: Cash flow comparison for 15 and 25 year term (HK) 9 Figure 3: Revenue and Operating Expenses (HK) 10 List of Tables Table 1: List of Assumptions made for NPV analysis 4 Table 2: List of Limitations on NPV Analysis. 4 Table 3: Estimation of Resale value of Carrier @15th year 7 1. Introduction 1.1 Executive Summary Ocean Carriers Inc. (OCI) is an International provider of Marine transportation services mainly focussing on Dry Bulk commodities mainly

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    Log P Value Atenolool

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    Log P values: Log p value atenolol: 0.16 Log P value metoprolol: 1.8 Log P value of propranolol: 3.21 Reason: The distribution of a drug between water and octanol is one criterion to determine how lipophilic the compound is. The distribution coefficient (log P) gives an indication of how easily the drug is adsorbed‚ how strong the effect is‚ how long it remains in the body in an active form‚ and how it is metabolized and excreted. The partition coefficient is a ratio of concentrations of unionized

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    Experiments #7A & 7B 7A. Electrochemical Cells 7B. Formation of a Complex Ion Chem 102 Section 3095 Grace H. Kim Dec. 15‚ 2011 Abstract Two experiments were conducted to figure out the value of the formation constant of tetraamminecopper(II)‚ Kf‚ with different methods and which experimental method produces more accurate result. One was electrochemistry using a Daniel cell and the other one was spectrometry by estimating concentration of complex solution using a calibration

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